# What are the steps for using a compass and straightedge to construct a line through point P that is parallel to line m? A horizontal line m and a point P are drawn. The point P is above the horizontal line m. Drag the steps and drop them in order from start to finish.

Here, m is a line and we have to find the draw parallel line of line of m through a point P with the help of straightedge and compass,

The correct order of steps for constructing a line through point P that is parallel to line m are as follows,

Step 1 : Use the straightedge to draw a line n that passes through P and intersect line m, lebel the point of intersection as X,

Step 2 : Place the point of the compass on point X and draw an arc that intersect line m and n, label the intersection point A and B,

Step 3 : Without changing the width of the compass opening, place the point of compass on point P and draw an arc that intersect line n label the intersection point as C,

Step 4 : Place the point of compass on point A and open it to the width of AB,

Step 5 : With the compass opening set the width of AB, place the point of the compass On point C and draw an arc that intersects the arc that was drawn from point P lebel the intersection of arc as point Y,

Step 6 : Use the straightedge to draw PY

Here's the list of the following sequence in the right order for you (I took the test myself and got this whole sequence right)

1. Use the straightedge to draw a line n that passes through P and intersects line m. Label the point of intersection as point X.

2. Place the point of the compass on point X and draw an arc that intersects lines m and n. Label the intersections as points A and B.

3. Without changing the width of the compass opening, place the point of the compass on point P and draw an arc that intersects line n. Label the intersection as point C.

4. Place the point of the compass on point A and open it to width AB.

5. With the compass opening set to width AB, place the point of the compass on point C and draw an arc that intersects the arc that was drawn from point P. Label the intersection of the arcs as point Y.

6. Use the straightedge to draw line PY.

## Related Questions

In a relay race, Jill runs 250 meters in 1.5 minutes. She hands the baton to John, who walks for 3 minutes at a rate of 70 meters per minute. Finally, Suzy sprints the last 100 meters in 15 seconds. What distance is traveled in this relay

9514 1404 393

560 m

Step-by-step explanation:

Jill's distance is given as 250 m.

John's distance can be computed as ...

distance = speed × time = (70 m/min)(3 min) = 210 m

Suzy's distance is given as 100 m.

Then the total distance is ...

250 m + 210 m + 100 m = 560 m

The distance traveled is 560 m in this relay.

A goliath grouper at the local aquarium ate 112 fish over the course of 8 hours. At this rate how many fish can he eat in 3.5 hours

112 divided by 8 is 14
14 multiplied by 3.5 is 49

The discriminant help us to identify the nature of the roots.

If Disc > 0, the function has two distinct roots
If Disc = 0, the function has repeated roots
If Disc < 0, the function has complex roots

The turning away of the function indicates a repeated root at that point.
Thus, the given quadratic equation has a repeated root at x = 2. So the discriminant of the function is zero.

Therefore, the correct answer is option B

What is a3 if an=64(12)n−1

Step-by-step explanation:

Quadrilateral MBPV is similar to quadrilateral GKDF. BP = 78 mm, KD = 30 mm , and FD = 45 mm. What is VP? Enter your answer in the box □mm.

VP = 117 mm

Step-by-step explanation:

Corresponding sides of similar quadrilaterals are proportional.

VP/FD = BP/KD

VP = FD·BP/KD = (45 mm)·(78/30) . . . . multiply by FD; fill in the givens

VP = 117 mm

Product of 6 and 6r and the product of 8s and 4

The product of the numbers are 36r and 32s.

### What is product?

When we multiply two numbers the resultant is called their product.

Given that, what can be the products of 6 and 6r and 8s and 4

a) 6 and 6r =

We can write it as =

6 x 6 x r

now multiply the numeric parts,

36 x r

= 36r

Similarly,

b) 8s and 4 =

We can write it as,

8 x s x 4

= 8 x 4 x s

now multiply the numeric parts,

= 32 x s

= 32s

Hence, the products are 36r and 32s.

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Product tells us we’re going to multiply.

6 x 6r = 36r

8s x 4 = 32s

We don’t have a number value to substitute in for r or s, so we just leave those variables as they are.

LMK if you have questions