What is the medium through which the wave is moving?
What is the medium through which the wave is moving? - 1


Answer 1


STRING held by the man


Wave is defined as a disturbance that travels through a MEDIUM and transfer energy from one point to another without causing any permanent displacement of the medium itself.

The medium through which wave travels varies e.g water, string, air etc

According to the diagram, wave travels through the string held by the man. This string is referred to as the MEDIUM through which the wave moves. The wave generated produces both crest (D) and trough (C) when displaced from its initial position (A)

Answer 2

Rope or one could consider it to be C to B or A to D

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A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. What is the lowest frequency associated with this portion of the spectrum?



the lowest frequency is 7.5* 10^(14) Hz


In the question it is given that wavelength(L) in the range of 200μm to 400μm.

let ν be frequency of wave v velocity = 3\times 10^8

velocity v= Lν

therefore ν=(v)/(L)

frequency ν be lopwest when L will be heighest

ν(lowest)=(3* 10^8)/(400* 10^-9)

ν=7.5* 10^(14) Hz

Power P is the rate at which energy E is consumed per unit time. Ornithologists have found that the power consumed by a certain pigeon flying at velocity v m/s is described well by the function P(v)=16v−1+10−3v3 J/s. Assume that the pigeon can store 5×104 J of usable energy as body fat. Find the velocity vp min that minimizes power consumption. (Use decimal notation. Give your answer to two decimal places.)




P(v) = 16 / v + 10⁻³ v³

differentiating on both sides

dP / dt = - 16 / v² + 3 x 10⁻³ v²

For maxima and minima , the condition is

dP / dt = - 16 / v² + 3 x 10⁻³ v²  = 0

v² = 160 / 3 x 10²

v² = 73 m/s

v = 8.54 m /s

To know the condition of minima

again differentiating

d²P / dt² = - 16 x -2 / v² + 6 x 10⁻³ x v

= 32 / v³ + 6 x 10⁻³ x v

= + ve quantity

So at v_p =  8.54 m /s , power consumption will be minimum .

A lead ball is dropped into a lake from a diving board 5.0 m above the water. After entering the water, it sinks to the bottom with a constant velocity equal to the velocity with which it hit the water. The ball reaches the bottom 3.0 s after it is released. How deep is the lake



|D_(depth) |=19.697m


To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:


x_(f)-x_(i)=v_(i)t+(1/2)at^(2)\n  -5.0m=(o)t+(1/2)(-9.8m/s^(2) )t^(2)\n -4.9t^(2)=-5.0\n t^(2)=5/4.9\nt=√(1.02) \nt=1.01s

As we have find the time taken now we need to find the final velocity vf from below equation as

v_(f)=v_(i)+at\nv_(f)=0+(-9.8m/s^(2) )(1.01s) \nv_(f)=-9.898m/s

So the depth of lake is given by:

first we need to find total time as

t=3.0-1.01 =1.99 s

|D_(depth) |=|vt|\n|D_(depth) |=|(-9.898m/s)(1.99s)|\n|D_(depth) |=19.697m

If you rub a balloon on your hair, youcan hang the balloon on the wall.
Why does the balloon stick to the



The balloon is electrostatically charged


After rubbing it on the hair, the balloon is electrically charged, and as such, when approaching the wall it draws opposite charges from the wall creating locally on the wall's surface an accumulation of the charges opposite to the balloon . and repelling deeper into the wall those charges of the same sign.

Which two types of simple machines can be found in a bicycle?



The correct answer is A) lever and wheel and axle


I took the quiz

hope this helps :)

A force of 200N acts on a body that moves along a horizontal plane in the same direction of movement. The body moves 30m. What is the work done by that force?


Work = Force times Distance

Work = 200 x 30

Work = 6000

The work done by a force of 200N on a body that moved 30m is 6000J or 6000 Joules.