# If molarity = moles liter , then how many grams of NaCl are needed to make 1 liter of a 0.1 M solution? A) 0.0584 g NaCl B) 3.246 g NaCl C) 5.844 g NaCl D) 58.44 g NaCl

The grams  of NaCl   that needed  to make 1L  of a 0.1 M solution  is

calculation

Step 1: find the  moles of NaCl

moles  = molarity  x  volume  in liters

molarity = 0.1 M =0.1 mol/l

= 1 L x 0.1 Mol/L = 0.1 moles

Step 2: find  the   mass  NaCl

mass =  moles x  molar mass

From  periodic  table   the molar mass of NaCl  = 23 +35.45 =58.45 g/mol

mass= 0.1 moles  x 58.45 g/mol =5.845 g appropriate ( answer C)

## Answer : Option C) 5.844 g NaCl

### Explanation :

To calculate the number of grams of NaCl that would be needed to make 0.1 M of solution we have to calculate;

1. The molecular weight of sodium chloride (NaCl) which is 58.44 g, so one gram molecular weight will be= 1 mole which is 58.44 g.
2. By dissolving 58.44 g of NaCl upto the final volume of 1 litre, one can get 1 M NaCl solution.
3. So, to make 0.1 M NaCl solution we have to dilute the mass of salt to 1000 ml of solution as follows;
4. 0.1 M NaCl solution will require 0.1 x 58.44 g of NaCl = 5.844 g. of NaCl.

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Mass percentage, also known as weight percentage, is a way of expressing the concentration of a component in a mixture or a compound. It represents the mass of the component (usually expressed in grams) per 100 grams of the mixture or compound. Mass percentage is commonly used in chemistry and other scientific fields to quantify the amount of a particular substance relative to the total mass of the mixture.

Na = 22.99 g/mol

H = 1.00 g/mol

C = 12.01 g/mol

O = 15.99 g/mol

Molar Mass of solution = (22.99 g/mol) + (1.00 g/mol) + (12.01 g/mol) + (15.99 g/mol x 3)

= 83.97 g/mol

(47.97 g/mol) / (83.97 g/mol) x 100 = 57.13%

To know more about mass percent, here:

brainly.com/question/14990953

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Molar mass of NaHCO3 = 84.00661 g/mo

Explanation:

This compound is also known as Baking Soda or Sodium Bicarbonate.

Convert grams NaHCO3 to moles  or  moles NaHCO3 to grams

Molecular weight calculation:

22.98977 + 1.00794 + 12.0107 + 15.9994*3

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