Calculate the volume of 8.87×10-2 M calcium hydroxide required to neutralize 15.0 mL of a 0.389 M hydrobromic acid solution. mL

Answers

Answer 1
Answer:

Answer : The volume of calcium hydroxide is, 32.89 ml

Explanation :

Using neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 1

n_2 = acidity of a base = 2

M_1 = concentration of hydrobromic acid = 0.389 M

M_2 = concentration of calcium hydroxide = 0.0887 M

V_1 = volume of hydrobromic acid = 15 ml

V_2 = volume of calcium hydroxide = ?

Now put all the given values in the above law, we get the volume of calcium hydroxide.

1* 0.389M* 15ml=2* 0.0887M* V_2

V_2=32.89ml

Therefore, the volume of calcium hydroxide is, 32.89 ml


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Answers

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Please ignore my answers because they are wrong.

Answers

Answer:

The wavelength of the radio wave is 3.003 m.

The energy of the radio wave is 6.6194* 10^(-26) J.

Explanation:

Frequency of the radio waves, ν = 99.9 MHz = 99.9* 10^6 Hz

Wavelength and frequency are related to each other by realtion:

\lambda =(c)/(\nu )

\lambda = Wavelength of the wave

c = speed of the light

ν = Frequency of the wave

\lambda =(3* 10^8 m/s)/(99.9* 10^6 s^(-1))=3.003 m

The wavelength of the radio wave is 3.003 m.

The energy of the electromagnetic wave is given by Planck's equation:

E=h* \nu

h = Planck's constant = 6.626* 10^(-34) Js

The energy of the radio wave with 99.9 MHz frequency will be:

E=6.626* 10^(-34) Js* 99.9* 10^6 s^(-1)

E = 6.6194* 10^(-26) J

The energy of the radio wave is 6.6194* 10^(-26) J.

What is the correct formula for phosphorus pentachloride? (a) PCl5 (b) P5Cl (c) P(ClO)5 (d) PO4Cl (e) PCIO

Answers

Answer:

(a) PCl_5

Explanation:

Hello,

In this case, such nomenclature expresses the amount of both phosphorous and chlorine atoms via prefixes for the sub indexes of each atom into the molecule, thus, as phosphorous is prefixless one infers that there is just one phosphorous and five chlorides since the prefix for such atom is penta. Therefore, the correct formula is:

PCl_5

Hence, the answer is (a)

Best regards.

Answer:

The correct formula for phosphorus pentachloride is a) PCl5

How many moles of atoms are in 9.00 g of 13c? express your answer numerically in moles?

Answers

Number of moles is defined as the ratio of given mass in grams to the molar mass of compound.

Number of moles =(Given mass in g)/(Molar mass)

Now, put the value of given mass of ^(13)C in grams and molar mass of ^(13)C in g/mol i.e. 13 g/mol.

Thus,

number of moles =(9.00 g)/(13 g/mol)

= 0.692 mol

Hence, number of moles of ^(13)C = 0.692 mol

11.Calculate the molar mass of Fe2(SO3)3

Answers

The molar mass of Fe2(SO3)3 is 351.8796 moles.

What is molar mass?

Molar mass is defined as the mass equivalent of an element's or a chemical compound's Avogadro number of atoms or molecules, respectively. A mole is defined as the quantity of atoms, molecules, or ions that are present in a substance. It is additionally referred to as the volume of material that contains the same number of discrete units.

Molar mass of Fe2(SO3)3

= 2 × 55.845 + 3 × 32.065 + 9 × 15.9994

= 111.69 +  96.195 + 143.9946

= 351.8796 moles.

The substance iron(III) sulfite, sometimes known as ferrous sulfite, has the chemical formula Fe2(SO3)3. The family of inorganic compounds known as iron(III) Sulphate, sometimes known as ferric Sulphate, has the formula Fe2(SO4)3(H2O)n.

Thus, the molar mass of Fe2(SO3)3 is 351.8796 moles.

To learn more about molar mass, refer to the link below:

brainly.com/question/12127540

#SPJ2

Answer:

The molar mass and molecular weight of Fe2(SO3)3 is 351.8796.

What is the pOH of a 7.9 x 10 ^-4 M OH- solution?

pOH= ?

Answers

Answer: pOH of the given hydroxide ion concentration is 3.10

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration. It is represented by the equation:

pOH=-\log[OH^-]

We are given:

Hydroxide ion concentration, [OH^-]=7.9* 10^(-4)M

Putting values in above equation, we get:

pOH=-\log(7.9* 10^(-4))\n\npOH=3.10

Hence, pOH of the given hydroxide ion concentration is 3.10

pOH is defined as -log([OH-]).

pOH = -log([OH-]) = -log(7.9 * 10^-4) = 3.1

Hope this helps!