Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + H2O(l)

BaSO4(s) + 2 H2O(l) → Ba(OH)2 (aq) + H2SO4(aq)

Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + 2 H2O(l)

Answer:

**Answer:**

Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + 2 H2O(l)

That's the right one.

**Explanation:**

You should see that this equation is balanced, not as

Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + H2O(l)

(on reactive we have 4 H, on products, we have only 2)

Ba(OH)2 (aq) + H2SO4(aq) → H2Ba(s) + SO4(OH)2(l)

(this is impossible, it's a nonsense)

BaSO4(s) + 2 H2O(l) → Ba(OH)2 (aq) + H2SO4(aq)

(it is the same with the right one but is the other way around. The statement says, reaction of Ba(OH)2 with H2SO4, not BaSO4 with water. Also, it is not a chemical balance.

Cobalt chloride Select one: a. Forms a single hydrate which may be pink or blue b. Is colorless in the presence of water c. Does not exist as a hydrate d. Forms different hydrates which have different colors

A nitric acid solution flows at a constant rate of 5L/min into a large tank that initially held 200L of a 0.5% nitric acid solution. The solution inside the tank is kept well stirred and flows out of the tank at a rate of 10L/min. If the solution entering the tank is 10% nitric acid, determine the volume of nitric acid in the tank after t minutes.

This is how osmium appears in the periodic table.A purple box has O s at the center and 76 above. Below it says osmium and below that 190.23.Rounded to the nearest whole number, how many neutrons, on average, are in an atom of osmium?76114190266

Salt, sugar, and snow are examples of ____________________ solids.

How much heat is transferred when 7.19 grams of H2 reacts with excess nitrogen, according to the following equation: N2(g) + 3 H2 (g) --> 2 NH3 (g) \DeltaΔH = +46.2 kJ

A nitric acid solution flows at a constant rate of 5L/min into a large tank that initially held 200L of a 0.5% nitric acid solution. The solution inside the tank is kept well stirred and flows out of the tank at a rate of 10L/min. If the solution entering the tank is 10% nitric acid, determine the volume of nitric acid in the tank after t minutes.

This is how osmium appears in the periodic table.A purple box has O s at the center and 76 above. Below it says osmium and below that 190.23.Rounded to the nearest whole number, how many neutrons, on average, are in an atom of osmium?76114190266

Salt, sugar, and snow are examples of ____________________ solids.

How much heat is transferred when 7.19 grams of H2 reacts with excess nitrogen, according to the following equation: N2(g) + 3 H2 (g) --> 2 NH3 (g) \DeltaΔH = +46.2 kJ

(b)CHCL3

(c)C12H10O16

(d)CH3CH2CH2CH2CH3

The **mass **of **carbon **in is 12.007 amu, is 12.007, is 144.084 amu, and is 60.035 amu.

The **mass **has been given as the sum of the **atomic **mass unit in the **compound**. The **mass **of 1 atom of **carbon **is **12.007 amu.**

The **mass **of **carbon **in the following **compounds **is given as:

The **number **of **Carbon **units = 1

The **mass **of **carbon **in compound = 12.007 amu

The **number **of **Carbon **units = 1

The **mass **of **carbon **in the compound = 12.007 amu

The **number **of **carbon **units =12

The **mass **of **carbon **in the compound:

The **number **of **carbon **units = 5

The **mass **of **carbon **in the compound:

Learn more about the **mass **of an **atom**, here:

**Answer:**

The atomic mass of carbon (C) is 12.0107 amu, so if you want to calculate the total mass in each molecule, you just need to multiply the number of carbon atoms in the substance by 12.017. In (a) there is one atom of C, (b) have also one atom of C, (c) have 12 atoms of C, and (d) have five atoms of C. Thus, the total mass (amu) of carbon is:

(a) 12.017 amu

(b) 12.017 amu

(c) 144.204 amu

(d) 60.085 amu

**Answer:**

ksp = 0,176

**Explanation:**

The borax (Na₂borate) in water is in equilibrium, thus:

Na₂borate(s) ⇄ borate²⁻(aq) + 2Na⁺(aq)

*When you add just borax, the moles of Na²⁺ are twice the moles of borate²⁻, that means 2borate²⁻=Na⁺ **(1)*

The ksp is defined as:

*ksp = [borate²⁻] [Na⁺]²*

Then, borate²⁻(B₄O₇²⁻) reacts with HCl thus:

B₄O₇²⁻ + 2HCl + 5H₂O → 4H₃BO₃ + 2Cl⁻

The moles of HCl that reacts with B₄O₇²⁻ are:

0,500M×0,01200L = 6,00x10⁻³ mol of HCl

As two moles of HCl react with 1 mol of B₄O₇²⁻, the moles of B₄O₇²⁻ are:

6,00x10⁻³ mol of HCl× = *3,00x10⁻³ mol of B₄O₇²⁻*

For (1), moles of Na⁺ are *3,00x10⁻³ mol ×2 = 6,00x10⁻³ mol of Na⁺*

The [borate²⁻] is *3,00x10⁻³ mol of B₄O₇²⁻/0,00850L = **0,353M*

And [Na⁺] is *6,00x10⁻³ mol of Na⁺ / 0,00850L = ***0,706M**

Replacing in the expression of ksp:

ksp = [0,353] [0,706]²

**ksp = 0,176**

I hope it helps!

Jessim should not move except to slowly spin the globe

Jesim should slowly spin the globe and walk away from Nancy

Jessim should have Nancy walk around him while spinning the ball

Jessim should spin the globe quickly while walking in a circle around Nancy

the answer is D jessim should spin the glove quickly while walking in a circle around nancy.

**Answer: **

The answer is D jessim should spin the glove quickly while walking in a circle around nancy.

**Explanation:**

The element is magnesium, its atomic number is 12.

**Answer:**

**THE NEW FREEZING POINT IS -4.196 °C**

**Explanation:**

ΔTf = 1 Kf m

molarity of MgCl2:

Molar mass = (24 + 35.5 *2) g/mol

molar mass = 95 g/mol

7.15 g of MgCl2 in 100 g of water

7.15 g = 100 g

(7.15 * 100 / 1000) = 1000 g or 1 L or 1 dm3

= 0.715 g /dm3

Molarity in mol/dm3 = molarity in g/dm3 / molar mass

= 0.715 g /dm3 / 95 g/mol

m = 0.00752 mol/ dm3

So therefore:

ΔTf = i Kf m

1 = 3 (1 Mg and 2 Cl)

Kf = 1.86 °C/m

M = 0.752 moles

So we have:

ΔTf = 3 * 1.86 * 0.752

ΔTf = 4.196 °C

The new freezing point therefore will be 0 °C - 4.196 °C which is equals to - 4.196 °C

**Answer:**** The concentration of solution is 0.342 M**

**Explanation:**

**To calculate the molarity of solution, we use the equation:**

**We are given:**

Mass of solute (Sodium chloride) = 15 g

Molar mass of sodium chloride = 58.5 g/mol

Volume of solution = 750 mL

**Putting values in above equation, we get:**

**Hence, the concentration of solution is 0.342 M**