Topic 1 Homework Homework – Due in 13 hours T2HW Question 16 - Challenge Homework – Unanswered The distance from San Francisco to Los Angeles is approximately 385 miles. You and your friends decide to cycle from San Francisco to Los Angeles. If the distance between the cities is about 385 miles and your doctor tells you that you need to drink 1 L of water for every 1 km that you cycle, how many Lof water will each cyclist need to drink on the journey? Enter your answer as a number using 3 significant figures without units. Do not enter the word "liters" as part of your answer. 1609 m = 1.0 mi Numeric Answer Unanswered

Answers

Answer 1
Answer:

Answer:

Each cyclist will need to drink 619 l

Explanation:

Hi there!!

First, let´s convert the miles to kilometers:

If 1.0 mi = 1609 m, then 385 mi will be:

385 mi · (1609 m/ 1.0 mi) ·  (1 km/ 1000 m) = 619 km

Now, if each cyclist need to drink one liter water per kilometer ( I think that´s a lot of water!), for the entire journey each cyclist will need to drink:

619 km · 1 l/km = 619 l

Then, each cyclist will need to drink 619 l.


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Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together. Which statement is correct? a.Both NaCl and CuS will precipitate from solution b.No precipitate will form c.Only CuS will precipitate from solution d.Only NaCl will precipitate from solution

Answers

C.Only CuS will precipitate from solution

Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together.

  • According to question theEquation :

Na₂S(aq) + CuCl₂(aq) → Products

  • The complete balanced reaction is:

Na₂S(aq) + CuCl₂(aq) →  CuS(s) ↓ +  2NaCl(aq)

When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)

 

Thus,the correct answer is C.

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Answer:

The correct state for the answer is c.

Only CuS will precipitate from solution

Explanation:

We analyse the compounds for the reaction and we write the equation:

Na₂S(aq) + CuCl₂(aq) → Products

For this case, the products are NaCl and CuS. The complete balanced reaction is:

Na₂S(aq) + CuCl₂(aq) →  CuS(s) ↓ +  2NaCl(aq)

When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)

Salts from chlorides are soluble except for the Ag⁺, Pb⁺ or Cu⁺

Salts from S⁻² which are soluble, are found in the group 2 of the Periodic Table (Ca²⁺, Ba²⁺, Mg²⁺)

The correct state for the answer is c.

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Answers

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A mixture contains N a H C O 3 together with unreactive components. A 1.68 g sample of the mixture reacts with H A to produce 0.561 g of C O 2 . What is the percent by mass of N a H C O 3 in the original mixture

Answers

There is 65% of NaHCO3 in the sample.

The equation of the reaction is;

HA + NaHCO3 -----> NaA + CO2 + H2O

Amount of CO2 formed = mass/molar mass

mass of CO2 = 0.561 g/44 g/mol = 0.013 moles

From the balanced reaction equation;

1 mole of NaHCO3 yields 1 mole of CO2

0.013 moles of Na2CO3 yields 0.013 moles of CO2

Hence, mass of NaHCO3 in the sample = 0.013 moles × 84 g/mol = 1.092 g of NaHCO3

Percentage by mass of NaHCO3 = 1.092 g/1.68 g ×100/1

= 65%

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Answer:

63.75%.

Explanation:

The first step here is to write out the reaction showing the chemical reaction between the two chemical species. Thus, we have;

HA(aq) + NaHCO3 --------------> CO2(g) + H20(l) + NaA(aq).

Therefore, the mole ratio is 1 : 1 : 1 : 1 that is go say one mole of HA reacted with one mole of NaHCO3 to give one mole of CO2 and one .ole of NaA.

Hence, the number of moles of CO2 = mass/molar mass = 0.561/44 = 0.01275 moles.

Thus, the number of moles of NaHCO3 = number of moles of CO2 = 0.01275 moles.

Therefore, we have ( 0.01275 moles × 84 g/mol) grams = 1.071 g NaHCO3 in the mixture.

Therefore, the percent by mass of N a H C O 3 in the original mixture = 1.071/1.68 × 100 = 63.75%.

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Answers

It depends, for example, it is quite important to know the Kelvin scale (i.e 0 degrees Celsius is 273 K and -273 degrees Celsius is 0 K ) when dealing gases. But I don't know other situations where you would need to know other temperature scales.

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Answers

Explanation:

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