Answer:
1 ton=2000lb

total weight=2000

we want total weight=weight of cans

weight of cans=weight of 1 can times number of cans

W of cans=1/25c

total weight=weight of cans

2000=1/25c

times 25/1 both sides

50000=c

50,000 cans

total weight=2000

we want total weight=weight of cans

weight of cans=weight of 1 can times number of cans

W of cans=1/25c

total weight=weight of cans

2000=1/25c

times 25/1 both sides

50000=c

50,000 cans

Answer:
50,000 cans

because if 1 can = 1/25 lb

the 25 cans = 1lb

and 1 ton =2,000lbs

so 25x2,000=50,000

because if 1 can = 1/25 lb

the 25 cans = 1lb

and 1 ton =2,000lbs

so 25x2,000=50,000

A rational number between 1.7 and 1.8

A line passing through the point (12,-5) has a slope of 1/3

What is -2m^2-2mn+8-10m+10n+mn+4n^2-5n simplify to

Solve the following equality. 7t+15>3t-13

What is the complement of 86.4 degrees ?

A line passing through the point (12,-5) has a slope of 1/3

What is -2m^2-2mn+8-10m+10n+mn+4n^2-5n simplify to

Solve the following equality. 7t+15>3t-13

What is the complement of 86.4 degrees ?

The metric unit of measuring length that is equal to 10 meters is called a decametre or a dekameter (depending on where you're from). It is a highly rarely used unit, but still exists.

I want to know if I did this correct

2y/(y²-8y+5) - 1/(y-5)=

2y/(y-5)(y-3) - 1/(y-5)=

Least common multiple=(y-5)(y-3)

2y-1(y-3) / (y-5)(y-3)=

2y-y+3 / (y-5)(y-3)=

y+3 / (y-5)/y-3)

Answer : (y+3) / (y-5)(y-3).

you did right, congratulations!!.

2y/(y-5)(y-3) - 1/(y-5)=

Least common multiple=(y-5)(y-3)

2y-1(y-3) / (y-5)(y-3)=

2y-y+3 / (y-5)(y-3)=

y+3 / (y-5)/y-3)

Answer : (y+3) / (y-5)(y-3).

you did right, congratulations!!.

B.f(–3) = 6

C.f(–3) = 9

D.f(–3) = 12

**Answer:**

**Step-by-step explanation:**

hello :

If f(x) = 3x² - 2x + 5,

f(-2)=3(-2)² - 2(-2) + 5=12+4+5=21

Hopefully this helps, the app I used is called Photomath

minus 12 over 16 and 12 over 16

B.

minus 12 over 18 and 12 over 18

C.

minus 9 over 16 and 9 over 16

D.

minus 72 over 128 and 72 over 128

You can get the solution by just testing.

Let's start with A:

12*12=144

16*16=256

Now you know that A is the correct answer.

Let's start with A:

12*12=144

16*16=256

Now you know that A is the correct answer.

First sort the number form least to greatest

24,26,27,28,30,30,33,36

To find the mean, we divide to sum of all numbers in the data set by the number of numbers given,'8'.

(24+26+27+28+30+30+33+36)/8=234/8=29.25

Mean=29.25

To find the inter quartile range, we must solve for the lower and upper quartile mean.

Lower Quartile=(24+26+27+28)/4=26.25

Upper Quartile=(30+30+33+36)/4=32.25

32.25=26.25=6

Interquartile range=6

The median is the middle number in the data set, or the sum of the two middle numbers if there isn't a sole middle number

24,26,27,28,30,30,33,36

Median=(28+30)/2=29

Median=29

1st quartile we already solved for...

Lower/1st Quartile=(24+26+27+28)/4=26.25

3rd quartile we already solved for....

Upper/3rd Quartile=(30+30+33+36)/4=32.25

The mean would be most effected by an outlier of 52, the median would only go from 29 to 30.

24,26,27,28,30,30,33,36

To find the mean, we divide to sum of all numbers in the data set by the number of numbers given,'8'.

(24+26+27+28+30+30+33+36)/8=234/8=29.25

Mean=29.25

To find the inter quartile range, we must solve for the lower and upper quartile mean.

Lower Quartile=(24+26+27+28)/4=26.25

Upper Quartile=(30+30+33+36)/4=32.25

32.25=26.25=6

Interquartile range=6

The median is the middle number in the data set, or the sum of the two middle numbers if there isn't a sole middle number

24,26,27,28,30,30,33,36

Median=(28+30)/2=29

Median=29

1st quartile we already solved for...

Lower/1st Quartile=(24+26+27+28)/4=26.25

3rd quartile we already solved for....

Upper/3rd Quartile=(30+30+33+36)/4=32.25

The mean would be most effected by an outlier of 52, the median would only go from 29 to 30.