An 800-kHz sinusoidal radio signal is detected at a point 6.6 km from the transmitter tower. The electric field amplitude of the signal at that point is 0.780 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the amplitude of the magnetic field of the signal at that point

Answers

Answer 1
Answer:

Answer:

0.0000000026 T

Explanation:

E_0 = Maximum electric field strength = 0.78 V/m

B_0 = Maximum magnetic field strength

c = Speed of light = 3* 10^8\ m/s

Relation between amplitudes of electric and magnetic fields is given by

E_0=B_0c\n\Rightarrow B_0=(E_0)/(c)\n\Rightarrow B_0=(0.78)/(3* 10^8)\n\Rightarrow B_0=0.0000000026\ T

The amplitude of the magnetic field is 0.0000000026 T


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An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 9.40 m/s in 3.50 s. (a) What is the magnitude and direction of the bird’s acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.20 s has elapsed?
Hotel rooms in Smalltown go for $100, and 1,000 rooms are rented on atypical day.a. To raise revenue, the mayor decides to charge hotels a tax of $10 perrented room. After the tax is imposed, the going rate for hotel roomsrises to $108, and the number of rooms rented falls to 900. Calculate theamount of revenue this tax raises for Smalltown and the deadweightloss of the tax. (Hint: The area of a triangle is l/2Xbase X height.)h. The mayor now doubles the tax to $20. The price rises to $116, andthe number of rooms rented falls to 800. Calculate tax revenue anddeadweight loss with this larger tax. Are they double, more thandouble, or less than double? Explain.

Dogs can hear higher-pitched whistles that humans do. How do you
think the sound frequencies that dogs can
hear compare to the frequencies that humans
can hear?

Answers

Dogs can hear sounds at higher frequencies than humans. The range of sound frequencies that dogs can hear is approximately 40 Hz to 60,000 Hz, while the range for humans is 20 Hz to 20,000 Hz. This means that dogs can hear ultrasonic sounds that are beyond the range of human hearing.

What is sound about?

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave.

Sound is the reception of these waves and the brain's perception of them in terms of human physiology and psychology. Dogs have the ability to hear ultrasonic sounds that are audible only to them.

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HELP ASAP PLEASE!!!In which direction(s) does the ground shake during an earthquake?
A. sideways
B. up and down
C. back and forth
D. all of the above

Answers

Answer: D i am pretty sure

Explanation:

Answer:

all

Explanation:

A golf pro swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00340 s. After the collision, the ball leaves the club at a speed of 46.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?

Answers

To solve this problem it is necessary to apply the concepts related to Newton's second law and the equations of motion description for acceleration.

From the perspective of acceleration we have to describe it as

a = (\Delta v)/(\Delta t)

Where,

\Delta v = Velocity

\Delta t= time

At the same time by the Newton's second law we have that

F = ma

Where,

m = mass

a = Acceleration

Replacing the value of acceleration we have

F = m ((\Delta v)/(\Delta t))

Our values are given as,

m = 55*10^(-3)Kg

v = 46m/s

t = 0.00340s

Replacing we have,

F = m ((\Delta v)/(\Delta t))

F = (55*10^(-3))((46)/(0.00340))

F = 744.11N

Therefore the magnitude of the average force exerted on the ball by the club is 744.11N

An internal explosion breaks an object, initially at rest,intotwo pieces, one of which has 1.5 times the mass of the other.If
7500 J were released in the explosion, how much kinetic energydid
each piece acquire?

Answers

Answer:

4500 J and 3000 J

Explanation:

According to conservation of momentum

      0 = m_1 V_1 + m_2 V_2

Given that m_2 = 1.5 m_1 , so

    V_1 = -1.5 V_2

  the kinetic energy of each piece is

    K_2= (1)/(2) m_2v_2^2

    K_1= (1)/(2) m_1v_1^2

substituting the value of V1 in the above equation

    K_1 = (1/2)( m_2 / 1.5 )( -1.5 V_2)^2 = 1.5 (1/2)m_2 V_2^2 = 1.5 K_2

  Given that

         K_1 + k_2 = 7500 J

       1.5 K_2 + K_2 = 7500

         K_2 = 7500 / 2.5

               = 3000 J

this is the KE of heavier mass

      K_1 = 7500 - 3000 = 4500 J

this is the KE of lighter mass

Final answer:

The question is about finding the kinetic energy acquired by each of two pieces of an object following an internal explosion, using principles of conservation of energy and momentum in physics.

Explanation:

The student has asked about an internal explosion that breaks an object into two pieces with different masses, releasing a certain amount of kinetic energy in the process. This question involves applying the principle of conservation of energy and momentum to find the kinetic energy acquired by each piece post-explosion.

Assuming piece 1 has a mass of m and piece 2 has a mass of 1.5m, the total mass of the system is 2.5m. Since 7500 J of energy was released in the explosion, to find the kinetic energy of each piece, we can use the fact that the total kinetic energy is equal to the energy released during the explosion. Let the kinetic energy of the smaller piece be K1 and of the larger piece be K2. Because the object was initially at rest and momentum must be conserved, the momenta of the two pieces must be equal and opposite. This relationship allows us to derive the ratio of the kinetic energies. We can solve for K1 and K2 proportionally. Finally, because the kinetic energy is a scalar quantity, adding the kinetic energies of the two pieces will equal the total energy released.

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Define reflection.what are the two types of reflection

Answers

Answer:

The reflection of light can be roughly categorized into two types of reflection: specular reflection is defined as light reflected from a smooth surface at a definite angle, and diffuse reflection, which is produced by rough surfaces that tend to reflect light in all directions

mark as brainliest plz

Explanation:

Final answer:

Reflection is the process of light bouncing off a surface and changing its direction. There are two types of reflection: specular reflection and diffuse reflection.

Explanation:

Reflection is the process of light bouncing off a surface and changing its direction. There are two types of reflection: specular reflection and diffuse reflection.

Specular reflection occurs when light reflects off a smooth surface, such as a mirror, at a specific angle.

Diffuse reflection occurs when light reflects off a rough surface, such as paper or clothing, and scatters in many different directions.

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A 2-C charge experiences a force of 40 N when put at a certain location inspace. The electric field at that location is a. 2 N/C.b. 20 N/C. c. 30 N/C. d.
40 N/C. e. 60 N/C.

Answers

Answer:

E = 20 N/C

Explanation:

Given that,

Charge, q = 2 C

Force experience, F = 40 N

We need to find the electric field at that location.

The electric field in terms of electric force is given by :

F = qE

Where

E is the electric field

E=(F)/(q)\n\nE=(40\ N)/(2\ C)\nE=20\ N/C

So, the electric field at that location is 20 N/C.