An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of 55 degrees C is mixed with the water in the insulated container. When thermal equilibrium is reached, the temperature of the mixture is 25 degrees C. Assume that heat flows only between the alloy and the water. What is the specific heat of the alloy?

Answers

Answer 1
Answer:

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

Step 1: Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C


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In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g) + 24,000 calories A yield of ammonia, NH3, of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. How many grams of N2 must react to form 1.7 grams of ammonia?

Answers

Answer:

Mass of N2 required = 1.429 g

Explanation:

The given reaction is:

N2(g) + 3H2(g) → 2NH3(g)

Mass of NH3 formed = 1.7 g

Molar mass of NH3 = 17 g/mol

Moles(NH3) = (Mass)/(Molar mass) = (1.7)/(17) = 0. 1

Based on the reaction stoichiometry:

1 mole of N2 forms 2 moles of NH3

Therefore, moles of N2 required to produce 0.1 moles of NH3 is:

= (1 mole(N2)*0.1moles(NH3))/(2 moles(NH3)) =0.05 moles(N2)

Molar mass of N2 = 28 g/mol

Mass of N2 required = moles*molar mass = 0.05*28 = 1.4 g

This is the theoretical mass corresponding to a 100% yield. Since the yield of NH3 is 98%, the corresponding mass of N2 required would be:

=(1.4)/(0.98) =1.429 g

28g N2/(17 x 2 x 0.98) g NH3


1.7 g NH3 x 28g N2/(17 x 2 x 0.98) g NH3 =

47.6 / 33.32 = 1.43 g N2

Polychlorinated biphenyls (PCBs) are major environmental pollutants. Which of the following detectors would be most sensitive for GC analysis of PCBs? (24-8) Group of answer choices flame photometric (FPD) electron capture (ECD) flame ionization (FID) thermal conductivity (TCD) nitrogen-phosphorus (NPD)

Answers

Answer:

electron capture detectors (ECD)

Explanation:

Electron capture detectors (ECD) would be most sensitive for GC analysis of PCBs.

Answer: The detectors that would be most sensitive for GC analysis of PCBs are

- Electron Capture Detectors (ECD)

Explanation:

Polychlorinated biphenyls(PCBs) are oily chemicals that are manufactured(man-made) and used as lubricants in electrical equipments such as transformers. They are grouped as major environmental pollutants because they are characterised as being very stable, as they are resistant to extreme temperature and pressure. Therefore with time the build up in the environment and can cause harmful health effects.

In the environment, it can be found distributed virtually everywhere incl, air water or soil. The PCBs can be analysed in the environment through the use of gas chromatography( GC) with electron capture detector (ECD) as the most sensitive detector. The method was found to be more sensitive as the number of chlorine atoms attached to the biphenyl increases.

g What is the typical carbon concentration range for medium-carbon steels? 0.50 wt% - 0.75 wt% C 0.05 wt% - 1.00 wt% C 0.10 wt% - 0.50 wt% C 0.25 wt% - 0.60 wt% C 0.25 wt% - 1.00 wt% C

Answers

Answer:

C 0.25 wt% - 0.60 wt%

Explanation:

How could you use these solutions to determine the identities of each metal powder?Fill in the blanks with options in below:
1. The nitric acid solution will oxidize and thus dissolve _________. This will allow to identify ________.
2. To distinguish between ________, we can use the nickel nitrate
3. The nickel nitrate solution will oxidize and thus dissolve ________ and will not oxidize or dissolve ________.
Options:
a. Zn and Pt
b. Zn, Pb and Pt
c. Pb and Pt
d. Pb
e. Zn
f. Pt
g. Zn and Pb

Answers

Answer:

1.) The nitric acid solution will oxidize and thus dissolve _*(Zn and Pb)*_. This will allow to identify _**Pt**_.

2) To distinguish between _*(Zn and Pb)*_, we can use the nickel nitrate.

3) The nickel nitrate solution will oxidize and thus dissolve _**Zn**_ and will not oxidize or dissolve _**Pb**_.

Explanation:

1) Unlike Zinc and Lead, Platinum does not react with Nitric acid. So, it will be the only metal from step 1 that doesn't react. Pt is identified in this manner.

2) Nickel is higher than Lead in the activity series, but Zinc is higher than both of them in the activity series. This selectivity can be used to distinguish between Zinc and Lead metal powders.

3) Because Zinc is higher than Nickel in the activity series, it means that Zinc metal can and will displace Nickel from Nickel Nitrate solution. Therefore the Nickel Nitrate solution will oxidize and dissolve the Zinc metal.

But, there will be no reaction with the Lead metal powders sample as Pb is lower than Ni in the activity series, so, Nickel Nitrate solution will not oxidize or dissolve the Lead metal powders.

A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number of significant figures, and show required steps used to reach your answer.

Answers

Answer : The distance covered by slow snail in 24 hours is 3.2* 10^(13)pm

Explanation :

As we are given that the a slow snail can travel 2.2 cm in 1 minute. Now we have to calculate the distance covered by slow snail in 24 hours.

First we have to convert 24 hours in minutes.

Conversion used : (1 hour = 60 minutes)

As, 1 hour = 60 minutes

So, 24 hour = 24 × 60 minutes

                    = 1440 minutes

Now we have to calculate the distance covered by slow snail in 24 hours.

In 1 minute, the distance covered by slow snail = 2.2 cm

In 1440 minute, the distance covered by slow snail = 1440 × 2.2 cm

                                                                                     = 3168 cm

                                                                                     = 3.2* 10^3cm

Now we have to convert 'cm' into 'pm'.

Conversion used : 1cm=10^(10)pm

As, 1cm=10^(10)pm

So,  3.2* 10^3cm=(3.2* 10^3cm)/(1cm)* 10^(10)pm=3.2* 10^(13)pm

Therefore, the distance covered by slow snail in 24 hours is 3.2* 10^(13)pm

What is the change in electrons for nitrogen in the following reaction?S + NO3 - -> SO2 + NO


A. Gain 2 electrons
B. Gain 3 electrons
C. Lose 2 electrons
D. Lose 3 electrons

Answers

Nitrogen changes from +5 in NO_3- to +2 in NO. This means nitrogen has gained 3 electrons. Option B

To determine the change in electrons for nitrogen in the given reaction, we need to compare the oxidation state of nitrogen in the reactant (NO_3-) and the product (NO).

In the reactant, -, nitrogen is in the +5 oxidation state. This is because oxygen has an oxidation state of -2, and there are three oxygen atoms in NO_3-. Therefore, nitrogen must have an oxidation state of +5 to balance the overall charge of NO_3-.

In the product, NO, nitrogen is in the +2 oxidation state. This is because oxygen has an oxidation state of -2, and there is only one oxygen atom in NO. Therefore, nitrogen must have an oxidation state of +2 to balance the overall charge of NO.

By comparing the oxidation states of nitrogen in the reactant and the product, we can determine the change in electrons. The change in oxidation state corresponds to the change in the number of electrons gained or lost by the nitrogen atom.

In this case, nitrogen changes from +5 in NO_3- to +2 in NO. This means nitrogen has gained 3 electrons.

Therefore, the correct answer is B) Gain 3 electrons.

The nitrogen atom undergoes a reduction because it gains electrons, reducing its oxidation state from +5 to +2 in the reaction.

Option B

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