Define a function that takes two arguments: a string called strText and a number called intNumber. This function will use a repetition structure (a While or For loop) to print strText intNumber of times. Call this function.

Answers

Answer 1
Answer:

Answer:

public class Main

{

   public static void printString(String strText, int intNumber) {

       for(int i=0; i<intNumber; i++){

           System.out.println(strText);

       }

   }

   

public static void main(String[] args) {

       

       printString("Brainly", 3);

}

}

Explanation:

- Define a function called printString that takes two parameters - a String and an int. Since the function will print out the given String, it's type will be void.

- Use for loop to iterate according to the given number and print the given string

- In the main, call the printString function with some parameters.

Answer 2
Answer:

Answer:

// Class declaration

public class Printer {  

   // Define the function and call it printMany

   // The return type is void since it doesn't necessarily return any value.

   // It just prints to the console.

   // It takes two arguments strText of type String and

   // intNumber of type int.

  public static void printMany(String strText, int intNumber){          

       // Initialize the loop counter i to 1;

       int i = 1;

      //Create a while loop that goes

      // from i = 1 to  i = intNumber.

      // Where intNumber is the number of times the string strText

      // will be printed.

      while(i <= intNumber) {

           

           // At each of the cycle of the loop;

           // print out the string strText

           // and increment the value of the loop counter by 1

           System.out.println(strText);

           i++;

       }                 // End of while loop

   }               // End of method, printMany, declaration

// Write the main method to call the printMany function

public static void main(String[] args) {

       // Call the printMany function by supplying sample arguments;

       // In this case, strText has been given a value of "Omobowale"

       // And intNumber has been given a value of 4

       // Therefore, "Omobowale" will be printed 4 times.

       printMany("Omobowale", 4);

   }            //  End of main method

}          // End of class declaration

Sample Output:

When the program above is run, the following will be the output;

----------------------------------------------------

Omobowale

Omobowale

Omobowale

Omobowale

-------------------------------------------------------

Explanation:

Comments:

* The above code has been written in Java

* The code contains comments explaining every part of the code. Kindly go through the comments.

The whole code without comments is re-written as follows;

public class Printer {      

   public static void printMany(String strText, int intNumber){    

       int i = 1;

       while(i <= intNumber){

           System.out.println(strText);

           i++;

       }

   }      

   public static void main(String[] args) {

       printMany("Omobowale", 4);

   }

}


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Consider the following functions: (4) int hidden(int num1, int num2) { if (num1 > 20) num1 = num2 / 10; else if (num2 > 20) num2 = num1 / 20; else return num1 - num2; return num1 * num2; } int compute(int one, int two) { int secret = one; for (int i = one + 1; i <= two % 2; i++) secret = secret + i * i; return secret; } What is the output of each of the following program segments? a. cout << hidden(15, 10) << endl; b. cout << compute(3, 9) << endl; c. cout << hidden(30, 20) << " " << compute(10, hidden(30, 20)) << endl; d. x = 2; y = 8; cout << compute(y, x) << endl;

Answers

Answer:

a.  cout<<hidden(15,10)<<endl;

output = 5

b. cout << compute(3, 9) << endl;

output=3

c. cout << hidden(30, 20) << " " << compute(10, hidden(30, 20)) << endl;

output = 10

d. x = 2; y = 8; cout << compute(y, x) << endl;

output= 8

Explanation:

solution a:

num1= 15;

num2= 10;

according to condition 1, num1 is not greater than 20. In condition 2, num2 is also not greater than 20.

so,

the solution is

return num1 - num2 = 15 - 10 = 5

So the output for the above function is 5.

solution b:

as in function there are two  integer type variables named as one and two. values of variables in given part are:

one = 3

two = 9

secret = one = 3

for (int i= one + 1 = 3+1 = 4; i<=9%2=1; i++ )

9%2 mean find the remainder for 9 dividing by 2 that is 1.

//  there 4 is not less than equal to  1 so loop condition will be false and loop will terminate. statement in loop will not be executed.

So the answer will be return from function compute is

return secret ;

secret = 3;

so answer return from the function is 3.

solution c:

As variables in first function are num1 and num2. the values given in part c are:

num1 = 30;

num2= 20;

According to first condition num1=30>20, So,

num1= num2/10

so the solution is

num1 = 20/10 = 2

now

num1=2

now the value return from function Hidden is,

return num1*num2 = 2* 20 = 40

Now use the value return from function hidden in function compute as

compute(10, hidden(30, 20))

as the value return from hidden(30, 20) = 40

so, compute function becomes

compute(10, 40)

Now variable in compute function are named as one and two, so the values are

one= 10;

two = 40;

as

secret = one

so

secret = 10;

for (int i= one + 1 = 10+1 = 11; i<=40%2=0; i++ )

40%2 mean find the remainder for 40 dividing by 2 that is 0.

//  there 11 is not less than equal to  0 so loop condition will be false and loop will terminate. statement in loop will not be executed.

So the answer will be return from function compute is

return secret ;

secret = 10;

so answer return from the function is 10.

solution d:

Now variable in compute function are named as one and two, so the values are

one = y = 8

two = x = 2

There

Secret = one = 8;

So

for (int i= one + 1 = 8+1 = 9; i<=2%2=0; i++ )

2%2 mean find the remainder for 2 dividing by 2 that is 0.

//  there 9 is not less than equal to  0 so loop condition will be false and loop will terminate. statement in loop will not be executed.

So the answer will be return from function compute is

return secret ;

secret = 8;

so answer return from the function is 8.

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Answers

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b.
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c.
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d.
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Answers

Answer: B) Web robot

Explanation:

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Write a python program that asks the user to enter a student's name and 8 numeric tests scores (out of 100 for each test). The name will be a local variable. The program should display a letter grade for each score, and the average test score, along with the student's name. There are 12 students in the class. Write the following functions in the program:
calc_average - this function should accept 8 test scores as arguments and return the average of the scores per student
determine_grade - this function should accept a test score average as an argument and return a letter grade for the score based on the following grading scale:
90-100 A
80-89 B
70-79 C
60-69 D
Below 60 F

Answers

In this exercise we have to use the computer language knowledge in python to write the code as:

the code is in the attached image.

In a more easy way we have that the code will be:

def calc_average(name):

  score = []

  sum = 0

  for j in range(8):

      inp = int(input("Test Score"+str(j+1)+": "))

      score.append(inp)

      sum = sum + inp

      if inp>=90 and inp<=100:

          print("A")

      elif inp>=80 and inp<90:

          print("B")

      elif inp>=70 and inp<80:

          print("C")

      elif inp>=60 and inp<70:

          print("D")

      else:

          print("F")

  avg = sum/8

  print("Result Details of "+name)

  print("Average Score: "+str(avg))

  return avg

def determine_grade(result):

  if float(result) >= 90.0 and float(result) <= 100.0:

      print("Letter Grade: A")

  elif float(result) >= 80.0 and float(result) <90.0:

      print("Letter Grade: B")

  elif float(result) >= 70.0 and float(result) < 80.0:

      print("Letter Grade: C")

  elif float(result) >= 60.0 and float(result) < 70.0:

      print("Letter Grade: D")

  else:

      print("Letter Grade: F")

  print(" ")

for i in range(2):

  name = input("Student Name: ")

  result = calc_average(name)

  determine_grade(result)

See more about python at brainly.com/question/26104476

Answer:

The program doesn't make use of comments (See Explanation)

Also the source code is attached as image to enable you see the proper format and indexing of the source code

The program using python is as follows

def calc_average(name):

   score = []

   sum = 0

   for j in range(8):

       inp = int(input("Test Score"+str(j+1)+": "))

       score.append(inp)

       sum = sum + inp

       if inp>=90 and inp<=100:

           print("A")

       elif inp>=80 and inp<90:

           print("B")

       elif inp>=70 and inp<80:

           print("C")

       elif inp>=60 and inp<70:

           print("D")

       else:

           print("F")

   avg = sum/8

   print("Result Details of "+name)

   print("Average Score: "+str(avg))

   return avg

def determine_grade(result):

   if float(result) >= 90.0 and float(result) <= 100.0:

       print("Letter Grade: A")

   elif float(result) >= 80.0 and float(result) <90.0:

       print("Letter Grade: B")

   elif float(result) >= 70.0 and float(result) < 80.0:

       print("Letter Grade: C")

   elif float(result) >= 60.0 and float(result) < 70.0:

       print("Letter Grade: D")

   else:

       print("Letter Grade: F")

   print(" ")

for i in range(2):

   name = input("Student Name: ")

   result = calc_average(name)

   determine_grade(result)

Explanation:

def calc_average(name):  -> Declares the function calc_average(name); It accepts local variable name from the main function

   score = []

-> Initialize an empty list to hold test scores

   sum = 0

-> Initialize sum of scores to 0

   for j in range(8):

-> Iterate from test score 1 to 8

       inp = int(input("Test Score"+str(j+1)+": "))

-> This line accepts test score from the user

       score.append(inp)

-> The user input is then saved in a lisy

       sum = sum + inp

-> Add test scores

The following lines determine the letter grade of each test score      

if inp>=90 and inp<=100:

           print("A")

---

      else:

           print("F")

   avg = sum/8  -> Calculate average of the test score

The next two lines prints the name and average test score of the student

   print("Result Details of "+name)

   print("Average Score: "+str(avg))

   return avg

-> This line returns average to the main method

The following is the determine_grade method; it takes it parameter from the main method and it determines the letter grade depending on the calculated average

def determine_grade(result):

   if float(result) >= 90.0 and float(result) <= 100.0:

       print("Letter Grade: A")

   elif float(result) >= 80.0 and float(result) <90.0:

       print("Letter Grade: B")

   elif float(result) >= 70.0 and float(result) < 80.0:

       print("Letter Grade: C")

   elif float(result) >= 60.0 and float(result) < 70.0:

       print("Letter Grade: D")

   else:

       print("Letter Grade: F")

   print(" ")

for i in range(2):

-> This is the main method

   name = input("Student Name: ")  -> A local variable stores name of the student

   result = calc_average(name)  -> store average of scores in variable results

   determine_grade(result)-> Call the determine_grade function

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