Answer:

**Answer:**

And we can use the complement rule and we got:

**Step-by-step explanation:**

**Previous concepts**

**Normal distribution**, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The **Z-score** is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

**Solution to the problem**

Let X the random variable that represent the bank account balances of a population, and for this case we know the distribution for X is given by:

Where and

Since the distribution of X is normal then the distribution for the sample mean is given by:

And we can use the z score formula given by:

And using this formula we got:

And we can use the complement rule and we got:

Answer:

Answer: the probability is 0.49

Step-by-step explanation:

Since the account balances at the large bank are normally distributed.

we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = account balances.

µ = mean account balance.

σ = standard deviation

From the information given,

µ = $1,637.52

σ = $623.16

We want to find the probability that a simple random sample of 400 accounts has a mean that exceeds $1,650. It is expressed as

P(x > 1650) = 1 - P(x ≤ 1650)

For x = 1650,

z = (1650 - 1637.52)/623.16 = 0.02

Looking at the normal distribution table, the probability corresponding to the z score is 0.51

P(x > 1650) = 1 - 0.51 = 0.49

Given the statement, TSR: ABC and the diagramof the right triangle TSR, determine theapproximate length of BC

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.y = 3x

Mr Thompson wants to cut a 5-ft rope into a 1/4-ft sections how many 1/4 sections will he have

Identify any outliers in the data set. 35,41,44,45,47,58

What is the answer to this problem and why 60+60×0+1=

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.y = 3x

Mr Thompson wants to cut a 5-ft rope into a 1/4-ft sections how many 1/4 sections will he have

Identify any outliers in the data set. 35,41,44,45,47,58

What is the answer to this problem and why 60+60×0+1=

**Answer:**

18√2

**Step-by-step explanation:**

The area of the smaller triangle is 1/2 that of the larger one. Since the triangles are similar, the dimensions of the smaller triangle are √(1/2) those of the larger one.

36 · √(1/2) = 36 · (√2)/2 = **18√2 . . . . length of line dividing the triangle**

**Answer:**

So, we get that is **P(A)=0.32.**

**Step-by-step explanation:**

We know that:

We have the formula for probability:

So, we calculate:

We calculate:

So, we get that is **P(A)=0.32.**

To find P(A), use the law of total probability given that B1 and B2 are mutually exclusive and complementary events. Substituting the provided values, P(A) = 0.32.

The question is asking us to calculate P(A), given the values for P(A | **B1**) and P(A | **B2**), and the knowledge that **B1 and B2 are mutually exclusive and complementary** events. In probability, if events B1 and B2 are mutually exclusive and complementary, this means that one and only one of them can occur, and their occurrence covers all possible outcomes. We can use the law of total probability to find the overall P(A). The law of total probability states that P(A) = P(A | B1) * P(B1) + P(A | B2) * P(B2). Plugging the provided values into this formula, we get P(A) = .2 * .6 + .5 * .4 = .12 + .2 = .32. Therefore, P(A) is .32.

#SPJ11

PLS HELP ME!!!

16 since 12.5% is 1/8 of 100 and 2 times 8 is 16

The answer to the question is 25.

**Answer:**

See below.

**Step-by-step explanation:**

First, distribute:

Now, perform partial fraction decomposition. This is only two factors, so we only need linear functions:

Now, multiply everything by x(x+1):

Now, solve for each variable. Let's let x=-1:

Now, let's let x=0:

So:

Double Check:

For the answer to the question above,

the answer is "The student can have only one blood type, so the actual events are mutually exclusive. "

The probabilities are not mutually exclusive. Based on the group

P(Type O) = 9/20 = 45% or 0.45

P(Type A) = 2/5 = 40% or 0.40

P(Other) = 3/20 = 15% or 0.15

I hope my answer helped you. Feel free to ask more questions. Have a nice day!

the answer is "The student can have only one blood type, so the actual events are mutually exclusive. "

The probabilities are not mutually exclusive. Based on the group

P(Type O) = 9/20 = 45% or 0.45

P(Type A) = 2/5 = 40% or 0.40

P(Other) = 3/20 = 15% or 0.15

I hope my answer helped you. Feel free to ask more questions. Have a nice day!

Hello there.

A group of students is donating blood during a blood drive. a student has 9/20 probability of having type 'o' blood and a 2/5 probability of having type 'A'.what is the probability that a student has type 'o' or type 'a' blood and why?

**The student can have only one blood type, so the actual events are mutually exclusive.**

A group of students is donating blood during a blood drive. a student has 9/20 probability of having type 'o' blood and a 2/5 probability of having type 'A'.what is the probability that a student has type 'o' or type 'a' blood and why?

The **parameter** used in the **probability** is the average number of **students** represented by u.

The **confidence interval** based on the information will be:

= 3.85 - 2.09(1.348 / ✓20)

= **3.22**

Also, 3.85 + 2.09(1.348 / ✓20) = **4.48**

The **confidence interval** simply means that one is 95% **confident** that the true mean is between 3.22 and 4.48.

Learn more about **probability** on:

**Answer:**

a) The parameter of interest on this case is who represent the average number of students in order to create an app.

b)

The 95% confidence interval is given by (3.22;4.48)

c) For this case we have 95% of confidence that the true mean for the average number of students in order to create an app is between 3,22 and 4.48.

d) We have the following criteria in order to decide: "You determine that if more than three students share a ride, on average, you will create the app"

So then since the lower limti for the confidence interval is higher than 3 we can conclude that at 5% of significance we have more than 3 students share a ride so then makes sense create the app.

**Step-by-step explanation:**

**Part a**

The parameter of interest on this case is who represent the average number of students in order to create an app.

**Part b**

Data: 6 5 5 5 3 2 3 6 2 2 5 4 3 3 4 2 5 3 4 5

n=20 represent the sample size

represent the sample mean

represent the sample standard deviation

m represent the margin of error

Confidence =95% or 0.95

A **confidence interval** is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The **margin of error** is the range of values below and above the sample statistic in a confidence interval.

**Normal distribution**, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

**Calculate the mean and standard deviation for the sample**

On this case we need to find the sample standard deviation with the following formula:

And in order to find the sample mean we just need to use this formula:

The sample mean obtained on this case is and the deviation s=1.348

**Calculate the critical value tc **

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by and . The degrees of freedom are given by:

We can find the critical values in excel using the following formulas:

"=T.INV(0.025,19)" for

"=T.INV(1-0.025,19)" for

The critical value

**Calculate the confidence interval **

The interval for the mean is given by this formula:

And calculating the limits we got:

The 95% confidence interval is given by (3.22;4.48)

**Part c**

For this case we have 95% of confidence that the true mean for the average number of students in order to create an app is between 3.22 and 4.48.

**Part d**

We have the following criteria in order to decide: "You determine that if more than three students share a ride, on average, you will create the app"

So then since the lower limti for the confidence interval is higher than 3 we can conclude that at 5% of significance we have more than 3 students share a ride so then makes sense create the app.