Answer:

**Answer:**

**Step-by-step explanation:**

5) 108

6) 55

7) 49

8) 65

A boat travels for 4 hours at a constant speed of 30 km/h.How far does the boat travel?30 km120 km160 km80 km

Express each number in fraction form before finding the inverse:7,10,1 3/4,

The test scores for a group of students are shown. 87, 72, 98, 84, 72, 65, 72, 70, 58, 91, 81, 84 What is the mode of the scores? A. 84 B. 78.8 C. 98 D. 85.5

Can someone answer this plzz

What property is this? 1. 2(4+3−6) = 2×4+2×3−2×6Commutative PropertyAssociative PropertyDistributive PropertyIdentity PropertyZero PropertyWhat property is this? 2. 7000×1=7000Distributive PropertyZero PropertyIdentity PropertyCommutative PropertyAssociative PropertyWhat property is this? 3. 3×(7×1)=(3×7)×1Distributive PropertyZero PropertyAssociative PropertyCommutative PropertyIdentity PropertyWhat property is this? 4. 48×0=0Commutative PropertyDistributive PropertyIdentity PropertyAssociative PropertyZero PropertyWhat property is this? 5. 4×2×1×9=9×1×2×4Commutative PropertyIdentity PropertyZero PropertyAssociative PropertyDistributive Property

Express each number in fraction form before finding the inverse:7,10,1 3/4,

The test scores for a group of students are shown. 87, 72, 98, 84, 72, 65, 72, 70, 58, 91, 81, 84 What is the mode of the scores? A. 84 B. 78.8 C. 98 D. 85.5

Can someone answer this plzz

What property is this? 1. 2(4+3−6) = 2×4+2×3−2×6Commutative PropertyAssociative PropertyDistributive PropertyIdentity PropertyZero PropertyWhat property is this? 2. 7000×1=7000Distributive PropertyZero PropertyIdentity PropertyCommutative PropertyAssociative PropertyWhat property is this? 3. 3×(7×1)=(3×7)×1Distributive PropertyZero PropertyAssociative PropertyCommutative PropertyIdentity PropertyWhat property is this? 4. 48×0=0Commutative PropertyDistributive PropertyIdentity PropertyAssociative PropertyZero PropertyWhat property is this? 5. 4×2×1×9=9×1×2×4Commutative PropertyIdentity PropertyZero PropertyAssociative PropertyDistributive Property

A.

1350 mm3

B.

225 mm3

C.

45 mm3

D.

3375 mm3

I'm guessing 15 mm is the side length.

V = a^3

Where 'a' is the side length.

V = 15^3

V = 3375

So the volume of the cube is**3375 mm^3**.

V = a^3

Where 'a' is the side length.

V = 15^3

V = 3375

So the volume of the cube is

a cube volume is side legnth=x x^3

so assuming that 15 is the side legnth then

15^3=15 times 15 times 15=3375mm^3 which is D

so assuming that 15 is the side legnth then

15^3=15 times 15 times 15=3375mm^3 which is D

Seventh Grade: 183, 187, 204, 215, 196

Use the mean absolute deviation to compare the variability in the mean number of pages read by students in each grade.

Thank you in advance!

102 for 4th graders

197 for 7th graders

95 pages between 4th and 7th graders

197 for 7th graders

95 pages between 4th and 7th graders

4k^3 - 8k^2 + 6k^2 - 12k - 6k - 9

Combine like terms... -8k^2+6k^2= -4k^2

-12k+6k=-6k

and leave 4k^3 and -9 alone because you don't have anything to combine it with so the equation is 4k^3 -4k^2 -6k -9

Combine like terms... -8k^2+6k^2= -4k^2

-12k+6k=-6k

and leave 4k^3 and -9 alone because you don't have anything to combine it with so the equation is 4k^3 -4k^2 -6k -9

You will get to the store in 2 hours because 5 * 2 equals 2.

Now add 5:30 plus 120 minutes to get 7:30.

Once you leave the store and walk back home that will be another 2 hours.

Add those 120 minutes to the 7:30 to get 9:30.

You will arrive on the dot at your home. Hope this helps!

Now add 5:30 plus 120 minutes to get 7:30.

Once you leave the store and walk back home that will be another 2 hours.

Add those 120 minutes to the 7:30 to get 9:30.

You will arrive on the dot at your home. Hope this helps!

7919 miles in the next 5 months

If this pertains to the Pythagorean theorem, then the answer that you would most likely to end up with is by utilizing the equation a² + b² = c² where a and b are the legs of the triangle and c is the hypotenuse. The hypotenuse refer to the longest side of the triangle while the other two would be the legs of the triangle.

When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.

When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.