# Over the course of a multi-stage 4510-km bicycle race, the front wheel of an athlete's bicycle makes 1.70x106 revolutions. How many revolutions would the wheel have made during the race if its radius had been 1.3 cm larger

Step-by-step explanation:

The total distance traveled during the race is

D = 4510km [(1000m)/(1km)] =

The radius (r1) of the smaller bicycle wheel is

r1 =

Than the larger wheel has a radius

r2 = 0.329 m + 0.012 m = 0.341 m

Over the same distance this wheel would make N2 revolutions

N2 =

## Related Questions

Sin A = 22/33.3 ≈ 0.7

Step-by-step explanation:

Sin A = opp/hyp

Opp = 22

Apply pythagorean theorem to find the hypotenuse length.

Thus:

Hyp = √(25² + 22²) ≈ 33.3

Therefore,

Sin A = 22/33.3 ≈ 0.7 (nearest tenth)

Paul has \$20,000 to invest. His intent is to earn 10.5% interest on his investment. He can invest part of his money at 7% interest and part at 12% interest. How much does Paul need to invest in each option to make 10.5% interest on his investment?Paul should invest \$
and \$
to earn 10.5% on his investments.

x=7%
y=12%
x+y=20000
0.07x+0.12y=20000*0.19=3800

Emily drove to town with an average speed of 32 miles per hour, and then back home with an average speed of 38 miles per hour. If her total traveling time was 42 minutes, how far is it from home to town?

• 12.16 miles

Step-by-step explanation:

Speed - s,   Distance - d,  Time - t

Equation of time is:

• t = d/s

Given,

• s1 = 32 m/h, s2 = 38 m/h, t1 + t2 = 42 min = 42/60 h = 7/10 h

Total time is the sum of time values to and from the town:

• d/32 + d/38 = 7/10
• d/16 + d/19 = 7/5
• d(1/16 + 1/19) = 7/5
• d(16 + 19) = 7(16*19)/5
• 35d = 425.6
• d = 425.6/35
• d = 12.16

It is given that,

→ s1= 32 miles/h

→ s2 = 38 miles/h

Now t1 + t2 is,

→ 42 min

→ 42/60 hours

→ 7/10 hours

The formula we use,

→ Time = Distance/Speed

→ t = d/s

Then the total time is the,

Sum of time values to and from the town.

→ d/32 + d/38 = 7/10

→ d/16 + d/19 = 7/5

→ d{(1/16) + (1/19)} = 7/5

→ d(16 + 19) = (7/5) × (16 × 19)

→ 35d = 425.6

→ d = 425.6/35

→ d = 12.16

Hence, the distance is 12.16 miles.

Find the scale.

Model length: 40 cm

Actual length: 60 m

2/3

Step-by-step explanation:

Given

Model length: 40 cm

Actual length: 60 m

Scale for any model is ratio of model length of object and actual length of object

Therefore scale for problem stated = Model length/Actual length

= 40/60 = 4/6 = 2/3

Given g(x) = -X – 1, solve for x when g(x) = 3.

-4 = x

Step-by-step explanation:

g(x) = -X – 1

g(x) = 3

3 = -x-1

3+1 = -x-1+1

4 = -x

Multiply by -1

-4 = x

- 4 = x
Hopefully it helps

Tom ate 1/4 of a pizza. he divided the leftover pizza into pieces each equal to 1/12 of the original pizza. after he gave some friends 1 piece each, 1/6th