Gabriella swims 2 laps per minute. What is the associated rate? ___ minute per lapA.2
B.4
C.1/4
D.1/2


ANSWER QUICKKK

Answers

Answer 1
Answer:

Answer:

The answer is D.

Step-by-step explanation:

ItisgiventhatGabriellaswims2lapsfor1minute.Soinordertofindhowmanyminutesdidheswimforeachlap,youhavetodivideitby2:

2 laps = 1 minute

2 laps ÷ 2 = 1 minute ÷ 2

1 lap = 1/2 minute

= 30 seconds

Test:

Gabriella swim 1/2 min per lap. So if he swim 2 laps, you have to multiply it by 2 :

1/2 × 2 = 1 minute

Answer 2
Answer:

Answer:

The answer is D

Step-by-step explanation:

HOPE THIS HELPS


Related Questions

The​ point-slope form of the equation of a nonvertical line with slope, m, that passes through the point (x1,y1) is...?a. Ax+By=c b. y-y1=m(x-x1) c. y1=mx1+b d. Ax1+by1=C e. y=mx+b f. y1-y=m(x-x1) Please explain why, if you can. Thanks! :)
A couch sells for $820. Instead of paying the total amount at the time of purchase, the same couch can be bought by paying $400 down and $60 per month for 12 months. How much is saved by paying the total amount at the time of purchase?
Is 16.5 the same thing as 16 or is it greater than 16?
Maria found the least common multiple of 6 and 15. Her work is shown below.Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . .Multiples of 15: 15, 30, 45, 60, . . .The least common multiple is 60.What is Maria’s error?the answer is IDK
Find the value of x in the triangle above Thank you to whoever helps

hi can someone help me with is problem on how to break it down so I can explain it to my daughter. please.​

Answers

Answer:  30

==========================================================

Explanation:

Refer to the drawing below. I have a 2 by 5 grid of squares. So there are 2*5 = 10 squares total.

Four of those squares are shaded blue to represent the fraction (4)/(10)

If Susan used 4 blue tiles (instead of 12), then she'd have 10 tiles total. This would mean 10 would be the answer.

However, she's using 12 blue tiles. The jump from 4 to 12 is "times 3". So we'll need to multiply that 10 by 3 as well.

10*3 = 30

If Susan uses 12 blue tiles, then she has 30 tiles total.

Notice that the fraction (4)/(10) is the same as (12)/(30) after multiplying both top and bottom by 3.

(4)/(10)= (4*3)/(10*3)= (12)/(30)

If you wanted, you can split a round cake into 10 equal slices. If a person eats 4 slices, then that represents the fraction (4)/(10). Now imagine splitting each of those initial ten slices into three smaller pieces. If you manage to do so, then you'd have 30 very small slices. The four that the person ate would have effectively eaten 12 very small slices. So this is another way to see how (4)/(10) = (12)/(30). Personally, when it comes to fractions, I prefer using a grid of squares because it's a bit tricky sometimes to divide up circles perfectly.

Suppose that 30% of all students who have to buy a text for a particular course want a new copy (the successes!), whereas the other 70% want a used copy. Consider randomly selecting 15 purchasers.The bookstore has 10 new copies and 10 used copies in stock.
If 15 people come in one by one to purchase this text, what is the probability that all 15 will get the type of book they want from current stock?

Answers

Answer:

The probability that all 15 will get the type of book they want from current stock is 0.4838.

Step-by-step explanation:

Denote the random variable Xas the number of students who want to buy new copy.

The probability of a student wanting to buy a new copy is, P (X) = p = 0.30.

A random sample of n = 15 students is selected.

The random variable X follows a Binomial distribution.

The probability function of a Binomial distribution is:

P(X=x)={n\choose x}p^(x)(1-p)^(n-x);\ x=0, 1, 2, 3,...

It is provided that the bookstore has 10 new copies and 10 used copies in stock.

All the 15 students get their desired copy, then this can happen if at most 10 want to buy new copy and at least 5 wants to buy used copy.

Compute the probability of (5 ≤ X ≤ 10) as follows:

P (5 ≤ X ≤ 10) = P (X = 5) + P (X = 6) + P (X = 7) + P (X = 8) + P (X = 9) + P (X = 10)

                     ={15\choose 5}(0.30)^(5)(1-0.30)^(15-5)+{15\choose 6}(0.30)^(6)(1-0.30)^(15-6)\n+{15\choose 7}(0.30)^(7)(1-0.30)^(15-7)+{15\choose 8}(0.30)^(8)(1-0.30)^(15-8)\n+{15\choose 9}(0.30)^(9)(1-0.30)^(15-9)+{15\choose 10}(0.30)^(10)(1-0.30)^(15-10)\n=0.2061+0.1472+0.0811+0.0348+0.0116+0.0030\n=0.4838

Thus, the probability that all 15 will get the type of book they want from current stock is 0.4838.

A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtained if she wishes the estimate to be within 0.03 with 90% confidence if (a) she uses a previous estimate of 0.34?(b) she does not use any prior estimates? n=_____(Round up to the nearest integer.)

Answers

Answer:

675 samples

752 samples

Step-by-step explanation:

Given that :

α = 90%

E = 0.03

Previous estimate (p) = 0.34

Estimated sample proportion (n)

n = p *q * (Zcritical /E)

Zcritical = α/2 = (1 - 0.9) /2 = 0.1 / 2 = 0.05

Z0.05 = 1.645 ( Z probability calculator)

q = 1 - p = 1 - 0.34 = 0.66

n = 0.34 * 0.66 * (1.645/0.03)^2

n = 674.70

n = 675

B.) without prior estimate given ;

p and q should have equal probability

Hence ;

p = 0.5 ; q = 0.5

n = 0.5 * 0.5 * (1.645/0.03)^2

n = 751.67361

n = 752

Final answer:

To determine the sample size for the research, a mathematical calculation is required, considering the level of confidence, the desired margin of error, and, if available, a previous estimate. For a 90% confidence level, two calculations are made based on an assumed proportion—first using the existing estimate of 0.34, and second with no prior estimate (commonly taken as 0.5).

Explanation:

The researcher is trying to determine the sample size required for a study on high-speed Internet access. The sample size can be calculated based on the level of confidence desired and the desired margin of error. In this case, (a) she is using a previous estimate of 0.34 and (b) she does not use any prior estimates.

For the calculation, we can use the formula for sample size in hypothesis testing for a population proportion:

n = (Z^2 * p * (1-p)) / E^2

Where:

  • n = required sample size
  • Z = z-score corresponding to our desired level of confidence
  • p = assumed proportion (in part (a) this is 0.34)
  • E = desired margin of error

For a 90% confidence level, the corresponding z-score is approximately 1.645. Now we can plug in the numbers.

(a) If she uses a previous estimate of 0.34, the calculation would be:

n = (1.645^2 * 0.34 * 0.66) / (0.03)^2

You will need to round up to the nearest whole number as you cannot have a part of a participant.

(b) If no previous estimate is used, it is common practice to use 0.5 as this will provide the maximum variance and, therefore, the largest sample size. The calculation would be:

n = (1.645^2 * 0.5 * 0.5) / (0.03)^2

Again, round up to the next whole number. Insert the results for these calculations to your answer.

Learn more about Sample Size Calculation here:

brainly.com/question/33689461

#SPJ3

Help me!, CERTAIN ANSWRS INLY I DONT UNDEDRSTNDDDDDD THANK YOU IN ADVance

Answers

Answer:

Initial temperature = 20° C

Temperature after 18 minutes = 4° C

Step-by-step explanation:

Function representing the relation in the temperature of the soda and time has been given as,

T(x) = -8+28e^(-0.045x)

Here x = number of minutes since the can was placed in the cooler

For initial temperature of the soda,

x = 0,

T(0) = -8+28e^((28* 0))

      = -8 + 28(1)

      = 20° C

For the temperature after 18 minutes,

x = 18,

T(18) = -8+28.e^(-0.045* 18)

       = -8+28.e^((-0.81))

       = -8+12.456

       = 4.456 C

       ≈ 4° C

Which conclusion can be drawn from the data?Question 9 options:

For ten weeks, City A received less rainfall, on average, than City B.


The range between the maximum and minimum values for City B is greater than the range between maximum and minimum values for City A.


During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.


The median for City A is less than the median for City B.

Answers

Answer:

During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

Step-by-step explanation:

Given the data :

City A :

Reordered data:

0, 0.2, 0.2, 0.3, 0.4, 1, 1.3, 1.5, 2.5, 3

City B :

Reordered data:

0, 0, 0.1, 0.1, 0.2, 0.3, 0.4, 1, 1, 1

Using a calculator :

Mean Rainfall for City A = 1.04

Mean rainfall for city B = 0.41

Range : maximum - minimum

City A = 3 - 0 = 3

City B = 1 - 0 = 1

Mode (most occurring) :

City A = 0.2

City B = 1

Median :

City A = 0.7

City B = 0.25

The only true conclusion in the options given that can be drawn from the data is that ;During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

Answer:

the Answer is C.

Step-by-step explanation:

I just took the test

Part E
Christopher Columbus set sail from Spain in 1492. In what year did the Civil War end?

Answers

Answer:

The civil war ended in 1865

Answer:

1865

Step-by-step explanation:

Other Questions