What is the molarity if 24 moles of solute are dissolved into 6 L of solution?

Answers

Answer 1
Answer:

Answer:

Molarity= 4M

Explanation:

n= CV

24= C×6,

C= 24/6 = 4M

Answer 2
Answer:

Answer:4M

Explanation:

Number of moles=24

Volume=6L

Molarity=number of moles ➗ volume

Molarity=24 ➗ 6

Molarity=4M


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How is Hess's law used to measure enthalpy of a desired reaction?A. The enthalpy is obtained from the enthalpy of an intermediate
step.
B. The enthalpy is determined from the enthalpy of similar reactions.
C. The enthalpy from the final equation in a series of reactions is
used
D. Intermediate equations with known enthalpies are added together.

Answers

Hess's law is used to measure the enthalpy of a desired chemical reaction because: D. Intermediate equations with known enthalpies are added together.

What is Hess's Law?

Hess's Law is also known as Hess's law of constant heat summation (enthalpy) and it was named after a Swiss-born Russian chemist called Germain Hess.

Hess's Law states that the energy change (enthalpy) experienced in a desired chemical reaction is equal to the sum of the energy changes (enthalpies) in each chemical reactions that it is made up of or contains.

Read more on Hess's Law here: brainly.com/question/9328637

How many molecules are shown in the chemical formula pictured? H3PO4A) 1
B) 3
C) 4
D) 7

Answers

Answer

A(1)

Explanation:

If you don't see a coefficient, which is the big number in front of the formula, then it's only one molecule.

Example of coefficient

4H3PO4  

When a solid compound is formed from chemicals that are in solution, it is called aprecipitate
condensate
crystal

Answers

Answer:

Precipitate

Explanation:

Question 51 pts A breathalyzer is a device used to estimate the blood alcohol content of a suspected drunk driver by measuring the amount of alcohol in one's breath. The fuel cell breathalyzer employs the reaction below: CH3CH2OH(g)+O2(g)→HC2H3O2(g)+H2O(g) When a suspected drunk driver blows his or her breath through the fuel-cell breathalyzer, the device measures the current produced by the reaction and calculates the percent alcohol in the breath. How many moles of electrons are transferred per mole of ethanol, CH3CH2OH, in the reaction?

Answers

Answer:

Four moles of electrons

Explanation:

The reactions in a breathalyzer are redox reactions. Fuel cell breathalyzers consists of fuel cells with platinum electrodes. The current produced depends on the amount of alcohol in the breath. Detection of alcohol involves the oxidation of ethanol to ethanoic acid. The two half cells set in the process are;

Anode;

C2H5OH(aq) + 4OH^-(aq) ----------> CH3COOOH(aq) + 3H2O(l) + 4e

Cathode;

O2(g) + 2H2O(l) +4e--------> 4OH^-(aq)

Hence four electrons are transferred in the process.

Write a balanced nuclear equation for the following: The nuclide uranium-238 undergoes alpha emission.

Answers

Answer:

²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He + Energy

Explanation:

Hello,

When uranium undergoes an alpha decay, it's atomic number is reduced by 2 while it atomic mass is reduced by 4 similar to the elements helium (He) and sometimes alpha decay is represented by a helium atom.

Equation of decay

²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He + Energy

When uranium undergoes an alpha decay, it loses an alpha particle similar to a helium atom and forms thorium which has an atomic number of 90 and atomic mass of 234 with the release of energy.

The standard entropy of Pb(s) at 298.15 K is 64.80 J K–1 mol–1. Assume that the heat capacity of Pb(s) is given by: CP,m(Pb, s) J K−1mol−1 = 22.13 + 0.01172 T K + 1.00 x 10−5 T 2 K2 The melting point is 327.4 ℃ and the heat of fusion is 4770 J mol-1. Assume that the heat capacity of Pb(l) is given by: CP,m(Pb, l) J K−1mol−1 = 32.51 − 0.00301 T K Calculate the standard entropy of Pb(l) at 500 ℃

Answers

Answer:

s_(Pb(l),500\°C)=100.83(J)/(mol*K)

Explanation:

Hello,

In this case, for the calculation of the standard entropy of liquid lead at 500 °C (773.15 K), starting by solid lead 298.15 K we need to consider three processes:

1. Heating of solid lead at 298.15 K to 600.55 K (melting point).

2. Melting of solid lead to liquid lead.

3. Heating of liquid lead at 600.55 K (melting point) to 773.15 K.

Which can be written in terms of entropy by:

s_(Pb(l),500\°C)=s_(Pb(s),298.15K)+s_1+s_2+s_3

Whereas each entropy is computed as follows:

s_1=\int\limits^(600.55K)_(298.15K) {(22.13 + 0.01172 T  + 1.00 x 10^(-5) T^2)/(T) } \, dT =20.4(J)/(mol*K)\n\n\ns_2=(4770(J)/(mol) )/(600.55K)= 7.94(J)/(mol*K)\n\n\ns_3=\int\limits^(773.15K)_(600.55K) {(32.51-0.00301T)/(T) } \, dT=7.69(J)/(mol*K)

Therefore, the standard entropy of liquid lead at 500 °C turns out:

s_(Pb(l),500\°C)=64.80+20.4+7.94+7.69\n\ns_(Pb(l),500\°C)=100.83(J)/(mol*K)

Best regards.