What is the sum in simplest form?
4 1/2 + 1 3/5


Answer 1


23  1/10

Step-by-step explanation:

Answer 2

Final answer:

To find the sum in simplest form of 4 1/2 and 1 3/5, you convert each to an improper fraction, adding the fractions and convert back to a mixed number. The sum is 6 1/10.


The sum in simplest form of the two numbers 4 1/2 and 1 3/5 can be calculated as follows:

  1. Change each mixed number into an improper fraction. 4 1/2 becomes 9/2 and 1 3/5 becomes 8/5.
  2. Then add the two fractions: 9/2 + 8/5 equals 45/10 + 16/10 (after finding a common denominator), which equals 61/10.
  3. Finally, convert back to a mixed number to get 6 1/10.

So, the sum in the simplest form of 4 1/2 and 1 3/5 is 6 1/10.

Learn more about Fraction Addition here:



Related Questions

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Please help with the last question & explain it to me. Thank you.
A student is taking a multiple-choice exam in which each question has four choices. Assume that the student has no knowledge of the correct answers to any of the questions. She has decided on a strategy in which she will place four balls (marked A, B, C, and D) into a box. She randomly selects one ball for each question and replaces the ball in the box. The marking on the ball will determine her answer to the question. There are five multiple choice questions on the exam. What is the probability that she will geta. Five questions correct?b. At least four questions correct?c. No questions correct?d. No more than two questions correct?

Pls help I will fail 10th grade




Step-by-step explanation:

Please mark brainiest

(c) Simplify fully
exex fxf



i know its a bit late but the answer below

Step-by-step explanation:


Could u be more specific

Chan receives a bonus from his job. He pays 30% taxes, pays 30% charity and 25% debt. Has $600 remaining from his bonus. What was the total amount of chains bonus?



b = $4000

Step-by-step explanation:

Let b represent the bonus amount.

Then the bonus, b, less the three deductions, is represented by

b - 0.30b - 0.30b - 025b, and this comes to $600.  Find the value of b.

b - 0.85b = $600, or

0.15b = $600

Then b = $4000

Help pls with answer!!!Rewrite the function in the given form.



g(x) = (-2)/(x-1)+5\n\n

The graph is shown below.



Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

g(x) = (5x-7)/(x-1)\n\ng(x) = (5x-5-2)/(x-1)\n\ng(x) = ((5x-5)-2)/(x-1)\n\ng(x) = (5(x-1)-2)/(x-1)\n\ng(x) = (5(x-1))/(x-1)+(-2)/(x-1)\n\ng(x) = 5+(-2)/(x-1)\n\ng(x) = (-2)/(x-1)+5

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).


Compare the equation g(x) = (-2)/(x-1)+5\n\n to the form g(x) = (a)/(x-h)+k\n\n

We can see that

  • a = -2
  • h = 1
  • k = 5

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

  • (-1,6)
  • (0,7) .... y intercept
  • (1.4, 0) .... x intercept
  • (2, 3)
  • (3, 4)

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.




Initial temperature = 20° C

Temperature after 18 minutes = 4° C

Step-by-step explanation:

Function representing the relation in the temperature of the soda and time has been given as,

T(x) = -8+28e^(-0.045x)

Here x = number of minutes since the can was placed in the cooler

For initial temperature of the soda,

x = 0,

T(0) = -8+28e^((28* 0))

      = -8 + 28(1)

      = 20° C

For the temperature after 18 minutes,

x = 18,

T(18) = -8+28.e^(-0.045* 18)

       = -8+28.e^((-0.81))

       = -8+12.456

       = 4.456 C

       ≈ 4° C

We wish to study the quality of our production line. We take a random sample of 1000 widgets from our line. A quality rating was determined for each of the 1000 widgets, and the average quality rating in the sample was 4. The sample standard deviation was 0.5. Also, 6 of the 1000 widgets were found to be defective.Estimate the average quality rating for widgets from our production line, and include the uncertainty in this estimate in the form, a ± b.



Average quality rating was 4.54+-0.00549

Final answer:

The estimate for the average quality rating from the production line, given this sample, is 4, with a degree of uncertainty expressed by a 95% confidence interval of 4 ± 0.031. The confidence interval represents a range whereby we can be 95% confident that the true mean lies within.


Since you have the average (mean) quality rating and standard deviation from a sample size of 1000 widgets, we can use these statistics to establish an estimate for the entire production line. The estimate of the average quality rating is given as 4. However, to account for the uncertainty of our estimate due to it being based upon a sample rather than the entire population, we use the concept of a confidence interval.

The formula for a confidence interval is mean ± z* (standard deviation/sqrt(n)), where z is a z-score corresponding to our desired level of confidence. For simplicity, we can use a z-score of 1.96 to represent a confidence level of 95%.

Therefore, the uncertainty in this estimate (at 95% confidence) is calculated as:1.96 * (0.5/sqrt(1000)), approximately equal to 0.031. So the confidence interval for the average quality of widgets is 4 ± 0.031.

Learn more about Confidence Interval here: