# 11. Number Sense Jamal saysthat the sumof 183 + 198 is less than 300. IsJamal'sanswer reasonable? Why orwhy notBoth addends aredes to 200.

Jamal's answer isn't reasonable because the sum of 183 and 198 is 381, which is way more than 300 and nowhere less than 300.

Step-by-step explanation:

Jamal makes an assertion that the sum of 183 and 198 is less than 300.

We are to check if Jamal's answer is reasonable or not.

183 + 198 = 381 > 300

The sum of the two numbers, 381, is evidently not less than 300, hence, Jamal's answer isn't reasonable because it is downright wrong.

Hope this Helps!!!

## Related Questions

1) A home improvement store sold wind chimes for w dollars each. A customer signed up for a free membership card and received a 5% discount off the price. Sales tax of 6% was applied after the discount. Write an algebraic expression to represent the final price of the wind chime.

Step-by-step explanation:

The original price of the wind chimes at the home improvement store is \$w.

A customer signed up for a free membership card and received a 5% discount off the price. The value of the discount is

5/100 × w = 0.05w

The discounted price would be

w - 0.05w = 0.95w

Sales tax of 6% was applied after the discount. The amount of sales tax applied would be

6/100 × 0.95w = 0.057w

The algebraic expression to represent the final price of the wind chime is

0.95w + 0.057w

= 1.007w

If G is midpoint of FH, find FG

consider a population of voters. suppose that that there are n=1000 voters in the population, 30% of whom favor jones. identify the event favors jones as a success s. it is evident that the probability of s on trial 1 is 0.30. consider the event b that s occurs on the second trial. then b can occur two ways: the first two trials are both successes or the first trial is a failure and the second is a success. show that p(b) = 0.3

P(B)=0.30

Step-by-step explanation:

Out of 1000 Voters, 30% favor Jones.

Event S=Favors Jones on First Trial

Event B=S occurs on Second Trial

P(S)=0.30

P(S')=1-0.30=0.70

Event B could occur in two ways

1. The first two trials are a success
2. The first trial is a failure and the second trial is a success.

Therefore,

P(B)=P(SS)+P(S'S)

=(0.3X0.3)+(0.7X0.3)

=0.09+0.21

=0.3

Therefore, the probability of event B(that event S occurs on the second trial), P(B)=0.30.

Lengths of time, in months for a tumor to recur after chemotherapy I need answers for questions 1-8

Answer: irdk the awnser but F on that tumor

Write in slope intercept form an equation of the line that passes through the given points. (0,4) (4,8) and (-2,3) (-4,4)

y-8=1(x-4)

Step-by-step explanation:

I used the equations y-y/x-x and y-__y__=__m__(x-__x__)

y=-8=1(x-4) hope that helped!

Organisms A and B start out with the same population size. Organism A's population doubles every day. After 5 days, the population stops growing and a virus cuts it in half every day for 3 days. Organism B's population grows at the same rate but is not infected with the virus. After 8 days, how much larger is organism B's population than organism A's population? Answer the questions to find out. The expression showing organism A's decrease in population over the next 3 days is ( 1 2 ) ( 2 1 ​ ) 3 . This can be written as (2–1)3. Write (2–1)3 with the same base but one exponent.

The number of times organism B's population is larger than organism A's population after 8 days is 32 times

Step-by-step explanation:

The population of organism A doubles every day, geometrically as follows

a, a·r, a·r²

Where;

r = 2

The population after 5 days, is therefore;

Pₐ₅ = = 32·a

The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

P₈ =  a·2⁸ = 256·a

Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

Organism A's population at the end of 5 days is 2^5. After 5 days, a virus cuts it in half for 3 days. Organism B's population at the end of 8 days is 2^8. To find the difference, subtract organism A's population from organism B's population.

### Explanation:

Organism A's population doubles every day for 5 days, so the population at the end of 5 days is 25. After 5 days, a virus cuts the population in half for 3 days, so we need to find (25) * (2-1)3. Using the rule of exponents, we can rewrite this expression as (25+(-1*3)), which simplifies to 2-4.

Organism B's population grows at the same rate but is not infected with the virus. After 8 days, the population is 28.

To find out how much larger organism B's population is than organism A's population, we need to subtract the population of organism A from organism B. So, 28 - 2-4 is the answer.