I need help with math can someone help me I’ll show the question?

Answers

Answer 1
Answer: What’s your question

Related Questions

A.3(f) The line graphed on the grid represents the first of two equations in a system of linear equations.20-1612-8-20 -16 -12--4481216 2024-8-1216If the graph of the second equation in the system passes through (-12, 20) and (4,12), which statement is true?
Graph or explain how to graph the equation: y = 3x -5
Solve the following expression: (9 x 10) - (30 + 30). Show all steps taken.
Im still stuck.... help? :',)
Someone please tell me and also what b is

Vincent wrote an example of a proportion on the board.Evaluate Vincent’s proportion to determine if it is correct. Explain your reasoning.

Answers

Answer:

Vincent’s proportion is incorrect. His corresponding parts are not in the same position. The heights and bases are in different positions.

Step-by-step explanation:

I got it right on my assignment

Answer:    Vincent’s proportion is incorrect. His corresponding parts are not in the same position. The heights and bases are in different positions.

Step-by-step explanation: i got it right on my assignment

Find the exact values of the six trigonometric functions of given the point (-4, 5) on the terminal side of in standard position.

Answers

Answer:

\sin(\theta)=5√(41)/41\text{ and } \csc(\theta)=√(41)/5\n\cos(\theta)=-4√(41)/41\text{ and } \sec(\theta)=-√(41)/4\n\tan(\theta)=-5/4\text{ and } \cot(\theta)=-4/5

Step-by-step explanation:

Please refer to the attached figure.

So, we can see that our angle θ is in QII.

Recall All Students Take Calculus. Since this is QII, we use the Students. In other words, only sine (and cosecant) is positive. So, cosine and tangent are negative.

Now, we also know that a point is (-4,5). Referring to our figure, this means that our adjacent side is 4 (technically -4, but we can ignore this) and our opposite side is 5. So, to find the other ratios, let's find the hypotenuse.

Use the Pythagorean Theorem:

a^2+b^2=c^2

Substitute 4 for a and b for 5. Solve for c. So:

4^2+5^2=c^2

Square:

16+25=c^2

Add:

c^2=41

Take the square root:

c=√(41)

So, our side lengths are: Opposite=5; Adjacent=4; and Hypotenuse=√41.

Now, we can find our side lengths.

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 5 for Opp and √41 for Hyp. So:

\sin(\theta)=5/√(41)

Rationalize:

\sin(\theta)=5√(41)/41

Since our angle is in QII, sine stays positive.

Cosecant is the reciprocal of sine. So:

\csc(\theta)=√(41)/5

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 4 for Adj and √41 for Hyp:

\cos(\theta)=4/√(41)

Rationalize:

\cos(\theta)=4√(41)/41

Since our angle is in QII, cosine is negative. So:

\cos(\theta)=-4√(41)/41

Secant is the reciprocal of cosine. So:

\sec(\theta)=-√(41)/4

Tangent and Cotangent:

\tan(\theta)=opp/adj

Substitute 5 for Opp and 4 for Adj. So:

\tan(\theta)=5/4

Since our angle is in QII, tangent is negative. So:

\tan(\theta)=-5/4

Cotangent is the reciprocal of tangent:

\cot(\theta)=-4/5

And we are finished!

Final answer:

Using the given point (-4,5) in standard position, first calculate the radius using the Pythagorean theorem. Then, calculate each of the six trigonometric functions using the coordinates and the calculated radius.

Explanation:

The given point is (-4,5). In the standard position, the x-coordinate represents the cosine of the angle, while the y-coordinate represents the sin of the angle. However, we need to find the radius (r), which can be found using Pythagorean theorem:

r = sqrt(x

2

+ y

2

)

meaning, r = sqrt((-4)

2

+ 5

2

) = sqrt(41).  

Now, each of the six trigonometric functions can be calculated as follows:

  • Sine (Sin θ = y/r): Sin θ = 5/sqrt(41),
  • Cosine (Cos θ = x/r): Cos θ = -4/sqrt(41),
  • Tangent (Tan θ = y/x): Tan θ = -5/4,
  • Cosecant (Csc θ = r/y): Csc θ = sqrt(41)/5,
  • Secant (Sec θ = r/x): Sec θ = -sqrt(41)/4,
  • Cotangent (Cot θ = x/y): Cot θ = 4/5.

Learn more about Trigonometric Functions here:

brainly.com/question/31540769

#SPJ3

Given that r = ( 7, 3, 9) and v = ( 3, 7, -9), evaluate r + va. (-21,-21,81)
b. (10,10,0)
c. (21,21,-81)
d. (-10,-10,0)

Answers

Answer:

b. (10,10,0)

Step-by-step explanation:

r+v can be evaluated if the vectors/matrices have the same dimensions.

These do. They are both 1 by 3 vectors.

Just add first to first in each.

Just add second to second in each.

Just add third to third in each.

Example:

(5,-5,6)+(1,2,3)

=(5+1,-5+2,6+3)

=(6,-3,9)

Done!

In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).

r+v

=(7,3,9)+(3,7,-9)

=(7+3,3+7,9+-9)

=(10,10,0)

Done!

Over the 52 weeks in 2000 the price per share of a certain stock ranged in value from a low of $10.69 to a high of 33.54 by how much did the high value differ from the low value?

Answers

33.54 -10.69 = 22.85
 correct, the word difference means to subtract so the difference of 33.54 and 10,69 just means 33.54-10.69=22.85

Answer=$22.85

The sizes of houses in Kenton County are normally distributed with a mean of 1346square feet with a standard deviation of 191 square feet. For a randomly selected
house in Kenton County, what is the probability the house size is:
a. over 1371 square feet?
O Z=
o probability =
b. under 1296 square feet?
O Z=
o probability =
c. between 773 and 1637 square feet?
o zl =
o Z2 =
o probability =
Note: Z-scores should be rounded to 2 decimal places & probabilities should be
rounded to 4 decimal places.
License
Points possible: 8
This is attempt 1 of 3.

Answers

Answer:

(a) The probability that the house size is over 1371 square feet is 0.4483.

(b) The probability that the house size is under 1296 square feet is 0.3974.

(c) The probability that the house size is between 773 and 1637 square feet is 0.9344.

Step-by-step explanation:

We are given that the sizes of houses in Kenton County are normally distributed with a mean of 1346  square feet with a standard deviation of 191 square feet.

Let X = the sizes of houses in Kenton County

The z-score probability distribution for the normal distribution is given by;

                               Z  =  (X-\mu)/(\sigma)  ~ N(0,1)

where, \mu = mean size of houses = 1346 square feet

            \sigma = standard deviation = 191 square feet

(a) The probability that the house size is over 1371 square feet is given by = P(X > 1371 square feet)

        P(X > 1371) = P( (X-\mu)/(\sigma) > (1371-1346)/(191) ) = P(Z > 0.13) = 1 - P(Z \leq 0.13)

                                                             = 1 - 0.5517 = 0.4483

The above probability is calculated by looking at the value of x = 0.13 in the z table which has an area of 0.5517.

(b) The probability that the house size is under 1296 square feet is given by = P(X < 1296 square feet)

        P(X < 1296) = P( (X-\mu)/(\sigma) < (1296-1346)/(191) ) = P(Z < -0.26) = 1 - P(Z \leq 0.26)

                                                             = 1 - 0.6026 = 0.3974

The above probability is calculated by looking at the value of x = 0.26 in the z table which has an area of 0.6026.

(c) The probability that the house size is between 773 and 1637 square feet is given by = P(773 square feet < X < 1637 square feet)

       P(773 < X < 1637) = P(X < 1637) - P(X \leq 773)

 

      P(X < 1637) = P( (X-\mu)/(\sigma) < (1637-1346)/(191) ) = P(Z < 1.52) = 0.9357

       P(X \leq 773) = P( (X-\mu)/(\sigma)\leq(773-1346)/(191) ) = P(Z \leq -3) = 1 - P(Z \leq 3)

                                                             = 1 - 0.9987 = 0.0013

The above probabilities are calculated by looking at the value of x = 1.52 and x = 3 in the z table which has an area of 0.9357 and 0.9987 respectively.

Therefore, P(773 square feet < X < 1637 square feet)  = 0.9357 - 0.0013 = 0.9344.  

PLEASE HELP Function f is an exponential function. It predicts the value of a famous painting, in thousands of dollars, as a function of the number of years since it was last purchased.


What equation models this function?


(My graph is below)


Enter your answer in the box.


f(x)=

Answers

Answer:

f(x) = 8·1.25^x

Step-by-step explanation:

An exponential function has the form ...

... f(x) = a·b^x

Then f(0) = a. Your graph shows f(0) = 8.

The base "b" can be found from any other point on the graph. You have marked the point (1, 10), so we can find "b" from ...

... f(1) = 10 = 8·b^1 = 8b

... 10/8 = b = 1.25 . . . . . . . divide by the coeffiicient of b

Now, we know the exponential function is ...

... f(x) = 8·1.25^x

Answer:

The correct answer is f(x) = 8·1.25^x

Step-by-step explanation: