The total area of the parallelogram and the triangle is 160 square meters find the value x

Answers

Answer 1
Answer:

The value of x for the given triangle side in the parallelogram will be 4.

What is a parallelogram?

A basic quadrilateral with two sets of parallel sides is known as a parallelogram.

A parallelogram's facing or opposing sides are of equal length, and its opposing angles are of similar size.

What is a triangle?

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices.

The area of a parallelogram is given as,

(1/2)(sum of parallel sides)(distance between parallel lines)

Area of parallelogram = (1/2)(14 + 14)(10) = 140 square meter.

The area of the right angle triangle = (1/2)base x height.

Area of triangle = (1/2)x × 10 = 5x

Total area = 140 + 5x

160 = 140 + 5x

5x = 20

x = 4

Hence "The value of x for the given triangle side in the parallelogram will be 4".

Learn more about parallelograms here,

brainly.com/question/3050890

#SPJ5

The given question is missing a parallelogram as attached below,

Answer 2
Answer:

Answer:

80x2

Step-by-step explanation:

.


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Whats 76x168 + 69+87=

Answers

Answer:

12,924

Step-by-step explanation:

76x168= 12,768

and...

69+87= 156

nowweaddthemtogether...

12,768+156=12,924

Hopethishelpedyou-haveagooddaybrocya)

Victor collects data on the price of a dozen eggs at 8 different stores.median: $ 1.55
Find the lower quartile and upper quartile of
the data set.
lower quartile: $
upper quartile: S
?
$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80

Answers

Answer:

Lower quartile: $1.42

Upper quartile: $1.64

Step-by-step explanation:

The median is the middle value when all data values are placed in order of size.

The ordered data set is:

$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80

There are 8 data values in the data set, so this is an even data set.

Therefore, the median is the mean of the middle two values:

\implies \sf Median\;(Q_2)=(\$1.50+\$1.60)/(2)=\$1.55

Place "||" in the middle of the data set to signify where the median is:

$1.39 $1.40 $1.44 $1.50 ║ $1.60 $1.63 $1.65 $1.80

The lower quartile (Q₁) is the median of the data points to the left of the median.  As there is an even number of data points to the left of the median, the lower quartile is the mean of the the middle two values:

\implies \sf Lower\;quartile\;(Q_1)=(\$1.40+\$1.44)/(2)=\$1.42

The upper quartile (Q₃) is the median of the data points to the right of the median.  As there is an even number of data points to the right of the median, the upper quartile is the mean of the the middle two values:

\implies \sf Upper \;quartile\;(Q_1)=(\$1.63+\$1.65)/(2)=\$1.64

Answer:

to find the lower quartile and upper quartile of the given dataset, we need to first arrange the data in ascending order:

$1.39, 1.40, 1.44, 1.50, 1.60, 1.63, 1.65, 1.80$

The median of the dataset is given as $1.55$. Since there are an even number of data points, the median is the average of the two middle values, which in this case are $1.50$ and $1.60$.

Now, we need to find the lower quartile and upper quartile. The lower quartile is the median of the lower half of the data set, and the upper quartile is the median of the upper half of the data set.

The lower half of the dataset is $1.39, 1.40, 1.44, 1.50$. The median of this half is the average of the middle two values, which are $1.40$ and $1.44$.

Therefore, the lower quartile is $1.42$.

The upper half of the dataset is $1.60, 1.63, 1.65, 1.80$. The median of this half is the average of the middle two values, which are $1.63$ and $1.65$.

Therefore, the upper quartile is $1.64$.

Hence, the lower quartile of the dataset is $1.42$ and the upper quartile is $1.64$.

Which of these is the smallest number: A.0.452
B. 45%
C. 0.045

Answers

Answer:

C. 0.045

Step-by-step explanation:

a nonagon is a nine-sided polygon, if a regular nonagon was rotated about its center point, which of the following angels of rotation would not map the figure onto itself

Answers

The angles of rotation that would not map the figure onto itself will not be the multiple of 40 and this can be determined by evaluating the possible angle of each rotation.

Given :

  • A nonagon is a nine-sided polygon.
  • A regular nonagon was rotated about its center point.

To determine angels of rotation that would not map the figure onto itself, first, evaluate the possible angle of each rotation.

To determine the possible angle of each rotation the following calculation can be used:

The possible angle of eachrotation is the ratio of the complete rotation to the number of sides.

\rm Each \;Rotation = (360^\circ)/(9)

Each Rotation = 40^\circ

So, the angles of rotation that would not map the figure onto itself will not be the multiple of 40.

For more information, refer to the link given below:

brainly.com/question/22051318

Answer:

See Explanation

Step-by-step explanation:

Given

Shape: Nonagon

Required

Angles of rotation that would not map the shape on itself

Side of a nonagon is:

Sides = 9

and a complete rotation is:

Complete\ Rotation = 360\°

To start with, we calculate a possible angle of each rotation:

This is calculated by dividing the complete rotation by number of sides

Each\ Rotation = (360)/(9)

Each\ Rotation = 40

The question lacks option; so, it's difficult to give a specific answer.

However, I'll give a generalized answer

For the nonagon to map on itself, the angle must be a multiple of the calculated angle of rotation (40)

i.e.

Possible\ Angles = 40,80,120,160,200,240,280,320,360......

Any angle different from the above listed angles (or any other multiple of 40 not listed above) answers the question.

Could you help me solve y = x^2+6x+7?

Answers

Answer:

x ≈ -1.585786438 or x ≈ -4.414213562

y = 7

Step-by-step explanation:

This should be a parabola function.

Let y = 0 so we can find the two x-intercepts. (x1,0) and (x2,0)

x^2+6x+7 = 0

Using the quadratic equation, we get:

x ≈ -1.585786438 or x ≈ -4.414213562

Now we can find y by setting x = 0, so that we get a y-intercept. (0,y)

y = 0^2+6(0)+7

y = 7

1. 2x-y≤-6
2. 5x+4y ≥20

Answers

Answer

2x-y <or =-6

2x<or=-6+y

divide both sides by 2

x<or=1/2y+3

5(1/2y+3)+4y>or=20

5/2y+15+4y>or=20

5/2y+4y>or=20-15

13/2y>or=5

divide both sides by 2/13

y>or=10/13

2x-10/13<or=-6

2x<or=-6+10/13

2x<or=-68/13

divide both sides by 2

x< or =-34/13