Answer:

**Answer:**

**Apparent frequency of the bell to the observer is 546.12 Hz**

**Explanation:**

The frequency of train bell (frequency of source) = 505 Hz

The speed of train (observer) = 27.6 m/s

The speed of sound in the air is (velocity of sound) = 339 m/s

The apparent frequency of the bell to the observer is calculated as follows:

Apparent frequency of bell to the observer.

1. Two forces F~ 1 and F~ 2 are acting on a block of mass m=1.5 kg. The magnitude of force F~ 1 is 12N and it makes an angle of θ = 37◦ with the horizontal as shown in figure-1. The block is sliding at a constant velocity over a frictionless floor.(a) Find the value of the normal force on the block.(b) Find the magnitude of force F~2 that is acting on the block(c) Find the magnitude of force F~ 2 if the block accelerates with a magnitude of a = 2.5 m/s2 along the direction of F~ 2 .

" A sound wave moving through air consists of alternate regions of high pressure and low pressure. If the frequency of the sound is increased, what happens, if anything, to the distance between successive high-pressure regions, and why

Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 641Hz . You are standing between the speakers, along the line connecting them and are at a point of constructive interference.How far must you walk toward speaker B to move to reach the first point of destructive interference?Take the speed of sound to be 344 .

Bailey wants to find out which frozen solid melts the fastest: soda, ice, or orange juice. She pours each of the three liquids into the empty cubes of an ice tray, and then places the ice tray in the freezer overnight. The next day, she pulls the ice tray out and sets each cube on its own plate. She then waits and watches for them to melt. When the last part of the frozen liquid melts, she records the time.

An airplane is traveling 835 km/h in a direction 41.5 ∘ west of north. Find the components of the velocity vector in the northerly and westerly directions. How far north and how far west has the plane traveled after 2.20 h ?

" A sound wave moving through air consists of alternate regions of high pressure and low pressure. If the frequency of the sound is increased, what happens, if anything, to the distance between successive high-pressure regions, and why

Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 641Hz . You are standing between the speakers, along the line connecting them and are at a point of constructive interference.How far must you walk toward speaker B to move to reach the first point of destructive interference?Take the speed of sound to be 344 .

Bailey wants to find out which frozen solid melts the fastest: soda, ice, or orange juice. She pours each of the three liquids into the empty cubes of an ice tray, and then places the ice tray in the freezer overnight. The next day, she pulls the ice tray out and sets each cube on its own plate. She then waits and watches for them to melt. When the last part of the frozen liquid melts, she records the time.

An airplane is traveling 835 km/h in a direction 41.5 ∘ west of north. Find the components of the velocity vector in the northerly and westerly directions. How far north and how far west has the plane traveled after 2.20 h ?

**We are given:**

The tuning fork vibrates at 15660 oscillations per minute

**Period of one back-and forth movement:**

the given data can be rewritten as:

1 minute / 15660 oscillations

60 seconds / 15660 oscillations *(1 minute = 60 seconds)*

*dividing the values*

**0.0038 seconds / Oscillation**

**Therefore, one back and forth vibration takes 0.0038 seconds**

Express your answer in terms of the variable v0 and appropriate constants.

c) For what value of h does the collision occur at the instant when the first ball is at its highest point?

Express your answer in terms of the variable v0 and appropriate constants.

In this exercise we have to have knowledge about the **horizontal launch**, so we have to use the known formulas to find that:

a)

b)

c)

So we have to remember some famous** equations** like the position and **velocity** of an object moving in a constant, like this:

where:

- y = height at time t

- y0 = initial height

- v0 = initial velocity

- a = acceleration

- t = time

- v = velocity

a) When the balls collide, h1 = h2. Then,

Replacing in the **equation** of the **height **of the **first ball**:

b) that the **balls collide** at t = h/v0. Then:

c) The value of h for which the** collision** occurs at the instant when the first ball is at its **highest** point is the **maximum value**,Then:

See more about **velocity** at brainly.com/question/862972

Answer:

**Recoil velocity of cannon = 2.92 m/s**

Explanation:

By law of conservation of momentum, we have momentum of cannon = momentum of cannonball.

Mass of cannon = 1200 kg

Mass of cannon ball = 100 kg

Velocity of cannon ball = 35 m/s

We have, Momentum of cannon = momentum of cannon ball

1200 x v = 100 x 35

v =3500/1200 = 2.92 m/s

Recoil velocity of cannon = 2.92 m/s

The recoil **speed** of the cannon is 2.92 m/s.

To find the recoil speed of the cannon, we can use the conservation of momentum. The initial momentum of the cannon and cannonball system is zero since the cannon is at rest before firing. The final momentum is the sum of the momenta of the cannon and cannonball after firing. Using the equation:

**Initial momentum** = Final momentum

(mass of cannon) x (recoil speed of cannon) = (mass of cannonball) x (velocity of cannonball)

Plugging in the given values:

(1200 kg) x (recoil speed of cannon) = (100 kg) x (35 m/s)

Solving for the recoil speed of the cannon:

recoil speed of cannon = (100 kg x 35 m/s) / 1200 kg = 2.92 m/s

#SPJ3

**Answer:**

**Explanation:**

D its incorrect in edge

**Answer:**

D

**Explanation:**

The particles will move side to side over large areas

**Answer:**

t = 39.60 s

**Explanation:**

Let's take a careful look at this interesting exercise.

In the first case the two motors apply the force in the same direction

F = m a₀

a₀ = F / m

with this acceleration it takes t = 28s to travel a distance, starting from rest

x = v₀ t + ½ a t²

x = ½ a₀ t²

t² = 2x / a₀

28² = 2x /a₀ (1)

in a second case the two motors apply perpendicular forces

we can analyze this situation as two independent movements, one in each direction

in the direction of axis a, there is a motor so its force is F/2

the acceleration on this axis is

a = F/2m

a = a₀ / 2

so if we use the distance equation

x = v₀ t + ½ a t²

as part of rest v₀ = 0

x = ½ (a₀ / 2) t²

let's clear the time

t² = (2x / a₀) 2

we substitute the let of equation 1

t² = 28² 2

t = 28 √2

t = 39.60 s

Answer:

The detailed explanations is attached below

Explanation:

What is applied is the De brogile equation and the equation showing a relationship between Energy, speed of light and wavelength.

The explanation is as attached below.