4Ga + 3S2 → 2Ga2S3 1. How many grams of Gallium Sulfide would form if 20.5 moles of Gallium burned?


Answer 1





In this case, for the given chemical reaction, we can notice there is a 4:2 molar ratio between the burned moles of gallium and the yielded moles of gallium sulfide, therefore, we compute them as shown below:

n_(Ga_2S_3)=20.5molGa*(2molGa_2S_3)/(4molGa)=10.25mol Ga_2S_3

Then, by using the molar mass of gallium sulfide (235.64 g/mol), we directly compute the grams:

m_(Ga_2S_3)=10.25mol Ga_2S_3*(235.64gGa_2S_3)/(1molGa_2S_3) \n\nm_(Ga_2S_3)=2415.31gGa_2S_3

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Organisms with traits that help them survive and reproduce in their environment pass on those traits.

Changes in the environment cause organisms to change.
Organisms naturally select traits that help them survive and reproduce


In an ecosystem, organisms evolve to make changes to help them survive and reproduce in their environment.

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From which type of clouds do hail pellets form?



Hail pallets forms inside of cumulonimbus clouds


Answer: cumulonimbus hope it helps pls stay safe

Consider the reaction at 25 °C. H2O(l) ↔ H2O(g) ΔG° = 8.6 kJ/mol Calculate the pressure of water at 25 °C (Hint: Get K eq)



\boxed{\text{23.4 mmHg}}


H₂O(ℓ) ⟶ H₂O(g)

K_{\text{p}} = p_{\text{H2O}}

\text{The relationship between $\Delta G^(\circ)$ and $K_{\text{ p}}$ is}\n\Delta G^(\circ) = -RT \ln K_{\text{p}}


T = 25 °C

ΔG° = 8.6 kJ·mol⁻¹


T = (25 + 273.15) K = 298.15 K

\begin{array}{rcl}8600 & = & -8.314 * 298.15 \ln K \n8600 & = & -2478.8 \ln K\n-3.47 & = & \ln K\nK&=&e^(-3.47)\n& = & 0.0311\end{array}

Standard pressure is 1 bar.

p_{\text{H2O}} = \text{0.0311 bar} * \frac{\text{750.1 mmHg}}{\text{1 bar}} = \textbf{23.4 mmHg}\n\n\text{The vapour pressure of water at $25 ^(\circ)\text{C}$ is $\boxed{\textbf{23.4 mmHg}}$}

In both industry and research there are often times when one particular component of a mixture needs to be separated from a solution. Maybe it is a rare metal that is dissolved in a mixture of minerals. Maybe it is a particular protein from lysed plant cells. If the desired component is volatile, distillation could be used. But if the goal is to separate ions in solution, fractional precipitation is preferred.a. True
b. False



a. True


Distillation process is a process that is used to separate the components or the substances from the liquid mixtures by using selectively boiling and condensation.

While fractional precipitation is a process which separates the ions from solution based on the different solubilities.

Therefore, the answer is true.

The value of the Solubility Product Constant for lead phosphate is ____________Write the reaction that corresponds to this Ksp value.

_______(Aq,S,L) +_______(Aq,S,L) <-------->_______(Aq,S,L) +_______(Aq,S,L)

Ksp values are found by clicking on the "Tables" link.

Use the pull-down menus to specify the state of each reactant or product.

If a box is not needed leave it blank.


Answer: The reaction for the K_(sp) value of lead phosphate is given below and the value of solubility product for the same is 3.0\rightarrow 10^(-44)


Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is expressed as K_(sp)

The chemical formula of lead phosphate is Pb_3(PO_4)_2

The equation for the hydration of the lead phosphate is given as:

Pb_3(PO_4)_2(s)+H_2O(l)\rightarrow 3Pb^(2+)(aq.)+2PO_4^(3-)(aq.)

The solubility product of lead phosphate is 3.0\rightarrow 10^(-44). This means that it is highly insoluble in water as the solubility product is very very low.

Hence, the reaction for the K_(sp) value of lead phosphate is given above and the value of solubility product for the same is 3.0\rightarrow 10^(-44)

How do I name cycloalkanes?



{ \tt{aromatic \: alkanes}} \n  \n { \underline{ \blue{ \tt{becker⚜jnr}}}}

1. Determine the number of sides of the cyclic compound.

2. Use IUPAC theory, determine the functional group and its position.