Answer:

**Answer:**

speed when it reaches y = 4.00cm is

v = 14.9 g.m/s

**Explanation:**

**given**

q₁=q₂ =2.00 ×10⁻⁶

distance along x = 3.00cm= 3×10⁻²

q₃= 4×10⁻⁶C

mass= 10×10 ⁻³g

distance along y = 4×10⁻²m

r₁ = = = 3.61cm = 0.036m

r₂ = = = 5cm = 0.05m

electric potential V =

change in potential ΔV =

ΔV = , where 2.00μC

ΔV =

ΔV = 2 × 9×10⁹ × 2×10⁻⁶ ×

ΔV= 2.789×10⁵

= ΔV × q₃

ˣ 10×10⁻³ ×v² = 2.789×10⁵× 4 ×10⁻⁶

v² = 223.12 g.m/s

v = 14.9 g.m/s

Answer:

The **speed of the charge q₃** when it starts from rest at y = 2 cm and reaches y = 4 cm is; __v = 14.89 m/s __

We are given;

Charge 1; q₁ = 2.00 μC = 2 × 10⁻⁶ C

Charge 2; q₂ = 2.00 μC = 2 × 10⁻⁶ C

Distance of charge 1 along x = 3 cm = 3 × 10⁻² m

Distance of charge 2 along x = -3 cm = -3 × 10⁻² m

Charge 3; q₃ = +4.00 μC = 4 × 10⁻⁶ C

mass; m = 0.01 g

distance of charge 3 along y = 4 cm = 4 × 10⁻² m

q₃ starts from rest at y = 2 × 10⁻² m and reaches y = 4 × 10⁻² m.

Thus;

Distance of charge 1 from the initial position of q₃;

r₁ = √((3 × 10⁻²)² + ((2 × 10⁻²)²)

**r₁ = 0.0361 m**

Distance of charge 2 from the final position of q₃;

r₂ = √((3 × 10⁻²)² + ((4 × 10⁻²)²)

**r₂ = 0.05 m**

Now, **formula for electric potential** is;

**V = kq/r**

Where k = 9 × 10⁹ N.m²/s²

Thus,change in potential is;

**ΔV = V₁ - V₂**

Now, Net V₁ = 2kq₁/r₁

Net V₂ = 2kq₂/r₂

Thus;

ΔV = 2kq₁/r₁ - 2kq₂/r₂

ΔV = (2 × 9 × 10⁹)[(2 × 10⁻⁶/0.0361) - (2 × 10⁻⁶/0.05)]

**ΔV = 277229.92 V**

Now, **from conservation of energy**;

**½mv² = q₃ΔV**

Thus;

½ × 0.01 × v² = 4 × 10⁻⁶ × 277229.92

v² = 2 × 4 × 10⁻⁶ × 277229.92/0.01

v = √(221.783936)

**v = 14.89 m/s**

Read more about **point charges** at;brainly.com/question/13914561

A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm and (c) 0 cm.

How do you define 'heat' and 'temperature'

A screen is placed 1.20m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40cm wide-that is, the two first-order diffraction minima are separated by 1.40cm What is the distance between the two second-order minima?

The tension in a string is 15 N, and its linear density is 0.85 kg/m. A wave on the string travels toward the -x direction; it has an amplitude of 3.6 cm and a frequency of 12 Hz. What are the: a. Speed b. Wavelength of the wave? c. Write down a mathematical expression for the wave, substituting numbers for the variables

An auto repair technician who specializes in the installation, troubleshooting, and repair of heating and air conditioning systems is called a/an A. passenger comfort specialist. B. maintenance and light repair (MLR) specialist. C. service manager. D. electrical system specialist.

How do you define 'heat' and 'temperature'

A screen is placed 1.20m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40cm wide-that is, the two first-order diffraction minima are separated by 1.40cm What is the distance between the two second-order minima?

The tension in a string is 15 N, and its linear density is 0.85 kg/m. A wave on the string travels toward the -x direction; it has an amplitude of 3.6 cm and a frequency of 12 Hz. What are the: a. Speed b. Wavelength of the wave? c. Write down a mathematical expression for the wave, substituting numbers for the variables

An auto repair technician who specializes in the installation, troubleshooting, and repair of heating and air conditioning systems is called a/an A. passenger comfort specialist. B. maintenance and light repair (MLR) specialist. C. service manager. D. electrical system specialist.

**Answer:**

venus - 2

earth - 3

mars - 4

mercury - 1

**Answer:**

The answer is below

**Explanation:**

Let g = acceleration due to gravity = 9.81 m/s², x = half of the width of the crate, half of the height of the crate = 0.5 m, a = acceleration of crate, N = force raising the crate

The sum of moment is given as:

Sum of vertical forces is zero, hence:

Sum of horizontal force is zero, hence:

Solving equation 1, 2 and 3 simultaneously gives :

N = 447.8 N, a = 2.01 m/s², x = 0.25 m

x is supposed to be 0.3 m (0.6/2)

The crate would slip because x <0.3 m

**Answer:**

when u learn something new it goes to ur short term memory

**Answer:**

24 hours take earth to complete rotation

**Answer:**

Gemini

**Explanation:**

Zodiac Constellation or Sun sign is the constellation in which the Sun resides on the date of birth of a person. Throughout the year the Sun crosses across 12 constellations thus there are 12 Sun-signs. Though astronomically the Sun crosses across 13 constellations so there should be 13 zodiacs but most of the astrologers do not accept this. On the date of June 20, the Sagittarius which is a summer constellation and a zodiac can be seen high up in the sky in the night time. At this time the Sun will be in a constellation which is almost opposite to Sagittarius in the celestial sphere. That constellation is Gemini. Thus for a person born on 20 June, zodiac will be Gemini.

B 0.56 s

C 4.3s

D 70s

B 0.56 s is the **time period **of a twirlers baton.

**Centripetal acceleration** is defined as the property of the motion of an object which traversing a **circular path. **

Any object that is moving in a circle and has an **acceleration vector** pointed towards the center of that circle is known as **Centripetal acceleration.**

The** centripetal acceleration** is given by:

a = 4π²R/T²

Given values are:

a = 47.8 m/s²

D = 0.76 m so , R = 0.76/2 = 0.38m

Using this formula,

47.8*T² = 4π² x0.38

T² =

T = 0.56 s

Therefore,

A twirlers baton is 0.76 m long and spins around its center. The end of the baton has a **centripetal acceleration** of 47.8 m/s2 which have **time period of **0.56 s.

Learn more about** Centripetal acceleration** here:

#SPJ5

.

**Answer:**

C. 4.3 seconds

**Explanation:**