# the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$and wages at 120$ if the cost of raw materials and overheads are increased by 11% and 20% respectively while wages are decreased by 15% find the percentage increase or decrease in the production cost of the printer

The percentage increase in the production cost of the printer is 3%.

Step-by-step explanation:

We are given that the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$and wages at 120$.

Also, the cost of raw materials and overheads are increased by 11% and 20% respectively while wages are decreased by 15%.

Cost of raw material = $100 Cost of overheads =$80

Cost of wages = $120 So, the total cost of the printer =$100 + $80 +$120

= $300 Now, the increase in the cost of raw material =$100 + 11% of $100 = =$100 + $11 =$111

The increase in the cost of overheads = $80 + 20% of$80

=

= $80 +$16 = $96 The decrease in the cost of wages =$120 - 15% of $120 = =$120 - $18 =$102

So, the new cost of a printer = $111 +$96 + $102 =$309

Now, the percentage increase in the production cost of the printer is given by;

% increase =

=

=  3%

Hence, the percentage increase in the production cost of the printer is 3%.

## Related Questions

1/6 hdshgsjehegebdbdjz

Read the information in the box below.Last year during the hurricane season, the amount of rain that fell on the Texas Gulf Coast in October was 14 inches, which was 312times more than the rainfall during September of the same year. How much rain fell during the month of September?

Rebecca tried to solve the problem but made a mistake in her calculations. You must analyze Rebecca's work, identify the error, and then correctly solve the problem. Then, create a model to justify your thinking.
Rebecca's Math Calculations
Step 1: 14×312
Step 2: 141×72
Step 3: 982=49
Solution: In September, 49 inches of rain fell.

Be sure to –
Identify the error that the student made
Create a pictorial model that represents the problem situation and justifies your identification of the error and its solution
Explain how the model justifies the identified error and how to correct it

4 inches

Step-by-step explanation:

Given that :

Amount of Rainfall in October = 14 inches

Amount of Rainfall in October = 3 1/2 times more than Rainfall during September

How much rain fell.during September :

The problem is a division problem ;

Since the amount of Rainfall in October is greater, then obtaining the amount of Rainfall in September requires dividing The amount of Rainfall in October by the number of times it is more than the September rainfall;

If multiplication is applied, then tbe value obtained will be greater than 14 inches. Which makes no sense since, the Rainfall in October is much greater than that in September.

14 inches ÷ 3 1/2

14 ÷ 7/2

14 * 2 / 7

= 28 / 7

= 4 inches

Hence, the amount of Rainfall in September is 4 inches

46

Step-by-step explanation:

Determine the wavelengths of all the possible photons that can be emitted from the n = 5 state of a hydrogen atom.

Wavelengths of all possible photons are;

λ1 = 9.492 × 10^(-8) m

λ2 = 1.28 × 10^(-6) m

λ3 = 1.28 × 10^(-6) m

λ4 = 4.04 × 10^(-6) m

Step-by-step explanation:

We can calculate the wavelength of all the possible photons emitted by the electron during this transition using Rydeberg's equation.

It's given by;

1/λ = R(1/(n_f)² - 1/(n_i)²)

Where;

λ is wavelength

R is Rydberg's constant = 1.0974 × 10^(7) /m

n_f is the final energy level = 1,2,3,4

n_i is the initial energy level = 5

At n_f = 1,.we have;

1/λ = (1.0974 × 10^(7))(1/(1)² - 1/(5)²)

1/λ = 10535040

λ = 1/10535040

λ = 9.492 × 10^(-8) m

At n_f = 2,.we have;

1/λ = (1.0974 × 10^(7))(1/(2)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.21)

1/λ = 2304540

λ = 1/2304540

λ = 4.34 × 10^(-7) m

At n_f = 3, we have;

1/λ = (1.0974 × 10^(7))(1/(3)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.07111)

1/λ = 780373.3333333334

λ = 1/780373.3333333334

λ = 1.28 × 10^(-6) m

At n_f = 4, we have;

1/λ = (1.0974 × 10^(7))(1/(4)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.0225)

1/λ = 246915

λ = 1/246915

λ = 4.04 × 10^(-6) m

Write a problem that uses a fraction greater than 1?

3/2+3/2=3. Does this help? If not then I sincerely apologize- ^^". Please inform me if this is incorrect or not helpful

Step-by-step explanation:

Rounding (3.762) to the nearest tenths place is

3.8

Step-by-step explanation:

Rounding to the nearest tenth means that eliminating the digits in the hundredths and thousandths place and if the hundredths place is greater than 5, then you also have to add a 1 to the tenths place.

So, The number becomes:

=> 3.8 (Hundredths place have 6 which is greater than 5)

3.8

Step-by-step explanation:

pls mark as brainliest

Consider the sequence below. 3, 1, 1/3, 1/9,...

select the explicit function which defines the sequence.

A.) f(n) = 1/3 • 2^(n - 1)

B.) f(n) = 2 • (1/3)^(n - 1)

C.) f(n) = 1/3 • 3^(n - 1)

D.) f(n) = 3 • (1/3)^(n - 1)

The explicit formula that defines the sequence is

EXPLANATION

The given sequence is

The first term of this sequence is

We can find the common ratio by expressing a subsequent term over a previous term and simplifying it.

The common ratio is

The formula for finding the nth term of the given geometric sequence is given by,

We now substitute the value of the first term and the common ratio in to the above formula to obtain,

The correct answer is option D.