Which is an example of a situation that is in equilibrium?A. The amount of air in a room increases quickly when the door is
opened.
B. The amount of money in a bank account never changes
C. The amount of water in a cup decreases as it evaporates
D. A flower slowly grows taller​

Answers

Answer 1
Answer:

Answer:B the amount of money in a bank account never changes.

Step-by-step explanation:

Answer 2
Answer:

Answer:

B. The amount of money in a bank account never changes.

Step-by-step explanation:

Equilibrium is achieved when the state of a reversible reaction of opposing forces cancel each other out. While in a state of equilibrium, the competing influences are balanced out. Imagine a cup with a hole in it being filled with water from a tap. The level of water in this cup would stay the same if the rate at which the water that flows inside is the same as the water that flows outside. Option B will be the correct answer because the amount of money going into the account is at the same rate of money coming out of the account.


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. Roger uses his truck to plow parking lots when it snows. He wants to find a model to predict the number of service calls he can expect to receive based on how much snow falls during a storm. Snow Plow Service Based on the collected data shown in the scatterplot, he uses the linear model . According to this model, c(s)=0.8s+0.29about how many service calls will Roger have in the next snow storm if 4.7 inches of snow fall? Round to the nearest tenth if necessary

Write a system of equations to describe the situation below, solve using substitution, and fillin the blanks.Nora, an office manager, needs to find a courier to deliver a package. The first courier she isconsidering charges a fee of $14 plus $5 per kilogram. The second charges $15 plus $4 perkilogram. Nora determines that, given her package's weight, the two courier services areequivalent in terms of cost. What is the weight? How much will it cost?

Answers

The first courier service cost is;

5x+14

Where, x is the number of kilograms delivered;

The second courier service cost is;

4x+15

Equating it, we have;

\begin{gathered} 5x+14=4x+15 \n x=1 \end{gathered}

Thus, the weight that will result in equal cost is 1 kilogram.

And the cost is 5( 1 )+14 = $19

A triangular prism has a base with a height of 5 cm and a base with a width of 4 cm. The prism has a height of 10 cm. What is the volume of the prism?​

Answers

Answer:

The volume of the triangular prism is 100 cubic centimeters.

A square is inscribed in a circle . If the area of the square is 9 inch square what is the ratio of the radius of the circle to the side of the square.

Answers

Answer:

  (√2)/2

Step-by-step explanation:

The ratio of the radius of the circle to the side of the inscribed square is the same regardless of the size of the objects.

The radius of the circle is half the length of the diagonal of the square. For simplicity, we can call the side of the square 1, so its diagonal is √(1²+1²) = √2 by the Pythagorean theorem. The radius is half that value, so is (√2)/2. The desired ratio is this value divided by 1.

Scaling up our unit square to one with a side length of 3 inches, we have ...

  radius/side = ((3√2)/2) / 3 = (√2)/2

_____

A square with a side length of 3 inches will have an area of (3 in)² = 9 in².

6)Do these calculations and use proper significant figures:
26 X 0.02584 =
15.3 +1.1 =
782.45 X 3.5 =
63.258 + 734.2 =

Answers

Answer:

0.67184

16.4

2738.575

797.458

Answer:

0.67184

16.4

2738.575

847.458

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second). (a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

Answers

Answer:

The probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day is P(Y>190)=\frac{1}{e^{(19)/(10)}}\approx 0.1496

Step-by-step explanation:

Let Y be the water demand in the early afternoon.

If the random variable Y has density function f (y) and a < b, then the probability that Y falls in the interval [a, b] is

P(a\leq Y \leq b)=\int\limits^a_b {f(y)} \, dy

A random variable Y is said to have an exponential distribution with parameter \beta > 0 if and only if the density function of Y is

f(y)=\left \{ {{(1)/(\beta)e^{-(y)/(\beta) }, \quad{0\:\leq \:y \:\leq \:\infty}   } \atop {0}, \quad elsewhere} \right.

If Y is an exponential random variable with parameter β, then

mean = β

To find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day, you must:

We are given the mean = β = 100 cubic feet per second

P(Y>190)=\int\limits^(\infty)_(190) {(1)/(100)e^(-y/100) } \, dy

Compute the indefinite integral \int (1)/(100)e^{-(y)/(100)}dy

(1)/(100)\cdot \int \:e^{-(y)/(100)}dy\n\n\mathrm{Apply\:u \:substitution}\:u=-(y)/(100)\n\n(1)/(100)\cdot \int \:-100e^udu\n\n(1)/(100)\left(-100\cdot \int \:e^udu\right)\n\n(1)/(100)\left(-100e^u\right)\n\n\mathrm{Substitute\:back}\:u=-(y)/(100)\n\n(1)/(100)\left(-100e^{-(y)/(100)}\right)\n\n-e^{-(y)/(100)}

Compute the boundaries

\int _(190)^(\infty \:)(1)/(100)e^{-(y)/(100)}dy=0-\left(-\frac{1}{e^{(19)/(10)}}\right)

\int _(190)^(\infty \:)(1)/(100)e^{-(y)/(100)}dy=\frac{1}{e^{(19)/(10)}}\approx 0.1496

The probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day is P(Y>190)=\frac{1}{e^{(19)/(10)}}\approx 0.1496

2(x – 9) = 10x + 11
Help

Answers

Answer:

exact form: -28/8

decimal form: -3.625

mixed number form: -3 5/8

Answer:

x = -3.625

Step-by-step explanation: