Answer:

**Answer:**

correct answer is 1 and 3

**Explanation:**

In direct measurement with an instrument, the precision or absolute error of the instrument is given by its appreciation, in this case we see that the measurements have two decimal places, so the appreciation of the instrument must be 0.01 cm

Based on this appreciation, the valid measurements are 5.52 and 5.5.

the other two measurements have errors much higher than the assessment of the instrument, for which there must have been some errors in the measurement.

The correct answer is 1 and 3

Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen a distance of 3.00 m from the slits. The first-order bright fringe is a distance of 4.84 mm from the center of the central bright fringeFor what wavelength of light will thefirst-order dark fringe be observed at this same point on thescreen?Express your answer in micrometers(not in nanometers).

Which one A, B, C, D or the last one?

why does the value of capacitance of a capacitor increases in parallel combination but not in series??

A UHF television loop antenna has a diameter of 11 cm. The magnetic field of a TV signal is normal to the plane of the loop and, at one instant of time, its magnitude is changing at the rate 0.16 T/s. The magnetic field is uniform. What emf is induced in the antenna

18. Wind speed on Earth is reduced by which?A. temperatureB. frictionC. weatherD. convergence

Which one A, B, C, D or the last one?

why does the value of capacitance of a capacitor increases in parallel combination but not in series??

A UHF television loop antenna has a diameter of 11 cm. The magnetic field of a TV signal is normal to the plane of the loop and, at one instant of time, its magnitude is changing at the rate 0.16 T/s. The magnetic field is uniform. What emf is induced in the antenna

18. Wind speed on Earth is reduced by which?A. temperatureB. frictionC. weatherD. convergence

Statements that are right as regards **oscillation **are:

A. The decrease in the** amplitude** of an oscillation caused by dissipative forces is called **damping.**

B. The increase in amplitude of an **oscillation b**y a driving force is called **forced oscillation.**

C. In a mechanical system, the amplitude of an oscillation diminishes with time unless the lost **mechanical energy **is replaced.

D. An oscillation that is maintained by a driving force is called** forced oscillation.**

**Amplitude**can be regarded as**magnitude**of change that is been experienced by**oscillating variable**with each oscillation.

- When there is a decrease in the
**amplitude**of an oscillation as a result**dissipative forces**, then it is regarded as**damping.**

- When there is increase in
**amplitude**of an oscillation as a result of**driving force**then it is termed**forced oscillation.**

Therefore, the options are correct.

Learn more at:

**Answer:**

right A, B, C, D

**Explanation:**

They ask which statements are true

A) Right. The decrease in amplitude is due to the dissipation of energy by friction and is called damping

B) Right. In resonant processes the amplitude of the oscillation increases, being a forced oscillation

C) Right. In a system with energy loss, the amplitude must decrease, therefore energy must be supplied to compensate for the loss.

D) Right. It is a resonant process the driving force keeps the oscillation of the system

**Answer:**

**velocity of the river is equal to 0.56 m/s**

**Explanation:**

given,

velocity of swimmer w.r.t still water = 1 m/s

width of river = 73 m

he arrives to the point = 41 m

** t = 73 s **

=

**= 0.56 m/s **

**velocity of the river is equal to 0.56 m/s**

**Answer:**

06 Hours

**Explanation:**

As per the details given in the question it self, the neutron star X-1 is revolving around its companion star. The orbital period is 1.7 years which means it will complete the revolution in 1.7 years. During the movement in the orbit we will be able to detect the x-rays except for the time when it goes behind the companion star and eclipsed by it as seen from Earth.

Since the x-rays disappear completely for around 6 hours. This clearly means that eclipse period is 06 hours.

(A) m3

(B) 1.8 m3

(C) 3.6 m3

(D) 6 m3

(E) 9 m3

**Answer:**

(C)

**Explanation:**

=

Since the object is a solid sphere, the equation for rotational inertia is:

The provided question seems to have a discrepancy as the calculated value of rotational inertia for a spherical object with a given mass-radius relationship is 4.5M³, which does not match any of the supplied answer choices.

The question is asking for the correct expression for the rotational inertia of a spherically shaped object with mass distribution given by the radius as a function of mass (*r = km²* where *k = 3*). The rotational inertia, or moment of inertia, for a solid sphere is given by the formula ⅒MR², where *M* is the mass of the sphere, and *R* is its radius. Considering that *R* is defined by *r = km²*, we substitute *R* with *km²* in the formula:

I = ⅒M(km²)² = ⅒Mk²m⁴ = ⅒Mk²M²

Since *k = 3*, we further simplify the expression:

I = ⅒M(3M)² = ⅒(3²)M³ = ⅒ × 9M³ = 4.5M³

However, none of the options (A) to (E) match the value 4.5M³, which indicates there may be an error in the supplied options or an error within the initial assumptions or question parameters. It's important to recheck the given data and the calculation steps to ensure accuracy. If the question and the parameters are indeed accurate as stated, additional information or clarification would be necessary.

**Answer:**

**3.65 x mass**

**Explanation:**

Given parameters:

Time = 20s

Initial velocity = 0m/s

Final velocity = 73m/s

Unknown:

Force the ball experience = ?

Solution:

To solve this problem, we apply the equation from newton's second law of motion:

F = m

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

So;

F = m ( ) = **3.65 x mass**

To calculate the force experienced by the ball to accelerate from rest to 73 m/s, use Newton's **second law of motion.**

To calculate the **force** experienced by the ball to accelerate from rest to 73 m/s, we can use Newton's second law of motion, which states that force equals mass times acceleration (F = m * a).

Since the ball starts from rest, its** initial velocity **(vi) is 0 m/s. The final velocity (vf) is 73 m/s. The time (t) taken for the impact is given as 2 x 10 seconds. So, the **acceleration** (a) can be calculated using the formula a = (vf - vi) / t.

Substituting the given values into the equation, we have a = (73 - 0) / (2 x 10) = 3.65 m/s^2.

Now, we can find the force (F) using the formula F = m * a. If the mass of the ball is known, we can substitute it into the equation to find the force experienced by the ball.

#SPJ3

7 true

8 false

9 false

10 false

11 false

12 true

13 true

hope this helps!