How many hours are there in 360 mins​

Answers

Answer 1
Answer:

Answer: 6 hours

Step-by-step explanation:

You have to divide 360 by 60 minutes.

Answer 2
Answer:

Answer:

There are 360 minutes in 6 hours.

Hope this helps :)


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If f(x) = -1/x, then f'(x) = 1/x^2. Theorem seems to suggest that the integral from -1 to 1 of 1/x^2 dx would equal f(1) - f(-1) = -1 -1 = -2. But 1/x^2 is a positive function and so its integral over [-1,1] should be positive. What is wrong here?

Answers

Answer:

The flaw is at x=0 where the function is not defined

Step-by-step explanation:

For any function we have

F(x)=\int f(x)dx

The integral can be evaluated only if the function f(x) is defined in the interval [a,b] in which this integral is evaluated

In our our case function f(x) is not defined at x=0 in the interval [-1,+1] thus this results in the flaw that we have obtained in the reasoning

Derive cos (2x - 1)​

Answers

Answer:

Step-by-step explanation:

I believe that what you want to do here is to "differentiate" cos (2x - 1).

We must use the rule for differentiating cos x and also the chain rule, since the input to cos x here is (2x - 1).

(d/dx) is the derivative operator.

(d/dx) (cos x) = -sin x

(d/dx) cos (2x - 1) = - sin (2x - 1) * (d/dx) (2x -1) = -sin (2x - 1)(2) = -2sin (2x - 1)

lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2:131F2:131 white squash, 3434 yellow squash, and 1010 green squash. Are these data consistent with a 12:3:112:3:1 dominant epistatic model of genetic inheritance( white being dominant)? The null hypothesis for the chi‑square goodness‑of‑fit test is

Answers

Here is the full question:

When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.

Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?

The null hypothesis for the chi-square goodness-of-fit test is                

Answer:

The null  hypothesis for the chi-square goodness-of-fit test is :

\mathbf{H_o:p_(white) = (12)/(16), p_(yellow) = (3)/(16); p_(green) = (1)/(16)           }

Step-by-step explanation:

The objective of this question is to state the null hypothesis for the  chi-square goodness-of-fit test.

Given that:

There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1

The total number of these color traits associated with this model = 12 + 3 + 1 = 16

Thus ;

The null  hypothesis for the chi-square goodness-of-fit test is :

\mathbf{H_o:p_(white) = (12)/(16), p_(yellow) = (3)/(16); p_(green) = (1)/(16)           }

In a relay race, Jill runs 250 meters in 1.5 minutes. She hands the baton to John, who walks for 3 minutes at a rate of 70 meters per minute. Finally, Suzy sprints the last 100 meters in 15 seconds. What distance is traveled in this relay

Answers

9514 1404 393

Answer:

  560 m

Step-by-step explanation:

Jill's distance is given as 250 m.

John's distance can be computed as ...

  distance = speed × time = (70 m/min)(3 min) = 210 m

Suzy's distance is given as 100 m.

Then the total distance is ...

  250 m + 210 m + 100 m = 560 m

The distance traveled is 560 m in this relay.

Lola used 2 1/2 ink cartridges while her friends used 1 3/4 ink cartridges. How many more ink cartridges did Lola use than her friends

Answers

Answer:

Lola used 3/4 more ink cartridges than her friends

Step-by-step explanation:

What is the probability that a randomly drawn hand of four cards contains all black cards or all face cards? The probability is 6 Round to four decimal places as needed.)

Answers

Answer: 0.05699

Step-by-step explanation:

The total number of cards in a deck = 52

The total number of black cards = 26

Then ,\text{P(Black)}=(C(26,4))/(C(52,4))=0.00182842367\approx0.00183

The total number of face cards = 12

Then , \text{P(Face)}=(C(12,4))/(C(52,4))\approx0.05522

The number of cards that are black and face cards = 6

Then , \text{P(Black and Face )}=(C(6,4))/(C(52,4))\approx0.00006

Then , the probability that a randomly drawn hand of four cards contains all black cards or all face cards is given by :-

\text{P(Black or Face)}=\text{P(Black)+P(Face)-P(Black and Face)}\n\n\Rightarrow\ \text{P(Black or Face)}=0.00183+0.05522-0.00006\n\n\Rightarrow\ \text{P(Black or Face)}=0.05699