Access control lists (ACLs) are used to permit and deny traffic in an IP router.A. True
B. False

Answers

Answer 1
Answer:

Answer:

A. True

Explanation:

  • ACLs are the packet filters of the network. They may restrict, allow or deny traffic necessary for safety.
  • When setting rules for ACLs, all traffic flow depends on the point of view of the router's interface (not other networks).
  • ACL allows you to control the flow of packets for a single or group of IP addresses or for protocols such as TCP, UDP, ICMP and so on.
  • Invalid interface or accidental change of source / destination may adversely affect ACL network

Related Questions

Explain how signal detection theory can be used to analyze web site reading and searching. Based on this analysis, provide three suggestions for your favorite search engine or web site that includes search.
This program outputs a downwards facing arrow composed of a rectangle and a right triangle. The arrow dimensions are defined by user specified arrow base height, arrow base width, and arrow head width.(1) Modify the given program to use a loop to output an arrow base of height arrowBaseHeight. (1 pt)(2) Modify the given program to use a loop to output an arrow base of width arrowBaseWidth. Use a nested loop in which the inner loop draws the *’s, and the outer loop iterates a number of times equal to the height of the arrow base. (1 pt)(3) Modify the given program to use a loop to output an arrow head of width arrowHeadWidth. Use a nested loop in which the inner loop draws the *’s, and the outer loop iterates a number of times equal to the height of the arrow head. (2 pts)(4) Modify the given program to only accept an arrow head width that is larger than the arrow base width. Use a loop to continue prompting the user for an arrow head width until the value is larger than the arrow base width. (1 pt)while (arrowHeadWidth <= arrowBaseWidth) {// Prompt user for a valid arrow head value}Example output for arrowBaseHeight = 5, arrowBaseWidth = 2, and arrowHeadWidth = 4:Enter arrow base height:5Enter arrow base width:2Enter arrow head width:4********************This is what I have:import java.util.Scanner;public class DrawHalfArrow{public static void main(String[] args){Scanner scnr = new Scanner(System.in);int arrowBaseHeight = 0;int arrowBaseWidth = 0;int arrowHeadWidth = 0;System.out.println("Enter arrow base height:");arrowBaseHeight = scnr.nextInt();System.out.println("Enter arrow base width:");arrowBaseWidth = scnr.nextInt();while (arrowHeadWidth >= arrowBaseWidth){System.out.println("Enter arrow head width:");arrowHeadWidth = scnr.nextInt();} // Draw arrow base (height = 3, width = 2)for(int i=0; i < arrowBaseHeight; ++i){for(int j=0; j < arrowBaseWidth; ++j){System.out.print("*");}System.out.println();}// Draw arrow head (width = 4)for(int i=0; i < arrowHeadWidth; ++i){for(int j=0; j < arrowHeadWidth-i; ++j){System.out.print("*");}System.out.println();}return;}}
Discuss the relationship of culture and trends?
Which statement prints "hi" on the screen?(a) puts("hi");(b) put "hi";(c) puts "hi";(d) none of the above
Using for loop . Input an integer and identify whether it's EVEN OR ODD ( without using modulo operator )using only . C++ programming

When you move or size a control in the Form Designer, Visual Studio automatically adjusts the ________________ that specify the location and size of the control.

Answers

Answer:

When you move or size a control in the Form Designer, Visual Studio automatically adjusts the properties that specify the location and size of the control.

Broker Ray is closely acquainted with the Subdivision Heights neighborhood of his town. Over the year, Ray has made it a practice to contact homeowners in person and also to send them quarterly mailings. This method of finding listings is known as:

Answers

No multiple choice?

Give a non-network example of hierarchical addressing and discuss how it reduces the amount of work needed in physical delivery. Do not use the postal service, or the telephone network..

Answers

HIERARCHICAL EXAMPLE.

Many examples of hierarchical addressing exists which reduces the amount of work needed in locating or in delivering,and one of such examples is the 'sorting of books in a library'.

Looking at a library having books kept randomly on any stack and shelf,it will make it difficult finding any book easily or locating any book of a specific genre.so,to avoid such problems, books are orderly sorted in a library and each book is given or has a unique identification number.

Books that has the same or related subject are kept in the same stack and books of the same genre are also kept together.

In a library,there are many stacks having different rows.

Take for an example; If one need to find a book on computer network,the user can search for the books in stacks of books that are related to Computer Science instead of searching the whole library for the book.

So,the hierarchical addressing saves lots of work and also time required for searching a specific book in the library.

Which of the following describes a 2×4 decoder? A)-Two AND gates, four Inverters, and one OR gate.
B)-Two Inverters, four AND gates, and one OR gate.
C)-Two OR gates, four AND gates, and one Inverter.
D)-Two Inverters, four OR gates, and one AND gate.
E)-Two Inverters, four AND gates, and no OR gates.

Answers

Answer:

A decoder is a circuit which has n inputs and 2n outputs, and outputs 1 on the wire corresponding to the binary number represented by the inputs. For example, a 2-4 decoder might be drawn like this:

and its truth table (again, really four truth tables, one for each output) is:

i1  i0  d3  d2  d1  d0

0 0 0 0 0 1

0 1 0 0 1 0

1 0 0 1 0 0

1 1 1 0 0 0

Explanation:

The following circuit generates all four minterms from two inputs, and implements the 2-4 decoder.

Subtract (100000)2 from (111)2 using 1s and 2s complement method of subtraction​

Answers

Answer:

-11001

Explanation:

The following steps are performed in order to perform subtraction of the given binary numbers:

Step 1:

Find 2’s complement of the subtrahend. The subtrahend here is 100000

100000

First take 1's complement of 100000

1's complement is taken by inverting 100000

1's complement of 100000 = 011111

Now takes 2's complement by adding 1 to the result of 1's complement:

011111 + 1 = 100000

2's complement of 100000 = 100000

Step 2:

Add the 2's complement of the subtrahend to the minuend.

The number of bits in the minuend is less than that of subtrahend. Make the number of bits in the minuend equal to that of subtrahend by placing 0s in before minuend. So the minuend 111 becomes:

000111

Now add the 2's complement of 100000 to 000111

   0 0 0 1  1  1

+   1 0 0 0 0 0

    1 0 0 1  1  1

The result of the addition is :

 1 0 0 1  1  1

Step 3:

Since there is no carry over the next step is to take 2's complement of the sum and place negative sign with the result as the result is negative.

sum =   1 0 0 1  1  1

2's complement of sum:

First take 1's complement of 1 0 0 1  1  1

1's complement is taken by inverting 1 0 0 1  1  1

1's complement of 1 0 0 1  1  1 = 0 1 1 0 0 0

Now takes 2's complement by adding 1 to the result of 1's complement:

0 1 1 0 0 0 + 1 = 0 1 1 0 0 1

Now place the minus sign with the result of 2's complement:

- 0 1 1 0 0 1

Hence the subtraction of two binary numbers (100000)₂ and (111)₂  is

(-011001)₂

This can also be written as:

(-11001)₂

Residential and business customers are paying different rates for water usage. Residential customers pay $0.005 per gallon for the first 6000 gallons. If the usage is more than 6000 gallons, the rate will be $0.007 per gallon after the first 6000 gallons. Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0.008 per gallon after the first 8000 gallons. For example, a residential customer who has used 9000 gallons will pay $30 for the first 6000 gallons ($0.005 * 6000), plus $21 for the other 3000 gallons ($0.007 * 3000). The total bill will be $51. A business customer who has used 9000 gallons will pay $48 for the first 8000 gallons ($0.006 * 8000), plus $8 for the other 1000 gallons ($0.008 * 1000). The total bill will be $56. Write a program to do the following. Ask the user which type the customer it is and how many gallons of water have been used. Calculate and display the bill.

Answers

Answer:

// here is program in Java.

// import package

import java.util.*;

// class definition

class Main

{

   // main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

   // variable

   int gall;

   double cost=0;

       // object to read value from user

    Scanner scr=new Scanner(System.in);

     // ask user to enter type

    System.out.print("Enter customer type  (R for residential or B for business ):");

    // read type of customer

       char t=scr.next().charAt(0);

       if(t=='r'||t=='R')

       {

           System.out.print("enter the number of gallons:");

           //read number of gallons

           gall=scr.nextInt();

           // if number of gallons are less or equal to 6000

           if(gall<=6000)

            {

           // calculate cost

           cost=gall*0.007;

           // print cost

           System.out.println("total cost is: "+cost);

             }

           else

           {

           // calculate cost

            cost=(6000*0.005)+((gall-6000)*0.007);

            // print cost

            System.out.println("total cost is: "+cost);

           }

       }

       else if(t=='b'||t=='B')

       {

           System.out.print("enter the number of gallons:");

           //read number of gallons

           gall=scr.nextInt();

           // if number of gallons are less or equal to 8000

           if(gall<=8000)

            {

           // calculate cost

           cost=gall*0.006;

           // print cost

           System.out.println("total cost is: "+cost);

             }

           else

           {// calculate cost

            cost=(8000*0.006)+((gall-8000)*0.008);

            // print cost

            System.out.println("total cost is: "+cost);

           }

       }

   }catch(Exception ex){

       return;}

}

}

Explanation:

Ask user to enter the type of customer and assign it to variable "t" with scanner object.If the customer type is business then read the number of gallons from user and assign it to variable "gall". Then calculate cost of gallons, if   gallons are less or equal to 8000 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and   for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 6000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter customer type  (R for residential or B for business ):r

enter the number of gallons:8000

total cost is: 44.0