Evaluate k - m if k = 8, m = -7, and p = -10.

Answers

Answer 1
Answer:

Answer:15

8-(-7)=8+ 7=15 BECAUSE -(-7) = +7

Step-by-step explanation:

BECAUSE -(-7) = +7 SO THE PROBLEM CHANGES TO 8+7=15

P=10 HAS NOTHING TO DO WITH THE FORMULA. K-M=?


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Question 3 (1 point)What is the value of x in the equation 8+4 = 2(x - 1)?
a
11/2
b
13/2
c
5
d
7

Answers

Answer:

D. 7

Step-by-step explanation:

(8+4) = 2(x-1) multiply (x-1) by 2

(8+4) = 2x-2 add 8 and 4

12 = 2x-2 add 2 on both sides

14 = 2x divide both sides by 2

7 = x

Answer is D

12 = 2x - 2

14 = 2x

14/2 = x

7 = x

A certain genetic condition affects 8% of the population in a city of 10,000. Suppose there is a test for the condition that has an error rate of 1% (i.e., 1% false negatives and 1% false positives). Consider the values that would complete the table below.

Has condition Does not have condition totals

Test positive

Test negative

Totals

What is the probability (as a percentage) that a person has the condition if he or she tests positive? (Round your answer to one decimal place.)

Answers

Solution:

Population in the city= 10,000

As genetic condition affects 8% of the population.

8 % of 10,000

=(8)/(100)* 10,000=800

As, it is also given that, there is an error rate of 1% for condition (i.e., 1% false negatives and 1% false positives).

So, 1% false negatives means out of 800 tested who are found affected , means there are chances that 1% who was found affected are not affected at all.

So, 1% of 800 =(1)/(100)* 800=8

Also,  1% false positives means out of 10,000 tested,[10,000-800= 9200] who are found not affected , means there are chances that 1% who was found not affected can be affected also.

So, 1% of 9200 =(1)/(100)* 9200=92

1. Has condition Does not have condition totals  = 800

2. Test positive =92

3. Test negative =8

4. Total =800 +92 +8=900

5. Probability (as a percentage) that a person has the condition if he or she tests positive= As 8% are found positive among 10,000 means 9200 are not found affected.But there are chances that out of 9200 , 1% may be affected

=\frac{\text{1 percent of 9200}}{9200}\n\n ((1)/(100)* 9200)/(9200)=(92)/(9200)\n\n =0.01

that is Probability equal to 0.01 or 1%.

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. The numbers y of cell sites from 1985 through 2011 can be modeled byy = 269573/1+985e^-0.308t where t represents the year, with t = 5 corresponding to 1985. Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006.

Answers

Answer:

(a) 3178

(b) 14231

(c) 33152

Step-by-step explanation:

Given

y = (269573)/(1+985e^(-0.308t))

Solving (a): Year = 1998

1998 means t = 8 i.e. 1998 - 1990

So:

y = (269573)/(1+985e^(-0.308*8))

y = (269573)/(1+985e^(-2.464))

y = (269573)/(1+985*0.08509)

y = (269573)/(84.81365)

y = 3178 --- approximated

Solving (b): Year = 2003

2003 means t = 13 i.e. 2003 - 1990

So:

y = (269573)/(1+985e^(-0.308*13))

y = (269573)/(1+985e^(-4.004))

y = (269573)/(1+985*0.01824)

y = (269573)/(18.9664)

y = 14213 --- approximated

Solving (c): Year = 2006

2006 means t = 16 i.e. 2006 - 1990

So:

y = (269573)/(1+985e^(-0.308*16))

y = (269573)/(1+985e^(-4.928))

y = (269573)/(1+985*0.00724)

y = (269573)/(8.1314)

y = 33152 --- approximated

When is the function decreasing?A. (15, 40)
B. (30, 55)
C. (60, -40)
D. (40, 60)​

Answers

I believe it is C. (60, -40)

A photocopier can print 12 copies in 18 seconds. At this rate, how many copies can it print in 42 seconds?​

Answers

28 copies !!!!!!! In 42 second

Answer:

It should be 28 copies

Step-by-step explanation:

If you divide 42 by 18 it gives you 2.33333333

If you multiply 12 by 2.33333333 it gives you 28

You receive a fax with six bids (in millions of dollars):2.2,1.3,1.9,1.2 2.4 and x is some number that is too blurry to read. Without knowing what x is, the median a. Is 1.9 b. Must be between 1.3 and 2.2 c. Could be any number between 1.2 and 2.4

Answers

Answer:

b. Must be between 1.3 and 2.2

Step-by-step explanation:

The formula for calculating median is :

  1. When n(number of observations in data) is odd = ((n+1)/(2) )^(th)  observation
  2. When n is even = (((n)/(2))^(th)obs. + ((n)/(2) + 1)^(th) obs. )/(2)

Since in our data n is even so we use the formula for calculating median

                  =  (((n)/(2))^(th)obs. + ((n)/(2) + 1)^(th) obs. )/(2)

First arranging data in ascending order we get :

     1.2, 1.3, 1.9, 2.2, 2.4 and since we know nothing about our sixth value x so we assume that it may take any position in our data.

Now there may be cases for which position is x on ;

  • If x is the first obs in our data then our median = (3^(rd)obs + 4^(th)obs  )/(2) = (1.3+1.9)/(2)  

                                                                                                            = 1.6

  • If x is between 1.2 and 1.3 then also median will be 1.6 .
  • If x is between 1.3 and 1.9 then median will be somewhere between 1.3 and 1.9 .
  • If x is between 1.9 and 2.2 then median will be somewhere between 1.9 and 2.2 .
  • And If x is between 2.2 and 2.4 or after 2.4 then median =  (3^(rd)obs + 4^(th)obs  )/(2)

                                                                                         = (1.9+2.2)/(2) = 2.05 .

So from all these observations we conclude that without knowing what x median of data must be between 1.3 and 2.2 .

                                                                                                 

Final answer:

The median of a set of bids can be found by arranging them in numerical order and selecting the middle value.

Explanation:

The median is the middle value of a set of data arranged in numerical order. In this case, we have a set of six bids: 2.2, 1.3, 1.9, 1.2, 2.4, and x (blurred number). To find the median, we first need to arrange the bids in numerical order:

  1. 1.2
  2. 1.3
  3. 1.9
  4. 2.2
  5. 2.4
  6. x

Since there are six bids, the middle value will be the fourth number in the ordered list. Therefore, the median is 2.2.

Learn more about median of bids here:

brainly.com/question/32763192

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