What percent of 68 is 34

Answers

Answer 1
Answer:

Answer:

50

Step-by-step explanation:


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Solve the equation
3(x + 1) = 9+ 2x

Answers

Answer:

x=6

Step-by-step explanation:

So we have the equation:

3(x+1)=9+2x

Distribute the left side:

3x+3=9+2x

Subtract 2x from both sides. The right side cancels:

(3x+3)-2x=(9+2x)-2x\nx+3=9

Subtract 3 from both sides:

(x+3)-3=(9)-3\nx=6

So, x is 6.

3x(x)=3x
3x1=3
3x+3=9+2x

Let f(x) = tan(x)-2/x. Let g(x) = x^2+8.
What is f(x)*g(y)?​

Answers

The product of two functions f(x)*g(y), when f(x) = tan(x)-2/x and g(x) = x^2+8 is,

f(x)* g(y)= y^2\tan(x)+8\tan(x)-(2y^2)/(x)-(16)/(x)

What is the product of functions?

When the two or more than two functions are multiplies together. Then the resultant function is called the product of these functions.

Let suppose there is a function f(x) and another function g(x). Then the product of function can be written as,

f(x)* g(x)

Let suppose, a function f(x) is

f(x)= tan(x)-(2)/(x)

Let another function g(x) is,

g(x)= x^2+8

Then g(y), will be,

g(y)= y^2+8

The product of this two function is,

f(x)* g(y)= \left(\tan(x)-(2)/(x)\right)*(y^2+8)\nf(x)* g(y)= y^2\tan(x)+8\tan(x)-(2y^2)/(x)-(16)/(x)

Thus, the product of two functions f(x)*g(y), when f(x) = tan(x)-2/x and g(x) = x^2+8 is,

f(x)* g(y)= y^2\tan(x)+8\tan(x)-(2y^2)/(x)-(16)/(x)

Learn more about the composite function here;

brainly.com/question/10687170

Answer:

Step-by-step explanation:

(x)*g(y)

=(tanx-2/x)*(y²+8)

=y²tanx+8tanx-2y²/x-16/x

Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedurex1+4x2 =11
2x1+7x2=18
Find the solution to the system of equations.

Answers

Answer:

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

Step(i):-

Given equations are  x₁+4 x₂ = 11 ...(i)

                                 2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

                                A X = B

            \left[\begin{array}{ccc}1&4\n2&7\n\end{array}\right]  \left[\begin{array}{ccc}x\ny\n\end{array}\right] = \left[\begin{array}{ccc}11\n8\n\end{array}\right]

Step(ii):-

      \left[\begin{array}{ccc}1&4\n2&7\n\end{array}\right]  \left[\begin{array}{ccc}x\ny\n\end{array}\right] = \left[\begin{array}{ccc}11\n8\n\end{array}\right]

The Augmented Matrix form is

[AB] = \left[\begin{array}{ccc}1&4&11\n2&7&18\n\end{array}\right]

Apply Row operations,  R₂ → R₂-2 R₁

[AB] = \left[\begin{array}{ccc}1&4&11\n0&-1&-4\n\end{array}\right]  

The matrix form

                   \left[\begin{array}{ccc}1&4\n0&-1\n\end{array}\right]  \left[\begin{array}{ccc}x\ny\n\end{array}\right] = \left[\begin{array}{ccc}11\n-4\n\end{array}\right]

The equations are

                     x₁ + 4 x₂ = 11 ...(a)

                         - x ₂ = - 4

                            x ₂ = 4

Substitute   x ₂ = 4 in equation (a)

                      x₁ + 4 x₂ = 11

                      x₁ = 11 - 16

                        x₁ = -5

Final answer:-

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Which is bigger 0.159 or 1.590​

Answers

Answer:

1.590

Step-by-step explanation:

Answer:

0.159

Step-by-step explanation:its obvious hope this helped tho

P(q ÷ 3 - p ); use p = -6, and q= -3

Answers

Answer:

Step-by-step explanation:

p(q ÷ 3 - p )

p = -6

q= -3

-6(-3/3 - (-6))

-6(-1 + 6)

-6(+5)

-30

Law School According to the Law School Admission Council, in the fall of 2007, 66% of law school applicants wereaccepted to some law schooL4 The training program LSATisfaction claims that 163 of the 240 students trained in 2006were admitted to law school. You can safely consider these trainees to be representative of the population of law schoolapplicants. Has LSAfisfaction demonstrated a real improvement over the national average?a) What are the hypotheses?b) Check the conditions and find the P-value.c) Would you recommend this program based on what you see here? Explain.

Answers

Answer:

a) H_(0): p = 0.66\nH_A: p > 0.66

b) P-value = 0.2650

c) No, this programme will not be recommended as there is no real improvement over the national average.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 240

p = 66% = 0.66

Alpha, α = 0.05

Number of students admitted to law school , x = 163

a) First, we design the null and the alternate hypothesis  

H_(0): p = 0.66\nH_A: p > 0.66

This is a one-tailed(right) test.  

Formula:

\hat{p} = (x)/(n) = (163)/(240) = 0.6792

z = \frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}

Putting the values, we get,

z = \displaystyle\frac{0.6792-0.66}{\sqrt{(0.66(1-0.66))/(240)}} = 0.6279

b) Now, we calculate the p-value from the table.

P-value = 0.2650

c) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Thus, there is no real improvement over the national average.

No, this programme will not be recommended as there is no real improvement over the national average.