# the perimeter of the rectangle is 86 inches. if the length is 3 inches longer that the width, find the width of a rectangle.

Width = 20 inches

Step-by-step explanation:

Perimeter = 86 inches

Width = W

Length = 3 + W

Use the formula 2L + 2W = P to solve

Substitute new value for length (3 + w) into the formula

2(3 + W) + 2W = P

Change perimeter into the equation to 86 inches (Given)

2(3 + W) + 2W = 86

Multiply

6 + 2W + 2W = 86

6 + 4W = 86

Subtract 6 from both sides of the equation

4W = 80

Divide both sides of the equation by 4

W = 20 inches

Hope this helps :)

Answer: The length is 23in and the width is 20 inches

## Related Questions

Simplify the complex fraction. Please show all work!

3(u^2 +u-3)

-------------------

u(u-3)^2

Step-by-step explanation:

u         1

---- + -------

u-3      u

-------------------------

u-3

----------

3

Get a common denominator for the numerator

u *u         1(u-3)

----      + -------

(u-3)u      u(u-3)

-------------------------

u-3

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3

u *u + (u-3)

-----------

(u-3)u

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u-3

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3

Now use copy dot flip

u *u + (u-3)        3

----------------- * -------------

(u-3)u                 u-3

3(u^2 +u-3)

-------------------

u(u-3)^2

150 in. = ___ ft ___ in.

150 in. = 12 ft. 6 in.

Factorise this expression:3x - x^2

(If possible, please explain the method used to solve it)

My answer is x(3 - x)
Is that right?

Yes you are correct, GCF of both terms is x, so you can factor x out.

3x - x²   ⇒   x(3 - x)
3x - x²
x(3) - x(x)
x(3 - x)

How do I find the area of a triangle?

base times hight divided by 2

What is 3 more than x