Answer:

**Answer:**

**less, decreases**

**Explanation:**

When the pressure of an atmosphere occurs because of the force exerted so at the time of the higher altitudes, the air mass i.e. above the earth should be less as the air is attracted towards surface of an earth because of the gravity and air contains the mass that shows near the surface area so automatically the air density reduced due to which the mass also decreased

Cyclohexanecarboxylic acid, C6H11COOH (pKa 4.90), is only slightly soluble in water, but its sodium salt, C6H11COO-Na , is quite soluble in water. Describe the solubility of cyclohexanecarboxylic acid in solutions of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3). The pKa values for the conjugate acids of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3) are 15.7, 6.36, and 10.33, respectively.

Unknown A melts at 113- 114oC. Known compounds 3-Nitroaniline and 4-Nitrophenol both melt at 112-114 oC. If A is mixed with 3-Nitroaniline and the melting point becomes broad and depressed, what must A be __________A) 3-Nitroaniline B) 4-Nitrophenol C) Both

This section of the periodic table is called a(n)

Consider the titration of 30 mL of 0.030 M NH3 with 0.025 M HCl. Calculate the pH after the following volumes of titrant have been added: a) 0 mL; b) 10 mL; c) 20 mL; d)35 mL; e) 36 mL; f) 37 mL.

Oil is a fossil fuel used to run cars, heat up homes, and produce electricity. Oil can be removed from the bottom of the ocean through drilling. Drilling machines dig deep down into the Earth. When oil is found, pipes carry it to the surface. Sometimes, accidents happen that cause the oil to spill into the oceans. The oil can not only kill marine organisms, but when it reaches the surface of the water, some chemicals evaporate, become part of the atmosphere, and pollute the air.Based on the passage, which resources and organisms are affected by oil spills? Select three options.a) airb) landc) waterd) birds in the aire) trees on landf) organisms in the water

Unknown A melts at 113- 114oC. Known compounds 3-Nitroaniline and 4-Nitrophenol both melt at 112-114 oC. If A is mixed with 3-Nitroaniline and the melting point becomes broad and depressed, what must A be __________A) 3-Nitroaniline B) 4-Nitrophenol C) Both

This section of the periodic table is called a(n)

Consider the titration of 30 mL of 0.030 M NH3 with 0.025 M HCl. Calculate the pH after the following volumes of titrant have been added: a) 0 mL; b) 10 mL; c) 20 mL; d)35 mL; e) 36 mL; f) 37 mL.

Oil is a fossil fuel used to run cars, heat up homes, and produce electricity. Oil can be removed from the bottom of the ocean through drilling. Drilling machines dig deep down into the Earth. When oil is found, pipes carry it to the surface. Sometimes, accidents happen that cause the oil to spill into the oceans. The oil can not only kill marine organisms, but when it reaches the surface of the water, some chemicals evaporate, become part of the atmosphere, and pollute the air.Based on the passage, which resources and organisms are affected by oil spills? Select three options.a) airb) landc) waterd) birds in the aire) trees on landf) organisms in the water

**Answer:**

**Explanation:**

In an internal combustion engine operational in automobiles, fuels are converted into mechanical energy in order to move pistons.

The basic reaction in automobile engines is combustion.

**Principal chemicals consumed Chemicals produced**

** **Petroleum Carbon dioxide

Carbon monoxide

Nitrogen oxides

Sulfur oxides

In **diesel engines**, production of particulate carbon is also produced.

**Automobiles such as car, truck, motorbikes run on petrol or diesel.** While operating these automobiles, combustion of diesel or petrol takes place which in turn requires oxygen for the process to occur.

Operation of the automobiles consumes **oxygen, petrol or diesel** and releases **harmful chemicals** like **carbon dioxide (CO2), sulphur dioxide (SO2), carbon monoxide (CO)** and many more. These chemicals pollutes the air and also affects the **survival of living organisms by affecting the respiratory organs. **

**Answer : The mass of silver chlorate will be 2.654 grams.**

**Explanation :**

**The balanced chemical reaction is,**

**First we have to calculate the moles of oxygen gas at STP.**

As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas

So, 0.466 L volume of oxygen gas present in mole of oxygen gas

**Now we have to calculate the moles of silver chlorate.**

From the balanced chemical reaction, we conclude that

As, 3 moles of oxygen produced from 2 moles of silver chlorate

So, 0.0208 moles of oxygen produced from moles of silver chlorate

**Now we have to calculate the mass of silver chlorate.**

Molar mass of silver chlorate = 191.32 g/mole

**Therefore, the mass of silver chlorate will be 2.654 grams.**

C in CH4 :

H in CH4 :

O in O2 :

C in CO2 :

O in CO2 :

H in H2O :

O in H2O :

Which atom is reduced?

Which atom is oxidized?

The **oxidation numbers** of the **atoms** of the specified elements in each of the given atoms are;

__1) -4__

__1) -42) +1__

__1) -42) +13) 0__

__1) -42) +13) 04) +4__

__1) -42) +13) 04) +45) -2__

__1) -42) +13) 04) +45) -26) +1__

__1) -42) +13) 04) +45) -26) +17) -2__

__1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = C__

__1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = CAtom reduced = O__

1) **C in CH4**

To get the oxidation number of C;

Oxidation state of hydrogen atom is +1 and so if the oxidation state of C is x, then we have;

x + 4(+1) = 0

x + 4 = 0

x = -4

2) **H in CH4**

Oxidation state on Carbon atom in this case is -4. Thus;

-4 + 4x = 0

4x = 4

x = +1

3) **O in O2**

This is oxygen gas that exists in it's free state and as such oxidation number is 0.

4) **C in CO2**

Oxidation state of O here is -2. Thus;

x + 2(-2) = 0

x - 4 = 0

x = +4

5) **O in CO2**

Oxidation state of C is +4 here. Thus;

4 + 2x = 0

2x = -4

x = -4/2

x = -2

6) **H in H2O**

Oxidation state of oxygen here is -2. Thus;

2x - 2 = 0

2x = 2

x = 2/2

x = +1

7) **O in H2O**

Oxidation state of hydrogen here is +1. Thus;

2(1) + x = 0

x = -2

Finally, oxidation number of carbon increased, then it is the atom that was **oxidized** while the atom **reduced** is the Oxygen atom.

Read more at; brainly.com/question/22816291

**Answer:**

1. -4

2. +1

3. 0

4. +4

5. -2

6. +1

7. -2

reduced = H

oxidized = O

**Explanation:**

Know oxidation rules.

- Hope this helped! Please let me know if you would like to learn this. I could show you the rules and help you work through them.

The amount of **heat** will be 5230 j.

What is heat?

**Heat** is a type of energy that is transferred between both the system and its surroundings as a result of temperature variations.

Calculation of **heat.**

Given data:

Mass = 25.0 g = 0.025 kg

C = 4.184 J/g°C

= 80.0°C

= 30.0°C

Q= ?

By using the formula of **heat**.

Q = MC ()

Put the value of given data in heat equation.

Q(**heat**) = 0.025 × 4.184 ( 30 - 80)

Q(**heat**) = 5230 J.

Therefore, the amount of **heat **will be 5230 J.

To know more about **heat**.

brainly.com/question/13860901.

#SPJ2

**Answer:**

5230 J

**Explanation:**

m = 25 g = 0,025 kg

c = 4,184 J /(g * °C) = 4184 J /(kg * °C)

= 80 °C

= 30 °C

The formula is Q = c *m * ()

Calculating:

Q = 4184 * 0,025 * (30 - 80) = 5230 J

Note that we get a negative heat (-5230 J). It just means that it is released.

To find the concentration of X+ at a potential of 0.0610V, use the Nernst equation which describes the electrochemical potential of a system. Given the initial concentration of X+ and its potential, rearrange the equation to solve for the concentration of X+ at the new potential.

The problem given can be solved using the **Nernst equation**, which relates the reduction potential of an **electrochemical****reaction** (half-cell or full cell reaction) to the standard electrode potential, temperature, and the activities of the chemical species undergoing the reduction.

The Nernst equation at 25 °C can be simplified as:

*E = E° - (0.059/n) log [Cl^- /[X^+]*

Where E is the electrode potential, E° is the standard electrode potential, n is the number of electron transferred and [Cl^- /[X^+] is the ratio of ion activities. Since the ion's activity coefficient is 1, we can treat [X^+] as the concentration of X^+.

If you apply this equation, using the given potentials and known initial concentration of X^+, you can solve for the concentration of X^+ when the potential is 0.0610V.

#SPJ12

The concentration of X+ can be calculated using the **Nernst equation **by substituting the initial and final potentials. By solving the equation, you can find the concentration of X+.

The concentration of X+ can be calculated using the Nernst equation. The Nernst equation relates the potential of a cell to the concentration of the ions involved.

The Nernst equation is given by:

**E = Eº - (0.0592/n)log(Q)**

Where E is the potential, Eº is the standard electrode potential, n is the number of electrons transferred, and Q is the reaction quotient.

In this case, the initial potential is 0.0460 V and the final **potential is 0.0610 V**. By substituting these values into the Nernst equation, you can solve for the concentration of X+.

#SPJ11

**Answer:**

2.90

**Explanation:**

Any ** buffer system** can be described with the reaction:

Where is the ** acid** and is the

With all this in mind, we can write the reaction for our buffer system:

In this case, the acid is with a concentration of 0.413 M and the base is with a concentration of 0.237 M. We can calculate the __ pKa value__ if we do the "-Log Ka", so:

Now, we can plug the values into the Henderson-Hasselbach

__The pH value would be 2.90__

I hope it helps!