Atmospheric pressure arises due to the force exerted by the air above the Earth. At higher altitudes, the mass of the air above the Earth is _____ than at sea level, and atmospheric pressure therefore _____ with altitude.
When the pressure of an atmosphere occurs because of the force exerted so at the time of the higher altitudes, the air mass i.e. above the earth should be less as the air is attracted towards surface of an earth because of the gravity and air contains the mass that shows near the surface area so automatically the air density reduced due to which the mass also decreased
As we drive an automobile, we dont't think about the chemical consumed and produced. Prepare a list of the principal chemicals consumed and produced during the operation of an automobile.
In an internal combustion engine operational in automobiles, fuels are converted into mechanical energy in order to move pistons.
The basic reaction in automobile engines is combustion.
Principal chemicals consumed Chemicals produced
Petroleum Carbon dioxide
In diesel engines, production of particulate carbon is also produced.
Automobiles such as car, truck, motorbikes run on petrol or diesel. While operating these automobiles, combustion of diesel or petrol takes place which in turn requires oxygen for the process to occur.
Operation of the automobiles consumes oxygen, petrol or diesel and releases harmful chemicals like carbon dioxide (CO2), sulphur dioxide (SO2), carbon monoxide (CO) and many more. These chemicals pollutes the air and also affects the survival of living organisms by affecting the respiratory organs.
What is the mass of silver chlorate (191.32 g/mol) that decomposes to release 0.466L of oxygen gas at STP? AgC1036) _AgCl). _026) A) 1.33g B) 597 E) 7.968 C) 3.988 D) 2658
Answer : The mass of silver chlorate will be 2.654 grams.
The balanced chemical reaction is,
First we have to calculate the moles of oxygen gas at STP.
As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas
So, 0.466 L volume of oxygen gas present in mole of oxygen gas
Now we have to calculate the moles of silver chlorate.
From the balanced chemical reaction, we conclude that
As, 3 moles of oxygen produced from 2 moles of silver chlorate
So, 0.0208 moles of oxygen produced from moles of silver chlorate
Now we have to calculate the mass of silver chlorate.
Molar mass of silver chlorate = 191.32 g/mole
Therefore, the mass of silver chlorate will be 2.654 grams.
Enter the oxidation number of one atom of each element in each reactant and product.CH4(g)+2O2(g)⟶CO2(g)+2H2O(g) C in CH4 : H in CH4 : O in O2 : C in CO2 : O in CO2 : H in H2O : O in H2O : Which atom is reduced? Which atom is oxidized?
The oxidation numbers of the atoms of the specified elements in each of the given atoms are;
Note that we get a negative heat (-5230 J). It just means that it is released.
When an ion‑selective electrode for X+ was immersed in 0.0482 M XCl, the measured potential was 0.0460 V . What is the concentration of X+ when the potential is 0.0610 V ? Assume that the electrode follows the Nernst equation, the temperature is at 25 °C, and that the activity coefficient of X+ is 1.
To find the concentration of X+ at a potential of 0.0610V, use the Nernst equation which describes the electrochemical potential of a system. Given the initial concentration of X+ and its potential, rearrange the equation to solve for the concentration of X+ at the new potential.
The problem given can be solved using the Nernst equation, which relates the reduction potential of an electrochemicalreaction (half-cell or full cell reaction) to the standard electrode potential, temperature, and the activities of the chemical species undergoing the reduction.
The Nernst equation at 25 °C can be simplified as:
E = E° - (0.059/n) log [Cl^- /[X^+]
Where E is the electrode potential, E° is the standard electrode potential, n is the number of electron transferred and [Cl^- /[X^+] is the ratio of ion activities. Since the ion's activity coefficient is 1, we can treat [X^+] as the concentration of X^+.
If you apply this equation, using the given potentials and known initial concentration of X^+, you can solve for the concentration of X^+ when the potential is 0.0610V.