Answer:
2.2m/s
Explanation:
a=vu/t
12.52.5/4.5=2.222
~2.2m/s
Answer:
m2=3.2722lbm/s
Explanation:
Hello!
To solve this problem follow the steps below
1. Find water densities and entlapies in all states using thermodynamic tables.
note Through laboratory tests, thermodynamic tables were developed, which allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy, etc.)
through prior knowledge of two other properties, such as pressure and temperature.
D1=Density(Water;T=50;x=0)=62.41 lbm/ft^3
D2=Density(Water;T=120;x=0)=61.71 lbm/ft^3
D3=Density(Water;T=80;x=0)=62.21 lbm/ft^3
h1=Enthalpy(Water;T=50;x=0)=18.05 BTU/lbm
h2=Enthalpy(Water;T=120;x=0)=88 BTU/lbm
h3=Enthalpy(Water;T=80;x=0)=48.03 BTU/lbm
2. uses the continuity equation that states that the mass flow that enters a system is the same as the one that must exit
m1+m2=m3
3. uses the first law of thermodynamics that states that all the flow energy entering a system is the same that must come out
m1h1+m2h2=m3h3
18.05(m1)+88(m2)=48.03(m3)
divide both sides of the equation by 48.03
0.376(m1)+1.832(m2)=m3
4. Subtract the equations obtained in steps 3 and 4
m1 + m2 = m3

0.376m1 + 1.832(m2) =m3

0.624m10.832m2=0
solving for m2
(0.624/0.832)m1=m2
0.75m1=m2
5. Mass flow is the product of density by velocity across the crosssectional area
m1=(D1)(A)(v1)
internal Diameter for 2" Sch 40=2.067in=0.17225ft
m1=(62.41 lbm/ft^3)(0.0233ft^2)(3ft/S)=4.3629lbm/s
6.use the equation from step 4 to find the mass flow in 2
0.75m1=m2
0.75(4.3629)=m2
m2=3.2722lbm/s
The baseball curves better at a flatplain due to contacting with air.
A curveball is a breaking pitch with more movement than most other pitches. It is thrown slower and with more overall break than a slider and is used to throw hitters off balance.
On a flat plain, a baseball will curve down better. This is due to the curving being caused by the ball contacting air and being pushed in a specificdirection.
The spin, speed, and location of the ball's stitches in relation to the air will all influence how it changes direction when pushed against.
Consider throwing a baseball in a vacuum where there is no air. Because there is no air to push on the ball, it will not curve at all.
Thus, a flat plain area will be better for baseball curve.
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A baseball will curve better down on a flat plain.In view of the fact that the curving is caused by the ball contacting the air and pushing the ball in a particular direction.
B. 60 cm
C. 75 cm
D. 90 cm
Answer:
3 min 55 sec is the solidification time if the cylinder height is doubled
7min 40 sec if the diameter is doubled
Explanation:
see the attachment
To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as
The potential energy,
The volume,
The potential energy per unit volume is defined as the energy density.
The energy density related with electric field is given by
Here, the permitivity of the free space is
Therefore, rerranging to find the electric field strength we have,
Therefore the electric field is 2.21V/m
To calculate the electric field strength that would store 12.5 Joules of energy in every 6.00 mm^3 of space, we use the energy density formula. We firstly find the energy density and input it into the formula to solve for the electric field strength. The result is approximately 6.87 X 10^6 N/C.
The energy stored in an electric field is given by the formula U = 1/2 ε E^2. Here, U is the energy density (energy per unit volume), E is the electric field strength, and ε is the permittivity of free space.
Given that the energy stored U is 12.5 joules, and the volume is 6.00 mm^3 or 6.00X10^9 m^3, the energy density (U) can be computed as 12.5 J/6.00X10^9 m^3 = 2.08X10^12 Joule/meter^3.
We can solve the formula for E (electric field strength): E = sqrt ((2U)/ε). Substituting the value of ε (8.85 × 10^12 m^3 kg^1 s^4 A^2), we can find E to be approximately 6.87 X 10^6 N/C.
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Answer:
Explanation:
Rate of Change
When an object moves at constant speed v, the distance traveled at time t is
We know at time t=0 two friends are at the intersection of two perpendicular roads. One of them goes north at speed v and the other goes west at constant speed w (assumed). Since both directions are perpendicular, the distances make a right triangle. The vertical distance is
and the horizontal distance is
The distance between both friends is computed as the hypotenuse of the triangle
We need to find d', the rate of change of the distance between both friends.
Plugging in the above relations
Solving for d
Differentiating with respect to t
The problem is solved using Pythagoras' Theorem, representing the two travel paths forming a right triangle. The rate at which the distance increases between two points moving perpendicularly can be found by differentiating the resulting equation, which yields the expression sqrt[(v^2)+(u^2)].
The question is about the rate at which the distance between you and your friend is increasing at time t. It's a typical problem in kinematics. Because the roads are perpendicular to each other, we can solve the problem using Pythagoras' Theorem which states that in a rightangled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Let's denote the distance you've traveled as D1 = v*t (because distance = speed * time) and the distance your friend has travelled D2 = u*t. The distance between you can be computed using Pythagoras' Theorem as D = sqrt(D1^2 + D2^2). Hence, D = sqrt[(v*t)^2 + (u*t)^2]. Differentiating D with respect to t using the chain rule will give us the rate at which the distance between you is increasing, which is sqrt[(v^2)+(u^2)].
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