Answer:

**Answer:**

ROYGBIV or Roy G

**Explanation:**

Thanks for the points!

What is the specific heat value of brass?

Explain the arrangement of the first 20 elements in the periodic table. Please help! Will give brainliest!

A student dissolves 12.g of sucrose C12H22O11 in 300.mL of a solvent with a density of 1.01/gmL . The student notices that the volume of the solvent does not change when the sucrose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits. molarity = molality =

Be sure to answer all parts. A baseball pitcher's fastballs have been clocked at about 97 mph (1 mile = 1609 m). (a) Calculate the wavelength of a 0.148−kg baseball (in nm) at this speed. × 10 nm (Enter your answer in scientific notation) (b) What is the wavelength of a hydrogen atom at the same speed? nm

What is my percent yield of titanium (II) oxide if I react 20 grams of titanium (II) oxide in excess water (that means TiS is my limiting reactant) and my actual yield of titanium (II) oxide is 13 g?

Explain the arrangement of the first 20 elements in the periodic table. Please help! Will give brainliest!

A student dissolves 12.g of sucrose C12H22O11 in 300.mL of a solvent with a density of 1.01/gmL . The student notices that the volume of the solvent does not change when the sucrose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits. molarity = molality =

Be sure to answer all parts. A baseball pitcher's fastballs have been clocked at about 97 mph (1 mile = 1609 m). (a) Calculate the wavelength of a 0.148−kg baseball (in nm) at this speed. × 10 nm (Enter your answer in scientific notation) (b) What is the wavelength of a hydrogen atom at the same speed? nm

What is my percent yield of titanium (II) oxide if I react 20 grams of titanium (II) oxide in excess water (that means TiS is my limiting reactant) and my actual yield of titanium (II) oxide is 13 g?

Part A

If the pH of a 0.133 M solution is 10.66, what is the ionization constant of the base?

Express your answer using two significant figures.

**Answer:**

**Kb = 1.6*10^-6**

**Explanation:**

The given reaction is:

**The ionization constant of the base Kb is given as:**

The pH = 10.66

therefore, pOH = 14-pH = 14-10.66 =3.34

**[N2H5+] = [OH-] = 4.57*10^-4M**

**[N2H4] = 0.133 M**

Based on eq(1)

Both transverse waves and longitudinal waves have motion parallel to velocity.

Both transverse waves and longitudinal waves have motion perpendicular to velocity.

Transverse waves have motion parallel to velocity, while longitudinal waves have motion perpendicular to velocity.

Transverse waves have motion perpendicular to velocity, while longitudinal waves have motion parallel to velocity.

The true statement is that **Transverse** waves have **motion** perpendicular to

**velocity**, while **longitudinal** waves have **motion** parallel to **velocity**.

This is a **disturbance** which travels through a **medium** and transports

**energy** in the process.

**Transverse** waves have motion which are **perpendicular** to the **velocity**

while the **longitudinal** waves move in the direction of the **velocity** which is

why they are regarded as being **parallel** to each other.

Read more about **Waves** here brainly.com/question/15663649

**Answer:**

D (The last answer)

**Explanation:**

In a transverse wave, particles oscillate perpendicular to the direction of wave motion.

In a longitudinal wave, the oscillations of particles are parallel to the direction of propagation.

**Answer and Explanation:**

**(a) Na and H : **The compound formed by Na and H is **sodium hydride which formula is NaH**

**(b) B and O : **The compound formed by Ba and O is **barium oxide which formula is BaO**

**(C)****Na and S :** The compound formed by Na and S is **sodium sulfide which formula is **

**(D) Al and F :** The compound formed by Al and F is a**luminium fluoride which formula is **

**(E) F and O : **The compound formed by F and O is **oxygen fluoride which formula is **

**(F) Sr and Cl : **The compound formed by Sr and Cl is **strontium chloride which formula is **

**Answer:**

(c) 18.8 g; (a) 0.798; (b) 16 mL

**Explanation:**

You don't give your experimental data, so I shall assume:

Mass of Al = 1.07 g

20 mL of 3 mol·L⁻¹ KOH

20 mL of 9 mol·L⁻¹ H₂SO₄

The **overall** equation for the reaction is

Mᵣ: 26.98 474.39

2Al + 2KOH +4H₂SO₄ + 22H₂O ⟶ 2K[Al(SO₄)₂]·12H₂O + 3H₂

m/g: 1.07

**(c) Theoretical yield of alum**

**(i) Moles of Al**

**(ii) Moles of alum**

**(iii) Theoretical yield of alum**

**(a) Scaling factor for 15.0 g alum**

You want a theoretical yield of 15.0 g, so you must scale **down** the reaction.

**(b) Corrected volumes of NaOH and H₂SO₄**

V = 0.798 × 20 mL = **16 mL**

b. 72.8 g c2h6o in 2.34 l of solution

c. 12.87 mg ki in 112.4 ml of solution

Q1)

molarity is defined as the number of moles of solute in 1 L solution

the number of moles of LiNO₃ - 0.38 mol

volume of solution - 6.14 L

since molarity is number of moles in 1 L

number of moles in 6.14 L - 0.38 mol

therefore number of moles in 1 L - 0.38 mol / 6.14 L = 0.0619 mol/L

molarity of solution is 0.0619 M

Q2)

the mass of C₂H₆O in the solution is 72.8 g

molar mass of C₂H₆O is 46 g/mol

number of moles = mass present / molar mass of compound

the number of moles of C₂H₆O - 72.8 g / 46 g/mol

number of C₂H₆O moles - 1.58 mol

volume of solution - 2.34 L

number of moles in 2.34 L - 1.58 mol

therefore number of moles in 1 L - 1.58 mol / 2.34 L = 0.675 M

molarity of C₂H₆O is 0.675 M

Q3)

Mass of KI in solution - 12.87 x 10⁻³ g

molar mass - 166 g/mol

number of mole of KI = mass present / molar mass of KI

number of KI moles = 12.87 x 10⁻³ g / 166 g/mol = 0.0775 x 10⁻³ mol

volume of solution - 112.4 mL

number of moles of KI in 112.4 mL - 0.0775 x 10⁻³ mol

therefore number of moles in 1000 mL- 0.0775 x 10⁻³ mol / 112.4 mL x 1000 mL

molarity of KI - 6.90 x 10⁻⁴ M

molarity is defined as the number of moles of solute in 1 L solution

the number of moles of LiNO₃ - 0.38 mol

volume of solution - 6.14 L

since molarity is number of moles in 1 L

number of moles in 6.14 L - 0.38 mol

therefore number of moles in 1 L - 0.38 mol / 6.14 L = 0.0619 mol/L

molarity of solution is 0.0619 M

Q2)

the mass of C₂H₆O in the solution is 72.8 g

molar mass of C₂H₆O is 46 g/mol

number of moles = mass present / molar mass of compound

the number of moles of C₂H₆O - 72.8 g / 46 g/mol

number of C₂H₆O moles - 1.58 mol

volume of solution - 2.34 L

number of moles in 2.34 L - 1.58 mol

therefore number of moles in 1 L - 1.58 mol / 2.34 L = 0.675 M

molarity of C₂H₆O is 0.675 M

Q3)

Mass of KI in solution - 12.87 x 10⁻³ g

molar mass - 166 g/mol

number of mole of KI = mass present / molar mass of KI

number of KI moles = 12.87 x 10⁻³ g / 166 g/mol = 0.0775 x 10⁻³ mol

volume of solution - 112.4 mL

number of moles of KI in 112.4 mL - 0.0775 x 10⁻³ mol

therefore number of moles in 1000 mL- 0.0775 x 10⁻³ mol / 112.4 mL x 1000 mL

molarity of KI - 6.90 x 10⁻⁴ M

The molarities of the given solutions: (a). 0.38 mol of LiNO₃ in 6.14 L of solution has a molarity of 0.062 M. (b). 72.8 g of C₂H₆O in 2.34 L of solution has a **molarity** of 0.675 M. (c). 12.87 mg of KI in 112.4 mL of solution has a molarity of 0.000688 M.

To calculate the molarity (M) of a solution, you can use the formula:

Molarity (M) = **moles** of solute / volume of solution (in liters)

a. 0.38 moles of LiNO₃ in 6.14 L of solution:

Molarity (M) = 0.38 moles / 6.14 L = 0.062 M

b. 72.8 grams of C₂H₆O (ethyl alcohol) in 2.34 L of solution:

First, you need to convert **grams** to moles using the molar mass of C₂H₆O.

Molar mass of C₂H₆O = 2(12.01 g/mol) + 6(1.01 g/mol) + 1(16.00 g/mol) = 46.08 g/mol

Now, calculate moles of C₂H₆O:

moles = 72.8 g / 46.08 g/mol = 1.58 moles

Molarity (M) = 1.58 moles / 2.34 L = 0.675 M

c. 12.87 mg of KI in 112.4 mL of solution:

First, convert **milligrams** to grams (1 g = 1000 mg):

12.87 mg = 12.87 g (since 12.87 mg / 1000 = 0.01287 g)

Now, convert mL to liters (1 L = 1000 mL):

112.4 mL = 0.1124 L

Calculate moles of KI:

Molar mass of KI = 39.10 g/mol (for K) + 126.90 g/mol (for I) = 166.00 g/mol

moles = 0.01287 g / 166.00 g/mol = 7.75 × 10⁻⁵ moles

Molarity (M) = (7.75 × 10⁻⁵ moles) / 0.1124 L = 0.000688 M

So, the molarities of the solutions are as follows:

a. 0.062 M

b. 0.675 M

c. 0.000688 M

To know more about **moles:**

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The **number** which should be placed in front of **CaSO4** to give the **same** total number of **sulfate ions** on each side of the equation is; **3**.

According to the question;

- We are required to determine what
**number**should be placed in front of**CaSO4**to give the**same number**of each side of the equation.

The equation given is;

?CaSO4 + AlCl3 → CaCl2 + Al2(SO4)3

There are **3 moles** of **SO4** on the **right** hand side of the equation and as such, there should be the same number of **SO4** on the **left** too.

In essence, the **number** that should be added in front of **CaSO4** is; **3**.

Read more:

**Answer : The number placed in front of should be, three (3).**

**Explanation :**

**Balanced chemical reaction :** It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

**The given unbalanced chemical reaction is,**

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.

**In order to balanced the chemical reaction,** the coefficient 3 is put before the , the coefficient 2 is put before the and the coefficient 3 is put before the .

**Thus, the balanced chemical reaction will be,**

**Therefore, the number placed in front of should be, three (3).**