PLZ HELP ASAP

Answer:

**Answer:**

the 2nd one I think i mean I forget stuff but not math that much

Find the missing values on the diagram below. Assume that each line is evenly divided

Determine the x-intercept of the line whose equation is given:y = StartFraction x Over 2 EndFraction minus 3a.(6, 0)b.(negative 6, 0)c.(0, three-halves)d.(Negative three-halves, 0)

6x^2 + 2x = 0 aiudajjffjjfivjzdhasadñojdva

Suppose you decide to invest in an annuity that pays 5% interest, compounded semiannually. How much money do you need to invest semiannually to reach a savings goal of $300,000 at the end of 25 years.

24 1/2 is equal to what decimal

Determine the x-intercept of the line whose equation is given:y = StartFraction x Over 2 EndFraction minus 3a.(6, 0)b.(negative 6, 0)c.(0, three-halves)d.(Negative three-halves, 0)

6x^2 + 2x = 0 aiudajjffjjfivjzdhasadñojdva

Suppose you decide to invest in an annuity that pays 5% interest, compounded semiannually. How much money do you need to invest semiannually to reach a savings goal of $300,000 at the end of 25 years.

24 1/2 is equal to what decimal

The **probability** that one of Melissa's classmates will be a brunette or have blue eyes is 0.75.

**Probability** can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an **event**.

Here, given that,

60% are brunettes,

i.e. P(A)=0.6

20% have blue eyes,

i.e. P(B)=0.2

and 5% are brunettes that have blue eyes

i.e. P(A∪B)=0.05

So. P(A∩B)= P(A)+P(B)-P(A∪B)

=0.6+0.2-0.05

=0.75

Hence, the probability that one of Melissa's classmates will be a brunette or have blue eyes is 0.75.

To learn more on probability click:

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**Answer:**

17

**Step-by-step explanation:**

**Answer:**

x=8.75

**Step-by-step explanation:**

The price x that maximizes profit is the maximum value of the function, and the maximum value of the function is located at a point where the first derivative of the function is equal to zero. The first derivative is:

Using P'(x)=0:

The minimum value of the function is also at a point where the first derivative of the function is equal to zero. To differentiate if x=8. is a minimum or a maximum obtain the second derivative and evaluate it at x=8.75 if the value P''(x)>0 x is minimum and if P''(x)<0 x is a maximum.

Evaluating at x=8.75:

Therefore, x=8.75 is the maximum value of the function and it is the price that maximizes profit.

**Answer:**

A

**Step-by-step explanation:**

Construction Y because point E is the circumcenter of Triangle LMN

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

**Answer:**

See the attached picture for detailed answer.

**Step-by-step explanation:**

See the attached picture for detailed answer.

The **probability **question from part (a) requires calculating the chance of getting all heads or all tails on multiple days in a year, which involves complex probability distributions. For part (b), using a Poisson distribution could be appropriate due to the rarity of the event and the high number of trials involved.

The question pertains to the field of probability theory and involves calculating the probability of specific outcomes when flipping a fair coin. For part (a), Jack flips a coin ten times each morning for a year, counting the days (X) when all flips are identical (all heads or all tails). The exact **expression **for P(X > 1), the probability of more than one such day, requires several steps. First, we find the probability of a single day having all heads or all tails, then use that to calculate the probability for multiple days within the year. For part (b), whether it is appropriate to approximate X by a Poisson distribution depends on the rarity of the event in question and the number of trials. A Poisson distribution is typically used for rare events over many trials, which may apply here.

For part (a), the probability on any given day is the sum of the probabilities of all heads or all tails: 2*(0.5^10). Over a year (365 days), we need to calculate the probability distribution for this outcome occurring on multiple days. To find P(X > 1), we would need to use the binomial **distribution **and subtract the probability of the event not occurring at all (P(X=0)) and occurring exactly once (P(X=1)) from 1. However, this calculation can become quite complex due to the large number of trials.

For part (b), given the low probability of the event (all heads or all tails) and the high number of trials (365), a Poisson distribution may be an appropriate **approximation**. The mean (λ) for the Poisson distribution would be the expected number of times the event occurs in a year. Since the probability of all heads or all tails is low, it can be considered a rare event, and the Poisson distribution is often used for modeling such scenarios.

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**Answer:**

Weighted mean hourly charge = $168.28 (Approx)

**Given:**

Charge for research = $125 per hour

Charge for consultations = $80 per hour

Charge for writing a brief = $250 per hour

Research work = 12 hour

Consultations = 8 hour

Writing = 15 hour

**Computation:**

Total hours = 12 + 8 + 15 = 35 hours

Total charge for researching = $125 × 12 = $1,500

Total charge for consulting = $80 × 8 = $640

Total charge for writing = $250 × 15 = $3,750

Total charge = $5,890

Weighted mean hourly charge = 5890 / 35

**Weighted mean hourly charge = $168.28 (Approx)**