MZTRI = 3x - 5, mZIRB = x + 27,
and mZTRB = 86. Find the mZTRI.
mZTRI = 3x - 5, mZIRB = x + 27, - 1

Answers

Answer 1
Answer:

Answer:

m∠TRI  = 43

Step-by-step explanation:

m∠TRI +  m∠IRB = m∠TRB

3x - 5 + x + 27 = 86

3x + x - 5 + 27 = 86   {Combine like terms}

     4x  + 22    = 86       {Subtract 22 from both sides}

               4x = 86 - 22

                4x = 64           {Divide both sides by 4}

                  x = 64/4

                 x = 16

m∠TRI = 3x - 5

           = 3*16 - 5

          = 48 - 5

          = 43


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Please help, will mark you as brainleist!!!
What is 04.151515... into a fraction

The attendance at Treeton Middle School was 2,465 on Monday. The attendance was tracked for the next two days. The change in attendance from the previous day is shown in the table.Which equation shows the attendance on Tuesday?

Answers

Answer:

2107.575

Step-by-step explanation:

Final answer:

To find the attendance on Tuesday, we need to add the change in attendance from Monday to Tuesday to the attendance on Monday.

Explanation:

The attendance at Treeton Middle School was 2,465 on Monday. The table shows the change in attendance from the previous day. To find out the attendance on Tuesday, we need to add the change in attendance from Monday to Tuesday to the attendance on Monday.

Change in attendance from Monday to Tuesday: -53
Attendance on Monday: 2,465

Attendance on Tuesday = Attendance on Monday + Change in attendance from Monday to Tuesday
Attendance on Tuesday = 2,465 + (-53) = 2,412

Therefore, the equation that shows the attendance on Tuesday is: Attendance on Tuesday = 2,412.

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HELP!! Monette began heating a liquid with a starting temperature of 62.5°F. The temperature increased by 5° per minute.

What is the recursive rule that represents this situation?\
an=
a1=

Answers

Greetings!

Answer:

an = 65 + 5_(n - 1)

a1 = 65

Step-by-step explanation:

If the begining value is 65, then a1 has to be itL

a1 = 65

Then, if this amount increased every minute then 5 has to be added to this value each time:

an = 65 + 5

But this means that 5 is added to 65 every time with no increase, so the five must me multiplied by the n value:

an = 65 + 5_(n)

a2 = 65 + 10 = 75

But this value should be 70 because it is the first point after 65 so it should be +5 not +10

To do this we can simply subtract one from the n value that is being multiplied by 5:

an = 65 + 5_(n - 1)

Which is the recursive rule!


Hope this helps!



Solve the equation 15.6 + (-1.8) =

Answers

The solution to the equation 15.6 + (-1.8) is 13.8.

The equation to solve is 15.6 + (-1.8).

First, add the two numbers: 15.6 + (-1.8) = 13.8.

The result is 13.8.

In this equation, you're adding a positive value (15.6) and a negative value (-1.8), which results in a smaller positive value. When you add a positive number and a negative number, you can think of it as moving to the right on the number line (positive direction) but not as far as you would if you were only considering the positive value.

So, the solution to the equation 15.6 + (-1.8) is 13.8.

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Since +(-) becomes (-) we can write the given problem as

15.6-1.8

Subtraction gives us 13.8

:)

593,204 rounded to the nearest million

Answers

The answer is  1,000,000

A study published in 1993 found that babies born at different times of the year may develop the ability to crawl at different ages! The author of the study suggested that these differences may be related to the temperature at the time the infant is 6 months old. (Benson and Janette, Infant Behavior and Development [1993]. The study found that 32 babies born in January crawled at an average age of 29.84 weeks, with a standard deviation of 7.08 weeks. Among 21 July babies, crawling ages averaged 33.64 weeks, with a standard deviation of 6.91 weeks. Is this difference significant?

Answers

Answer:

t=\frac{(29.84-33.64)-0}{\sqrt{(7.08^2)/(32)+(6.91^2)/(21)}}}=-1.939  

p_v =2*P(t_(51)<-1.939)=0.0580  

Comparing the p value with the significance assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the difference between the two groups is NOT significantly different at 1% of significance.  

Step-by-step explanation:

Data given

\bar X_(1)=29.84 represent the mean for sample January

\bar X_(2)=33.64 represent the mean for sample July

s_(1)=7.08 represent the sample standard deviation for 1  

s_(2)=6.91 represent the sample standard deviation for 2  

n_(1)=32 sample size for the group 2  

n_(2)=21 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_(1)-\mu_(2)=0  

Alternative hypothesis:\mu_(1) - \mu_(2)\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_(1)-\bar X_(2))-\Delta}{\sqrt{(\sigma^2_(1))/(n_(1))+(\sigma^2_(2))/(n_(2))}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=32+21-2=51  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(29.84-33.64)-0}{\sqrt{(7.08^2)/(32)+(6.91^2)/(21)}}}=-1.939  

P value  

Since is a bilateral test the p value would be:  

p_v =2*P(t_(51)<-1.939)=0.0580  

Comparing the p value with the significance assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the difference between the two groups is NOT significantly different at 1% of significance.  

80 total students 6/2 are girls how many are girls

Answers

Answer:

60

Step-by-step explanation: