Answer:

The **probability **of selecting a black pair of socks first, then a blue or white pair of socks is 27/136.

The probability of selecting a black pair of socks first is:

probability = (**number **of black pairs)/(total number of pairs)

= 8/17

Once a black pair of socks has been selected, there are 16 pairs of socks left in the drawer. Of these 16 pairs, 9 are either blue or white.

The probability of selecting a blue or white pair of socks second is:

probability = (number of blue and white pairs)/(number of remaining pairs)

= 9/16

Therefore, the overall probability of **selecting **a black pair of socks first, then a blue or white pair of socks is:

probability = (8/17)*(9/16)

= 27/136

To learn more about **probability **here:

#SPJ2

Answer:

**Answer:**

26.4%

**Step-by-step explanation:**

PLS GIVE BRAINLIEST

Charlotte had $86. She spent $15 on a ticket to the zoo and then her mom gave her $24. How much money does Charlotte have now? $____

Write an equation for the graph, where y depends on x.

The white "Spirit" black bear (or Kermode) Ursus americanus kermodei, differs from the ordinary black bear by a single amino acid change in the melanocortin 1 receptor gene (MC1R). In this population, the gene has two forms (or alleles): the "white" allele b and the "black" allele B. The trait is recessive: white bears have two copies of the white allele of this gene (bb), whereas a bear is black if it has one or two copies of the black allele (Bb or BB). Both color morphs and all three genotypes are found together in the bear population of the northwest coast of British Columbia. If possessing the white allele has no effect on growth, survival, reproductive success, or mating patterns of individual bears, then the frequency of individuals with 0, 1, or 2 copies of the white allele (b) in the population will follow a binomial distribution. To investigate, Hedrick and Ritland (2011) sampled and genotype 87 bears from the northwest coast:42 were BB 24 were Bb 21 were bb Assume that this is a random sample. A formal hypothesis test was carried out to compare the observed and expected frequencies of genotypes. The procedure obtained P = 0.0001. 1. "The frequency distribution of genotypes has a binomial distribution in the population" is the________ hypothesis, whereas "The frequency distribution of genotypes does not have a binomial distribution" is the _________ hypothesis. 2. The degrees of freedom for the test statistic are __________. Say whether the each of the following statements is true or false solely on the basis of these results: 3. The difference between the observed and expected frequencies is statistically significant.________4. The test statistic exceeds the critical value corresponding to α = 0.05. ___________5. The test statistic exceeds the critical value corresponding to α = 0.01. ____________

Four runners are training for long races. Noah ran 5.123 miles, Andre ran 6.34 miles, Jada ran 7.1 miles, and Diego ran 8 miles.What is the total running distance of the four runners?

P divided by 8.2 = 9.3who is smart

Write an equation for the graph, where y depends on x.

The white "Spirit" black bear (or Kermode) Ursus americanus kermodei, differs from the ordinary black bear by a single amino acid change in the melanocortin 1 receptor gene (MC1R). In this population, the gene has two forms (or alleles): the "white" allele b and the "black" allele B. The trait is recessive: white bears have two copies of the white allele of this gene (bb), whereas a bear is black if it has one or two copies of the black allele (Bb or BB). Both color morphs and all three genotypes are found together in the bear population of the northwest coast of British Columbia. If possessing the white allele has no effect on growth, survival, reproductive success, or mating patterns of individual bears, then the frequency of individuals with 0, 1, or 2 copies of the white allele (b) in the population will follow a binomial distribution. To investigate, Hedrick and Ritland (2011) sampled and genotype 87 bears from the northwest coast:42 were BB 24 were Bb 21 were bb Assume that this is a random sample. A formal hypothesis test was carried out to compare the observed and expected frequencies of genotypes. The procedure obtained P = 0.0001. 1. "The frequency distribution of genotypes has a binomial distribution in the population" is the________ hypothesis, whereas "The frequency distribution of genotypes does not have a binomial distribution" is the _________ hypothesis. 2. The degrees of freedom for the test statistic are __________. Say whether the each of the following statements is true or false solely on the basis of these results: 3. The difference between the observed and expected frequencies is statistically significant.________4. The test statistic exceeds the critical value corresponding to α = 0.05. ___________5. The test statistic exceeds the critical value corresponding to α = 0.01. ____________

Four runners are training for long races. Noah ran 5.123 miles, Andre ran 6.34 miles, Jada ran 7.1 miles, and Diego ran 8 miles.What is the total running distance of the four runners?

P divided by 8.2 = 9.3who is smart

A peak is where the frequency is lowest.

A peak is where the frequency is the highest.

A cluster is a group of bars, meaning the frequency is higher in these intervals.

A peak is a bar that is higher than the other bars around it.

Intervals on a histogram where there are no bars mean the frequency is 0.

If the graph is symmetrical, the data is clustered toward the right side.

If the graph is symmetrical, the data is evenly distributed.

The **correct statement **about **histogram** is as follows;

A **peak **is where the **frequency **is the **highest**.

A **cluster **is a group of **bars**, meaning the **frequency **is **higher **in these **intervals**.

A **peak **is a **bar **that is **higher than **the other **bars **around it.

**Intervals **on a **histogram **where there are no bars mean the **frequency **is **0.**

If the **graph **is **symmetrical**, the data is **evenly distributed**.

We have to **determine**, which **descriptions **of a **histogram **are **true**?

**According **to the **question**,

A **histogram **meaning can be stated as a **graphical representation **that **condenses **a **data series **into an easy **interpretation **of **numerical **data by **grouping **them into **logical ranges **of different **heights **which are also known as **bins.**

**Characteristics **of a **Histogram **are as follows;

A **histogram **is used to **display **continuous **data **in a **categorical** form.

In a **histogram**, there are **no gaps **between the **bars**, unlike a **bar graph**.

The **width **of the **bins **is **equal**.

A **histogram **is a **type **of **representation **of a **data **set where **bars **are used to **represent **the **frequencies**.

The **area **of these **bars **is said to be **proportional **to the **frequency **of the **variable**.

The **peak **of a **histogram **represents the **highest value **of **frequency**. Also, the **peak** is a **bar **that is **higher **than the **other bars **around it.

In a **histogram intervals **wherein **bars **cannot be seen would **represent **the **frequency **of that would **zero**.

Also, if the **histogram** is said to be **symmetrical**, then the **data **should be **distributed evenly**.

A **peak **is where the **frequency **is the **highest**.

A **cluster **is a group of **bars**, meaning the **frequency **is **higher **in these **intervals**.

For more details refer to the link given below.

**Answer:**

A peak is where the frequency is the highest.

A cluster is a group of bars, meaning the frequency is higher in these intervals.

A peak is a bar that is higher than the other bars around it.

Intervals on a histogram where there are no bars mean the frequency is 0.

If the graph is symmetrical, the data is evenly distributed.

**Step-by-step explanation:**

135 – 60 = h

B.

135 + h = 60

C.

60 + 135 = h

D.

60 – h = 135

I think that the answer is A

Since the local area businesses are supporting the fundraiser, the only cost to the students is the production cost. So, the

profit from the cards is found by subtracting the total production cost from the total revenue. Each card costs $0.20 to

produce and is sold for $20.

Select the correct answer from each drop-down menu.

If the class sold c cards, the inequality that represents their profit goal is

This year's class sold 520 cards, so they

their goal because they sold more than

cards.

Approximately **520 cards** actually sold this year in the **class**, more than 505, have fulfilled their **objective**.

According to the question,

If the students sell c cards the,

The** total revenue**,

- 20c

The **total production costs**,

- 0.2c

`

The** inequality** of **profit**, or **income**, which is less than** 10 thousand dollars **represents their objective, such as:

→

→

→

→

or,

→

The class had to sell more than **505 cards** just to meet their **goals**.

Thus the above answer is right.

**Learn more:**

**Answer:**

Sample Answer for Edmentum

6x - 5y = 15

X= y + 3

point form (1, -2)

equation form x=1, y=-2

equation form x=1, y=-2

the action of moving back and forth quickly and steadily

the distance between one compression and the compression next to it

the action of moving through a material or substance

**Answer:**

the action of moving back and forth quickly and steadily

**Explanation:**

hopes this helps :D

O A. 4,/25

B. 2V50

O C. 5,2

O D. 10

SUBMIT

__Answer____:__

__D.____1____0__

Hope you could get an idea from here.

Doubt clarification - use comment section.

10

2*10*5= 100

Square root of 100 is 10

2*10*5= 100

Square root of 100 is 10