# A particular frozen yogurt has 75 cal in 2 ounces how many calories are in 8 ounces of the yogurt

Total number of calories in 8 ounce yogurt is 300 calories.

Given that;

Total number of calories in 2 ounce yogurt = 75 calories

Find:

Total number of calories in 8 ounce yogurt

Computation:

Total number of calories in 8 ounce yogurt = 75[8/2]

Total number of calories in 8 ounce yogurt = 75[4]

Total number of calories in 8 ounce yogurt  = 300 calories

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Answer: Just divide 8 by 2 and you'll get 4
Each container is 2 ounces so do 75 times 4 and you'll get 300 calories

## Related Questions

Evaluate if c=3 and d=-4 2c/d

Substitute 3 into the expression for c and -4 for d. So, 2c/d = 2(3)/(-4) = 6/-4 = -3/2.  The answer is -3/2.

What is (4-5a)^2 - a (2a -3)

3a^2+13 should be correct

If f(1)=3 and f(n)=-2f(n-1)+1,then f(5)=

The value f(5) when f)1) = 3 is f(5) = 43.

### How to find the 5th term of the sequence?

The fifth term of the sequence can be found by finding the value of all the terms that precede it.

### We can find the value of f(5) as shown below:

The value of f(1) is given as:

f(1) = 3

With this, we can find the value of f(2) and with f(2), we can find the value of f(3), and so on.

f(n) = - 2f(n-1)+1

At n = 2:

f(2) = -2f(2-1)+1

= - 2f(1)+1

= - 2*3 + 1

= - 5

When n = 3:

f(3) = -2*-5 + 1

= 11

When n = 4:

f(4) = -2*11 + 1

= -21

When n = 5:

f(5) = -2*-21 + 1

= 43

Therefore, we have found the value of f(5) to be f(5) = 43.

#SPJ2

f(5) = - 2f(4) + 1
f(4) = -2f(3) + 1
f(3) = -2f(2) + 1
f(2) = -2f(1) + 1
Therefore:
f(2) = -2(3) + 1 = -5
f(3) = -2(-5) + 1 = 11
f(4) = -2(11) + 1 = -21
Therefore f(5) = -2(-21) + 1 = 43

Javier drove 45 miles, this represents 60% of his entire trip. What is the total number of miles in his trip

Ratio and proportion

45mi/60%=x miles/100%
cross multiply
60x=4500
x=75 miles

hope this helps
60% is the same thing as 6/10, or 3/5. So 45 miles is 3/5 of his trip. 45=3/5x, where x is the number of miles in his trip. Divide both sides by 3/5 and you should get 75 miles.

Perpendicular Vectors:Find v x w if v=5i -4j +4k & w=-6i +3j -2k.
A. 3i-4j-2k
B. -14i-9j-4k
C. 5i +3j -4k
D. -4i -14j -9k

Find v x w if v=-3i-4j-8k & w=2i+6j+4k.
A. 12i -2j +3k
B. 8i +12j +32k
C. 32i -4j -10k
D. 10 i -8j +3k

Find the cross product <-6, 7, 2> x <8, 5, -3>. Is the resulting vector perpendicular to the given vectors?
A. <-31,-2,-86>;yes
B. <-37,-2,0>; no
C. <0,-86,-37>; yes
D. <-37, 0, -80>;no

1.
v x w = 8 i - 24 j + 15 k + 10 j - 12 i - 24 k =
= - 4 i - 14 j - 9 k
2.
v x w = -16 i - 16 j - 18 k + 12 j + 48 i - 8 k =
= 32 i - 4 j - 10 k
3.
The cross product:
< - 6, 7, 2 > x < 8, 5, -3 > =
= - 21 i + 16 j - 30 k - 18 j - 10 i - 56 k =
= - 31 j - 2 j - 86 k = < - 31, - 2, - 86 >
Vectors are perpendicular if: cos ( u, v ) = 0
< - 6 , 7. 2 > * < -31, - 2, - 86 > = 186 - 14 - 172 = 0
< 8, 5 , - 3 > * < - 31, - 2, - 86 > = -248 - 10 + 258 = 0
Answer: A ) < - 31, - 2 , - 86 >,  yes.

Verify
tanx + cotx = 1/ sinxcosx