Explain how to write 2 dividid 5 as a fraction

Answers

Answer 1
Answer:

Answer:

2/5

Step-by-step explanation:

Two divided by 5 is simply written as 2/5.

Hope I helped!

Answer 2
Answer: 2/5 is how it’s written as a fraction, 2 is over 5, 2 goes inside and 5 outside when you write the division expression

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Graph and find the x-intercept, y-intercept, domain, range, and horizontal asymptote of the function y = 4x

Answers

The function y=4x is a line. As such, its domain and range is the whole real number set \mathbb{R}, and it has no horizontal nor vertical asymptotes.

Moreover, there's no constant term, so it's x and y intercept is the origin (0,0).

BRAINLEST Find the sum of the first 6 terms of the infinite series: 1 - 2 + 4 - 8+...

Answers

Answer:

-21

Step-by-step explanation:

1-2+4-8+16-32

=-21

Answer:

The sum of the first 6 terms of the infinite series will be - 21.

Step-by-step explanation:

In this case, the infinite geometric series 1 - 2 + 4 - 8 + ... is represented by the following summation,

\sum _{{k=0}}^{{n}}(-2)^(k)

Therefore if we continue this pattern, the first 6 terms will be 1 - 2 + 4 - 8 + 16 - 32. Adding these terms,

1 - 2 + 4 - 8 + 16 - 32

= - 1 + 4 - 8 + 16 - 32

= 3 - 8 + 16 - 32 = - 5 + 16 - 32

= 11 - 32 = Solution : - 21

Someone PLEASE HELP ME ?????

Answers

Answer:

69

Step-by-step explanation:

Since m is parallel to n, there are special rules that apply to these angles. One such rule is corresponding angles, which are angles in matching corners. In this case, both of the angles are in the bottom right, which makes them corresponding. Corresponding angles are always congruent, therefore x=69.

Answer:

69 degrees

Step-by-step explanation:

A coin is flipped until 3 heads in succession occur. list only those elements of the sample space that require 6 or less tosses. is this a discrete sample space? explain

Answers

we are given

A coin is flipped until 3 heads in succession occur

so, firstly, we will find sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

now, we are given that

list only those elements of the sample space that require 6 or less tosses

so, we can see that sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

There are infinite such possibilities

so, there are infinite number of elements in space

and we know that

discrete sample space will always have finite elements

but we have infinite number of sample space elements here

so, this is not discrete sample space...........Answer

The sample space of flipping a coin until getting 3 heads in a row, and listing the elements that require 6 or fewer tosses.

In this case, we are looking at the sample space of flipping a coin until we get 3 heads in a row. To list the elements of the sample space that require 6 or fewer tosses, we need to consider the possible outcomes:

  • 1 toss: H (head) or T (tail)
  • 2 tosses: HH, HT, or TT
  • 3 tosses: HHH, HHT, HTH, HTT, THH, THT, TTH, or TTT
  • 4 tosses: HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, or TTTT
  • 5 tosses: Same pattern as the 4 tosses with an additional H or T at the end
  • 6 tosses: Same pattern as the 5 tosses with an additional H or T at the end

Yes, this is a discrete sample space because each toss of the coin has a finite number of possible outcomes (H or T).

Learn more about Discrete sample space here:

brainly.com/question/32719013

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The value of 33 + 42 = .

Answers

Answer:

75

Step-by-step explanation:

Answer:

57

Step-by-step explanation:

 33

+42

 75

The height distribution of NBA players follows a normal distribution with a mean of 79 inches and standard deviation of 3.5 inches. What would be the sampling distribution of the mean height of a random sample of 16 NBA players?

Answers

Answer:

The probability will be "0.0111".

Step-by-step explanation:

The given values are:

Mean,

\mu = 79

Standard deviation,

\sigma = 3.5

Now,

\sigma\bar x = (\sigma)/(\sqrt n)

         =   (3.5)/(\sqrt 16)

         =0.875

P(\bar x > 81) = 1 - P(\bar x < 81)

So,

= 1 - P{((\bar x - \mu \bar x ))/( \sigma \bar x)  < ((81 - 79) )/(0.875) ]

= 1 - P(z < 2.2857)

= 0.0111