# The ratio of boys to girls in a certain school is 5:6. If there are 420 girls, how many boys are there?(put solution)​

I'm not completely sure but I think it's 350

Step-by-step explanation:

5/6 is .8333 then you multiply .8333 by 420 and you get 350

## Related Questions

There are 9 applicants for 3 jobs: software engineer, computer programmer, and systems manager. Which statement best describes this situation?A.
There are 9P3 = 504 ways the positions can be filled because the order in which the applicants are chosen doesn’t matter.
B.
There are 9C3 = 84 ways the positions can be filled because the order in which the applicants are chosen doesn’t matter.
C.
There are 9P3 = 504 ways the positions can be filled because the order in which the applicants are chosen matters.
D.
There are 9C3 = 84 ways the positions can be filled because the order in which the applicants are chosen matters.

The situation which is best described there is 9P3 = 504 ways the positions can be filled with order matters so option (C) will be correct.

### What are permutation and combination?

Combination and permutation are two alternative strategies in mathematics to break up a collection of components into groups. This subset's components can be listed in any order when concatenated. The components of the subgroup are listed in a permutation in a particular order.

npr = factorial n/ factorial (n -r)

Given that,

Number of applicants = 9

Number of jobs = 3

Since the jobs are certain to the applicant so the order will matter.

Numberof ways to choose 3 people among 9 jobs

9p3 = factorial 9/factorial (9 -3)

9p3 = 9 × 8 × 7 × factorial 6/factorial 6

9p3 = 504

So there will be a total of 504 ways to feel the position such that order will also matter.

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Step-by-step explanation:

; )

A large tank is filled to capacity with 600 gallons of pure water. Brine containing 5 pounds of salt per gallon is pumped into the tank at a rate of 6 gal/min. The well-mixed solution is pumped out at a rate of 12 gallons/min. Find the number A(t) of pounds of salt in the tank at time t. A(t)

Salt flows into the tank at a rate of

(5 lb/gal) * (6 gal/min) = 30 lb/min

The volume of solution in the tank after t min is

600 gal + (6 gal/min - 12 gal/min)*(t min) = 600 - 6t gal

which means salt flows out at a rate of

(A(t)/(600 - 6t) lb/gal) * (12 gal/min) = 2 A(t)/(100 - t) lb/min

Then the net rate of change of the salt content is modeled by the linear differential equation,

Solve for A:

Multiply both sides by the integrating factor, :

Integrate both sides:

The tank starts with no salt, so A(0) = 0 lb. This means

and the particular solution to the ODE is

Step-by-step explanation:

The secant of a circle is a line that cuts the cuts two points of the circumference with one end point external to the circle;

Fro the given diagram, the two lines that cuts the circumference of the circle at two points are AEB and ADMC

Hence the one that contains diameter with point M is line ADMC

The owner of a grocery store wants to mix two kinds of candy together to make 15 lb that he can sell for $5.00 per lb. He wants to use chocolate candies that he sells for$7.00 per lb and sugar candies that he sells for $2.00 per lb. How many pounds of each should the owner use?_ pounds of chocolate candies _ pounds of sugar candies =OWO= ### Answers Answer: 9 pounds of chocolate and 6 pounds of sugar candies Let's define the variables: C = pounds of chocolate candies used. S = pounds of sugar candies used. We know that he wants to make a total of 15lb, then: C + S = 15 We also want that the price per pound to be equal to 5$.

This means that the price of the 15 pounds will be the same as the price of the un-mixed candies.

C*$7.00 +$2.00*S = $5.00*15 Then we have a system of equations: C + S = 15 C*$7.00 + $2.00*S =$5.00*15

To solve this system, we need to start by isolating one of the variables, i will isolate C in the first equation:

C = 15 - S

now we can replace that in the other equation:

(15 - S)*$7.00 +$2.00*S = $5.00*15 Now we can solve this for S.$105 - $5.00*S =$75

$105 -$75 = $5.00*S$30 = $5.00*S$30/$5 = S = 6 Then there are 6 pounds of sugar candy, and we can use the equation: C + S = 15 C + 6 = 15 C = 15 - 6 = 9 There are 9 pounds of chocolate candy in the mix. Step-by-step explanation: ### Final answer: To find the pounds of chocolate and sugar candies the owner should use, set up and solve equations based on the given information. ### Explanation: Let's assume that the owner uses x pounds of chocolate candies and y pounds of sugar candies. According to the problem, the total weight of the candies should be 15 pounds. So, we can set up the equation: 1. x + y = 15 The owner wants to sell the candies for$5.00 per pound. We can set up another equation to represent the total value of the candies:

1. 7x + 2y = 5 * 15

Now we can solve these equations to find the values of x and y.
By solving the equations, we find that x = 9 and y = 6.

Therefore, the owner should use 9 pounds of chocolate candies and 6 pounds of sugar candies.

How to solve this?
4cos(4x)sin(10x)

2/5 or 0.4

Step-by-step explanation:

Find the surface area of this rectangular prism. Be sure to include the correct unit in your answer.

Step-by-step explanation: To find the surface area you add the area of all the sides. And the unit for a surface area is unit (yards) squared.

Front: 5 • 9 = 45

Back: 5 • 9 = 45

Left: 6 • 5 = 30

Right: 6 • 5 = 30

Top: 9 • 6 = 54

Bottom: 9 • 6 = 54

45 + 45 + 30 + 30 + 54 + 54 = 258.