Answer:

**Answer:**

yes

**Explanation:**

it is in the body system

Answer:

**Answer:**

it would show clearly because it is a metal piece in the body.

20 examples of scalar quantity

If the speed of light in a medium is 2 x 10^8 m/s, the medium's index of refraction is?

Sharece knows that wave peaks and valleys can add and subtract. What would be the net effect if she was able to cross Wave 1 (a large-amplitude wave in a valley phase) with Wave 2 (a wave with slightly smaller amplitude than Wave 2, in a peak phase)?Sharece knows that wave peaks and valleys can add and subtract. What would be the net effect if she was able to cross Wave 1 (a large-amplitude wave in a valley phase) with Wave 2 (a wave with slightly smaller amplitude than Wave 2, in a peak phase)?

If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

The interatomic spring stiffness for tungsten is determined from Young's modulus measurements to be 90 N/m. The mass of one mole of tungsten is 0.185 kg. If we model a block of tungsten as a collection of atomic "oscillators" (masses on springs), what is one quantum of energy for one of these atomic oscillators? Note that since each oscillator is attached to two "springs", and each "spring" is half the length of the interatomic bond, the effective interatomic spring stiffness for one of these oscillators is 4 times the calculated value given above. Use these precise values for the constants: ℏ = 1.0546 10-34 J · s (Planck's constant divided by 2π) Avogadro's number = 6.0221 1023 molecules/mole kB = 1.3807 10-23 J/K (the Boltzmann constant)

If the speed of light in a medium is 2 x 10^8 m/s, the medium's index of refraction is?

Sharece knows that wave peaks and valleys can add and subtract. What would be the net effect if she was able to cross Wave 1 (a large-amplitude wave in a valley phase) with Wave 2 (a wave with slightly smaller amplitude than Wave 2, in a peak phase)?Sharece knows that wave peaks and valleys can add and subtract. What would be the net effect if she was able to cross Wave 1 (a large-amplitude wave in a valley phase) with Wave 2 (a wave with slightly smaller amplitude than Wave 2, in a peak phase)?

If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

The interatomic spring stiffness for tungsten is determined from Young's modulus measurements to be 90 N/m. The mass of one mole of tungsten is 0.185 kg. If we model a block of tungsten as a collection of atomic "oscillators" (masses on springs), what is one quantum of energy for one of these atomic oscillators? Note that since each oscillator is attached to two "springs", and each "spring" is half the length of the interatomic bond, the effective interatomic spring stiffness for one of these oscillators is 4 times the calculated value given above. Use these precise values for the constants: ℏ = 1.0546 10-34 J · s (Planck's constant divided by 2π) Avogadro's number = 6.0221 1023 molecules/mole kB = 1.3807 10-23 J/K (the Boltzmann constant)

B.meter

C.Rate

D.Speed

E.velocity

F.slope

G.refrence point

PLS HELP NOW !!!

Speed can be calculated if you know the **distance **that an object travels in one unit of **time**, therefore the correct answer is option D.

The total distance covered by any **object **per unit of time is known as speed. It depends only on the magnitude of the moving object.

The **unit **of speed is a meter/second. The generally **considered **unit for speed is a meter per **second**.

Thus, Speed can be **calculated **if you know the distance that an object **travels **in one unit of time, therefore the correct answer is option D.

Learn more about **speed **from here, refer to the link;

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Answer:

D.Speed

Explanation:

The speed of an object is the distance the object travels in one unit of time.

Answer:

-384.22N

Explanation:

From Coulomb's law;

F= Kq1q2/r^2

Where;

K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2

q1 and q2 = magnitudes of the both charges

r= distance of separation

F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2

F= -495.65 × 10^-3/ 1.29 × 10^-3

F= -384.22N

Since the ball is moving by uniformly accelerated motion, its vertical velocity at time t is given by

where we took upward as positive direction, and where is the initial velocity, a the acceleration and t the time.

The instant at which is the instant when the ball reverses its velocity (from upward to downward). This means that the difference between the time t at which v(t)=0 and the instant t=0 is the total time during which the ball was going upward:

By plugging numbers into the equation, we find

where we took upward as positive direction, and where is the initial velocity, a the acceleration and t the time.

The instant at which is the instant when the ball reverses its velocity (from upward to downward). This means that the difference between the time t at which v(t)=0 and the instant t=0 is the total time during which the ball was going upward:

By plugging numbers into the equation, we find

Express your answer in micrometers(not in nanometers).

**Answer:**

1.196 μm

**Explanation:**

D = Screen distance = 3 m

= Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

For first dark fringe

**Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm**

The **wavelength **of light that will produce the first-order dark fringe at the same point on the screen is the same as the original wavelength of the light, which is 598 nm (0.598 μm).

To find the wavelength of light that will produce the first-order dark fringe at the same point on the screen, we can use the equation dsinθ = nλ, where d is the separation between the slits, θ is the angle of the **fringe**, n is the order of the fringe, and λ is the wavelength of the **light**.

In this case, the first-order bright fringe is located at a distance of 4.84 mm from the center of the central bright fringe. Since this is a first-order fringe, n = 1.

Plugging in the values, we have (0.120 mm)(sinθ) = (1)(λ). Rearranging the equation gives sinθ = λ/0.120 mm.

Since the first-order dark fringe is located at the same point as the first-order bright fringe, the angle of the first-order dark fringe can be calculated by taking the sine inverse of λ/0.120 mm.

Finally, to find the wavelength of light that will produce the first-order dark fringe at this point, we can rearrange the equation to solve for λ: λ = (0.120 mm)(sinθ).

Now, substitute the known values into the equation to calculate the wavelength of light:

λ = (0.120 mm)(sinθ) = (0.120 mm)(sin sin^-1(λ/0.120 mm)) = λ.

The wavelength of light that will produce the first-order dark fringe at this point on the screen is the same as the original wavelength of light, which is 598 nm. Converting this value to micrometers, we get 0.598 μm.

#SPJ3

Select the correct answer

You travel in a circle, whose circumference is 8 kilometers, at an average speed of 8 kilometers/hour. If you stop at the same point you started

from, what is your average velocity?

A

0 kilometers/hour

B.

2 kilometers/hour

4 kilometers/hour

D

8 kilometers/hour

E.

16 kilometers/hour

Rese

Velocity depends on the straight-line distance between your start-point and your end-point, regardless of what route you follow to get there.

If you stop at the same point where you started, then that distance is zero, no matter how far you drove before you returned to your start-point.

So the average velocity around any "CLOSED" path is **zero. (A)**

**Answer:**

423m/s

**Explanation:**

Suppose after the impact, the bullet-block system swings upward a vertical distance of 0.4 m. That's means their kinetic energy is converted to potential energy:

where m is the total mass and h is the vertical distance traveled, v is the velocity right after the impact at, which we can solve by divide both sides my m

Let g = 9.81 m/s2

According the law of momentum conservation, momentum before and after the impact must be the same

where are the mass and velocity of the bullet before the impact, respectively. are the mass and velocity of the block before the impact, respectively, which is 0 because the block was stationary before the impact