Answer:
114,688

the sequence was multiplying by 4 each time so all u needed to do was multiply each answer by four starting from 7x4

7×4 = 28

28×4 = 112

112×4 = 448

448×4 = 1 792

1792×4 = 7168

7168×4 = 28,672

28,672×4 =114,688

the sequence was multiplying by 4 each time so all u needed to do was multiply each answer by four starting from 7x4

7×4 = 28

28×4 = 112

112×4 = 448

448×4 = 1 792

1792×4 = 7168

7168×4 = 28,672

28,672×4 =114,688

Find the sum: 3 4/5+2 1/4 i need helpnplzzz

One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours.Required:a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal. b. The sample size was not given in the paper, but the sample size was described as large. Suppose that the sample size was 500. Explain why it is reasonable to use a one-sample t confidence interval to estimate the population mean even though the population distribution is not approximately normal. c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children.

Evaluate the expression.11 +4+2 = ?

HELP WILL MARK BRAINLIEST

a softball league has 13 teams, if every team must play every other team in the first round of league play, how many games must be scheduled

One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours.Required:a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal. b. The sample size was not given in the paper, but the sample size was described as large. Suppose that the sample size was 500. Explain why it is reasonable to use a one-sample t confidence interval to estimate the population mean even though the population distribution is not approximately normal. c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children.

Evaluate the expression.11 +4+2 = ?

HELP WILL MARK BRAINLIEST

a softball league has 13 teams, if every team must play every other team in the first round of league play, how many games must be scheduled

**Answer:**

**Explanation:**

Given the below function;

We'll follow the below steps to determine the inverse of the above function;

**Step 1: Replace h(x) with y;**

**Step 2: Switch x and y;**

**Step 3: Solve for y by first adding 2 to both sides;**

**Step 4: Take the cube of both sides;**

**Step 5: Expand the cube power;**

Recall;

Applying the above, we'll have;

**Step 6: Subtract 1 from both sides of the equation;**

**Step 7: Replace y with h^-1(x);**

The bis which is likely for the given question by the **researcher **is **response bias**.

Given that,

A researcher calls 1,800 randomly chosen residential telephone numbers, and then asks to speak with an adult member of the household.

The **researcher **asks, “How many 3D movies have you watched in a movie theater in the past 12 months?”.

**Response bias** happens when the people who needs to respond does this in an inaccurate way or wrongly.

Here almost no people will be correctly remembering the exact number of movies they watched in a year.

Also, they may be volatile to social desirability and may say less or more number of movies.

So there happens a response bias.

Hence the correct bias is response bias.

Learn more about **Response Bias** here :

#SPJ1

**Answer:**

-14

**Step-by-step explanation:**

Vegan 85.00 5.20 1.08

Omnivore 91.00 5.65 1.10

Calculate a 99% CI for the difference between the population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (Use μvegan−μomnivore). Round to three decimal places.)

Interpret the interval.

a. We are 99% confident that the true average cholesterol level for vegans is less than that of omnivores by an amount within the confidence interval.

b. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount within the confidence interval.

c. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount outside the confidence interval.

d. We cannot draw a conclusion from the given information.

Answer: hey

Step-by-step explanation:

about 83%

Put the given value in the formula and do the arithmetic.

... P(66) = 90/(1 +271·e^(-0.122·66))

... = 90/(1 +271·e^-8.052)

... = 90/(1 +271·0.00031846)

... = 90/(1 +0.0863)

... = 90/1.0863

... = **82.8 . . . . percentage with some coronary heart disease**

**Answer:**

**$183.7125**

**Step-by-step explanation:**

Given,

**Original investment**, A = **$ 5,175.00**

In** first year**,

Thetotal investment = $ 5,175.00

**The amount is increased by 9 %**,

Thus, the final amount at the end of first year,

In **Second year**,

The total investment = $ 5640.75,

**The amount is decreased by 5 %**,

Thus, the final amount at the end of second year,

Hence,

5,175 + 9% = 5640.75

5640.75 - 5% = 5302.305

Original investment = 5,175

Gain = 5,302.305

Subtract them both and get = 127.305

5640.75 - 5% = 5302.305

Original investment = 5,175

Gain = 5,302.305

Subtract them both and get = 127.305