Plz help me simply this
Plz help me simply this - 1

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Answer 1
Answer:

Answer:

Step-by-step explanation:

\sqrt[5]{u^(10)*p^(15)}*\sqrt[4]{u^(16)*p^(18)}=  \sqrt[5]{u^(2*5)*p^(3*5)}*\sqrt[4]{u^(4*4)*p^(16*2)}\n\n\n=\sqrt[5]{(u^(2))^(5)*(p^(3))^(5)}*\sqrt[4]{(u^(4))^(4)*p^(4*4)*p^(2)}\n\n=\sqrt[5]{(u^(2))^(5)*(p^(3))^(5)}*\sqrt[4]{(u^(4))^(4)*(p^{4)^(4)}*p^(2)}\n\n=u^(2)*p^(3) * u^(4)*p^(4)*\sqrt[4]{p^(2)}\n\n=u^(2+4)*p^(3+4)*\sqrt[4]{p^(2)}\n\n= u^(6)p^(7)\sqrt[4]{p^(2)}


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A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening with fll ttendance, there were combined. The receipts totaled $3450. How many children attended the show?

Answers

Answer:

Between 150 and 450

Step-by-step explanation:

We are going to find the number by resolving  a system of linear equations.

First we write the system equations :

C+S+A=750

Where C : children, S : students and A : adults

The equation represents the ''full attendance''

The second equation :

3C+5S+7A=3450

This equation represents the totaled receipts.

The system :

C+S+A=750\n3C+5S+7A=3450

has the following associated matrix :

\left[\begin{array}{cccc}1&1&1&750\n3&5&7&3450\end{array}\right]

By performing elementary matrix operations we find that the matrix is equivalent to

\left[\begin{array}{cccc}1&0&-1&150\n0&1&2&600\n\end{array}\right]

The new system :

C-A=150\nS+2A=600

Working with the equations :

C = 150 + A\nS = 600-2A

Our solution vector is :

\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]

For example :

If 0 adults attended ⇒ A = 0

C = 150 + 0 \nC = 150\nS = 600 - 2A\nS = 600

This verify the totaled receipts equation :

150($3)+600($5) = $ 3450

A ≥ 0 ⇒ If A = 0 ⇒ C = 150

C = 150 is the minimum children attendance

From the equation :

S = 600 -2A

S ≥0

600 - 2A ≥ 0

600 ≥ 2A

300≥ A

A is restricted to the interval [ 0, 300]

When A = 0 ⇒ C = 150

When A = 300 ⇒C = 150 + A = 150 + 300 = 450

Children ∈ [ 150,450]

With C being an integer number (including 0)

Also S and A are integer numbers (including 0)

Simplify 8X +7 - 2X -4

Answers

Answer:

6x + 3

Step-by-step explanation:

8x - 2x + 7 -4

Lookattheattachedpicture

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The quadratic function f(x) has a vertex at (9, 8) and opens upward. If g(x) = 4(x − 8)2 + 9, which statement is true?A.
The maximum value of f(x) is greater than the maximum value of g(x).
B.
The maximum value of g(x) is greater than the maximum value of f(x).
C.
The minimum value of f(x) is greater than the minimum value of g(x).
D.
The minimum value of g(x) is greater than the minimum value of f(x).

Answers

ANSWER

D.
The minimum value of g(x) is greater than the minimum value of f(x).

EXPLANATION

It was given that;

f(x)
has a vertex at

(9,8)

and opens upwards.

This means that f(x) is a minimum graph and hence have a minimum value of 8.

Also ,

g(x) = 4 {(x - 8)}^(2) + 9

When we compare this function to

y = a {(x - h)}^(2) + k

We can see that,a=4, h=8 and y=9.

The vertex is

(8,9)

Since a>0, the graph opens upwards.

The graph has a minimum point which is (8,9) and hence the minimum value is 9.

We can see that, the minimum value of g(x) is greater than the minimum value of f(x).

Therefore the correct answer is D.

Find an equation of the sphere with center (-3, 2 , 5) and radius 4. What is the intersection of this sphere with the yz-plane.

Answers

Answer:

The equation of the sphere with center (-3, 2 , 5) and radius 4 is (x+3)^(2) +(y-2)^(2) + (z-5)^(2) = 16

The intersection of the sphere with the yz- plane gave the equation (y-2)^(2) + (z-5)^(2) = 7 which is a 2D- circle with center (0,2,5) and radius √(7).

Step-by-step explanation:

The equation of a sphere of radius r, with center (a,b,c) is given by

(x-a)^(2) +(y-b)^(2) + (z-c)^(2) = r^(2)

where, x,y, and z are the coordinates of the points on the surface of the sphere.

Hence, the equation of the sphere with center,  (-3, 2 , 5) and radius 4 becomes

(x-a)^(2) +(y-b)^(2) + (z-c)^(2) = r^(2)

(x-(-3))^(2) +(y-(2))^(2) + (z-(5))^(2) = 4^(2)

Then,

(x+3)^(2) +(y-2)^(2) + (z-5)^(2) = 16

This is the equation of the sphere with center (-3, 2 , 5) and radius 4,

Now, for the intersection of this sphere with the yz- plane,

The yz -plane is where x = 0, then we set x = 0

Them the equation (x+3)^(2) +(y-2)^(2) + (z-5)^(2) = 16 becomes

(0+3)^(2) +(y-2)^(2) + (z-5)^(2) = 16

(3)^(2) +(y-2)^(2) + (z-5)^(2) = 16\n9 +(y-2)^(2) + (z-5)^(2) = 16\n(y-2)^(2) + (z-5)^(2) = 16 - 9\n(y-2)^(2) + (z-5)^(2) = 7

This equation is the equation of a 2D- circle with center (0,2,5) and radius √(7)

This is the part of the sphere that intersects with the yz-plane.

Please help me out with the below question

Answers

Answer:

A

Step-by-step explanation:

this is only what I know correct me if I'm wrong thank you

(c) Simplify fully
exexexf
————
exex fxf

Answers

Answer:

i know its a bit late but the answer below

Step-by-step explanation:

e/f

Could u be more specific