Layla is cutting bows out of ribbon which will be used to wrap gifts. If Layla needs 21/22of a foot of ribbon to make a bow, and she has 21 feet of ribbon, then how many bows can Layla make?
Since 21/22 is just 1 short of a whole 1, we can first round it up to a whole 1, and subtract it later. 21 divided by 1 is just 21, and now is the time to subtract the part in which we rounded out. 1/22 times 21 is 21/22, so Layla can't make an entire bow with it.
The Venn diagram shows the relationship betweenseveral sets of numbers. Where should 0.3% be placed in the Venn diagram? Real numbers Natural numbers, because 0.3% is a positive number B Integers, because 0.3% is a decimal Integers Rational numbers Natural numbers Rational numbers, because 0.3% can be written as a fraction Real numbers, because 0.3% is an irrational number
Rational numbers, because 0.3% can be
written as a fraction
Explain why you cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds?
We cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds
We cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds because we do not know the number of possible outcomes, the events , sample space or the sample size. Probability is calculated with frequency or occurrences or how much certainty there is.It is a number between 0 and 1. 1 indicates certainty and 0 indicates impossibility. Without a range or frequency how can we depict the possibility or impossibility of an occurrence of 200 pounds.
You cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds without sufficient data on the weight distribution of the population. Weight can widely vary due to individual factors, making it hard to have a definitive measurement. Accurate data and appropriate statistical methods are necessary.
The process of calculating the probability that a randomly selected passenger weighs more than 200 pounds would be seemingly simple deductive reasoning. However, it's impossible without access to sufficient data that provides information about the population's weight distribution. Since people's weights are variable and oftentimes private information, it would not be straightforward to obtain accurate and representative data.
For instance, while we can calculate the probability of drawing a certain card from a deck because we know the total number of cards and the number of each type of card, determining the likelihood of a randomly chosen passenger weighs over 200 pounds requires knowledge of the weight distribution of all potential passengers.
Moreover, weight can vary significantly among individuals due to factors like age, gender, health status, and so on. This makes it a continuous variable, meaning it's also affected by dimensions like decimal form and scientific notation when measuring. We'd need accurate data and appropriate statistical methodologies to consider all possible weight ranges and their frequencies for a reliable calculation of such probability.