# Use the distributive property to simplify this expression -2x(3x + x-5)

8x+10x
18x.

−8x^2  +  10x

Step-by-step explanation:

## Related Questions

The location of Sonia's school and home are plotted on the coordinateplane shown. What are the coordinates (x, y) of her school?

The coordinates of the school is (8,2)

The radius of a circle is 2.6 in. Find the circumference
to the nearest tenth.

16.

Step-by-step explanation:

since given the radius and the formula of the circumference of a circle is 2pie*r

There are two different music download companies that offer a monthly plan for downloading songs. S-Jams charges \$1.29 per song plus \$10 monthly fee. C-tunes charges \$0.99 per song plus \$16 monthly fee. When will the company’s plans cost the same? Write an expression for the cost of S-Jams.

Thus, when both S-jams and C-tunes have 20 songs downloaded in a month  , the cost will be same.

an expression for the cost of S-Jams \$0.99n + \$16

Step-by-step explanation:

For

S-Jams

cost of 1 song = \$1.29

then

cost of n songs = n*cost of 1 song  = \$1.29n

monthly fee = \$10

Total cost of S-Jams = \$1.29n+\$10

________________________________________

For

C-Tunes

cost of 1 song = \$0.99

then

cost of n songs = n*cost of 1 song  = \$0.99n

monthly fee = \$16

Total cost for C-Tunes= \$0.99n + \$16

we have to find When will the company’s plans cost the same.

Total cost of S-Jams = Total cost of C- Tunes

1.29n+10 = 0.99n + 16

=> 1.29n - 0.99n = 16-10

=> 0.30n = 6

=> n = 6/0.3 = 20

Thus, when both S-jams and C-tunes have 20 songs downloaded in a month  , the cost will be same.

an expression for the cost of S-Jams \$0.99n + \$16

30 points!!!!!A lawn sprinkler spins in a circle. The sprinkler covers a radius of 4 feet. Which choice is the closest to the area of lawn that the sprinkler can cover?

Aarea of a circle equals pie r squared so 4 x 4= 16 and 16 x pie =50.27

At a farm, there are two huge pits for storing hay. 90 tons of hay is stored in the first pit, 75 tons in the second pit. Then, three times as much hay was removed from the first pit as was removed from the second pit. After that, there was half as much hay in the first pit as there was now in the second pit. How many tons of hay was taken from the first pit?

63 tons

Step-by-step explanation:

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

63 tons of hay were taken from the first pit.

_____

Check

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.