Answer:
-6x-2x+10x

8x+10x

18x.

8x+10x

18x.

Answer:

**Answer:**

−8x^2 + 10x

**Step-by-step explanation:**

5.Eight feet of plastic tubing costs $4.08. If you only have $8.16 to spend, how much plastic tubingcan you afford?Cho

Circle R has a radius of line segment of QR and QP is a tangent to circle R at point Q.(Picture attached) (a) What is the measure of RQP? Explain your answer. (b) What is the value of x? Explain your answer with work. (c) What is the measure of QRP? Explain your answer with work. (d) What is the measure of RPQ? Explain your answer with work.

An investment project involves an immediate outlay of $8 million. The net cash flows received at the end of years 1, 2, and 3 will be $3 million, $4 million, and $2 million. A 10% discount rate is applicable so that the present value factors for years 1, 2, and 3 are 0.9091, 0.8264, and 0.7513. The NPV of the investment will be: (a) (b) (c) (d) $1 million $9 million $0.46 million $7.54 million

-8.46 greater or less than 5.31

Write an equivalent expression by distributing the "-−" sign outside the parentheses:-(9v+6.3w-3.3)

Circle R has a radius of line segment of QR and QP is a tangent to circle R at point Q.(Picture attached) (a) What is the measure of RQP? Explain your answer. (b) What is the value of x? Explain your answer with work. (c) What is the measure of QRP? Explain your answer with work. (d) What is the measure of RPQ? Explain your answer with work.

An investment project involves an immediate outlay of $8 million. The net cash flows received at the end of years 1, 2, and 3 will be $3 million, $4 million, and $2 million. A 10% discount rate is applicable so that the present value factors for years 1, 2, and 3 are 0.9091, 0.8264, and 0.7513. The NPV of the investment will be: (a) (b) (c) (d) $1 million $9 million $0.46 million $7.54 million

-8.46 greater or less than 5.31

Write an equivalent expression by distributing the "-−" sign outside the parentheses:-(9v+6.3w-3.3)

The coordinates of the school is (8,2)

to the nearest tenth.

**Answer:**

16.

**Step-by-step explanation:**

since given the radius and the formula of the circumference of a circle is 2pie*r

**Answer:**

**Thus, when both S-jams and C-tunes have 20 songs downloaded in a month , the cost will be same.**

** an expression for the cost of S-Jams $0.99n + $16**

**Step-by-step explanation:**

For

S-Jams

cost of 1 song = $1.29

let there be n songs downloaded in a month

then

cost of n songs = n*cost of 1 song = $1.29n

monthly fee = $10

Total cost of S-Jams = $1.29n+$10

________________________________________

For

C-Tunes

cost of 1 song = $0.99

let there be n songs downloaded in a month

then

cost of n songs = n*cost of 1 song = $0.99n

monthly fee = $16

Total cost for C-Tunes= $0.99n + $16

we have to find When will the company’s plans cost the same.

Total cost of S-Jams = Total cost of C- Tunes

1.29n+10 = 0.99n + 16

=> 1.29n - 0.99n = 16-10

=> 0.30n = 6

=> n = 6/0.3 = 20

**Thus, when both S-jams and C-tunes have 20 songs downloaded in a month , the cost will be same.**

** an expression for the cost of S-Jams $0.99n + $16**

The area is about 50.27

Aarea of a circle equals pie r squared so 4 x 4= 16 and 16 x pie =50.27

Aarea of a circle equals pie r squared so 4 x 4= 16 and 16 x pie =50.27

**Answer:**

63 tons

**Step-by-step explanation:**

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

**63 tons of hay were taken from the first pit.**

_____

*Check*

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.

Answer:

n = 31

Explanation:

Solve the equation by rewriting in exponential form using the definition of logarithm and simplifying. In other words, solve for n.

n = 31

Explanation:

Solve the equation by rewriting in exponential form using the definition of logarithm and simplifying. In other words, solve for n.