Answer:
the quantity of motion of a moving body, measured as a product of its mass and velocity.

*brainliest

*brainliest

Answer:
A golfer, putting on a green requires three strokes to “hole the ball.” During the first putt, the ball roles 5.0m due east. For the second putt, the ball travels 2.1m at an angle of 20 degrees north of east. The third putt is 0.50m due north. What displacement (magnitude

5 letter word foramount of work done per second

The earth takes 1 year to revolve around the sun at 1 A.U. distance (an astronomical unit = 93,000,000 miles). If a planet were 4 A.U. from the sun, how many years would it take to make 1 orbit?

A bicycle moves with a speed of 6 km/h for 2 hour and the speed of 4 km/h for the next 3 hours .find the average speed and the distance traveled?

Can someone help me on no. 6

Explain why particles in a gas are free to move far away from each other.

The earth takes 1 year to revolve around the sun at 1 A.U. distance (an astronomical unit = 93,000,000 miles). If a planet were 4 A.U. from the sun, how many years would it take to make 1 orbit?

A bicycle moves with a speed of 6 km/h for 2 hour and the speed of 4 km/h for the next 3 hours .find the average speed and the distance traveled?

Can someone help me on no. 6

Explain why particles in a gas are free to move far away from each other.

And has a base acceleration of 2.93ft/s2

How long would it take to reach 12.42 miles

**Answer: 271.4 s**

**Explanation:**

We are told the **top speed (maximum speed)** the car has is:

taking into account

And the **car's base acceleration (average acceleration)** is:

Since:

**(1)**

Where:

is the car's final speed (top speed)

because it starts from rest

is the time it takes to reach the top speed

Finding this time:

**(2)**

**(3)**

**(4)**

**Now we have to find the distance the car traveled at this maximum speed with the following equation:**

**(5)**

**Isolating :**

**(6)**

**(7)**

**(8)**

**On the other hand, we know the total distance traveled by the car is:**

Hence the remaining distance is:

**(9)**

**(10)**

**So, we can calculate the time it took to this car to travel this remaining distance ** at its top speed **, with the following equation:**

**(11)**

**Isolating :**

**(12)**

**(13)**

**(14)**

**With this time and the value of calculated in (4) we can finally calculate the total time :**

** (15)**

** (16)**

Chemical Potential Energy is a form of Potential Energy related to the structral arrangment of Atoms or Molecules.

i think A light bulb that gives off heat.

To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.

To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the **gravitational **constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:

2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg

#SPJ12

To find the radius of a planet with a **gravitational field **twice that of Earth's and half the mass, the radius is calculated to be half of **Earth's** radius.

The magnitude of the **gravitational field** strength *g* on a planet is given by the equation *g = G(M/R^2)*, where *G* is the universal gravitation constant, *M* is the planet's mass, and R is the planet's radius. Given that the **gravitational field** on the surface of the particular planet is *2g* where *g* is Earth's **gravitational field**, and the planet's mass is half of **Earth's** mass, we can derive the planet's radius in terms of Earth's radius *Rg*. Setting up the proportion *(G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2*, and simplifying, we find that *R^2 = (1/4)Rg^2*. Taking the square root of both sides gives us the final relation *R = (1/2)Rg*.

#SPJ3

T or F

I’m not completely sure but I thought no that’s true. Sorry if I’m wrong.

No, one more group must get the same result as the other group. This will make it more reliable and reproducible.