Answer:

**Answer:**

22 in

**Step-by-step explanation:**

It travels 35/60 ths of the complete circumference of a circle with r =6 in

diameter = 12 circumference = pi * d

35/ 60 * pi * 12 = ~22 inches

(a^3 / 4)^2Simplify

What is the solution to 7.5d=2.5d

Which situation can be modeled by a function?A. Raquel can spend $15 on 1 shirt, $30 on 2 shirts,or $30 on 3 shirts. B. Bonnie can spend $10 on a shirt, $20 on 2 shirts, and $20 on 3 shirts. C. Maria can spend $15 on 1 shirt, $15 on 2 shirts, or $30 on 3 shirts. D. Natalie can spend $15 on 1 shirt, $30 on 2 shirts, or $45 on 3 shirts.

Write the translated function. f(x)= 11x + 10 ; shifts 3 units up.

4. Ray RU bisects LQRS. If mSRU =50° and m2QRU = (+10) . Find the value of x.Find m2QRS. (Lesson 1.2) (1 point)

What is the solution to 7.5d=2.5d

Which situation can be modeled by a function?A. Raquel can spend $15 on 1 shirt, $30 on 2 shirts,or $30 on 3 shirts. B. Bonnie can spend $10 on a shirt, $20 on 2 shirts, and $20 on 3 shirts. C. Maria can spend $15 on 1 shirt, $15 on 2 shirts, or $30 on 3 shirts. D. Natalie can spend $15 on 1 shirt, $30 on 2 shirts, or $45 on 3 shirts.

Write the translated function. f(x)= 11x + 10 ; shifts 3 units up.

4. Ray RU bisects LQRS. If mSRU =50° and m2QRU = (+10) . Find the value of x.Find m2QRS. (Lesson 1.2) (1 point)

**Step-by-step explanation:**

It is given that, an air conditioning system can circulate 320 cubic feet of air per minute. We need to find how many cubic yards of air can it circulate per minute?

1 yard = 3 foot

1 feet = (1/3) yard

320 feet = 106.66 yard

**So, it will circulate 11.85 cubic yard of air per minute.**

An air conditioning **system can circulate** 11.85 cubic yards of air per minute.

To convert cubic feet to cubic yards, we need to divide the given value by 27 since 1 cubic yard is equal to 27 cubic feet. So, 320 cubic feet is equal to 320/27 = 11.85 cubic yards. Therefore, the air conditioning system can circulate 11.85 cubic yards of air per minute.

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**Answer:**

5/6 can´t be simplified

**Step-by-step explanation:**

**Answer:**

5i/6

**Step-by-step explanation:**

Answer:

Dear user,

Answer to your query is provided below

2(al−1) is the expression equivalent for 2la+26−2−26

B) 12%

C) 0.5%

D) 1.12

**Answer****:**

Given below.

**Explanation****:**

A) 0.02 = =

B) 12% = = =

C) 0.5% = =

D) 1.12 =

if it depreciates by 18%, then as each year passes, its worth is reduced to 82% of its value

So, after 5 years, it is worth 43750

So, after 5 years, it is worth 43750

**Answer:**

More number of words that can be made:

Please refer to below proof.

**Step-by-step explanation:**

**Given **that:

The number of binary code words that can be made:

where n is the length of binary numbers.

Binary numbers means 2 possibilities either 0 or 1.

Here, suppose if we have 5 as the length of binary number.

And there are 2 possibilities for each digit.

So, total number of possibilities will be

If the length of binary number is 2.

The total words possible are .

These numbers are:

{00, 01, 10, 11}

If the length of binary number is 3. (increasing the 'n' by 1)

The total words possible are .

These words are:

{000, 001, 010, 100, 011, 101, 110, 111}

So, number of More binary words = 8 - 4 = 4 or or .

So, the answer is .

Let us try to **prove in generic terms**:

Increasing the n by 1:

Number of more words made by increasing n by 1:

Hence, proved that:

More number of words that can be made:

When the length of a binary code word increases from n to n+1, the number of additional binary code words is equal to the number of binary code words of length n, which is .

When the length is increased from n to n+1, the number of binary code words of length n+1 is equal to the number of binary code words of length n multiplied by 2. This is because for each binary code word of length n, we can append a 0 or a 1 to create two new binary code words of length n+1. Therefore, the number of additional binary code words is equal to the number of binary code words of length n, which is.

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