I need help with #3
i need help with #3 - 1


Answer 1
Answer: Unit rate = 3/8 : 1/6

We can also write this as:

3/8 / 1/6

Flip the 2nd fraction and multiply:

3/8 * 6/1

Multiply the numerators and denominators together:


Simplify by dividing the numerator and denominaotr by 2:

18 / 2 = 9
8 / 2 = 4

So we have:


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Can someone help me on # 4
And tell me if I set it up right??


yup you did it better than I would have

At 5 seconds, an object's velocity is 9 meters per second. At 8 seconds, the object's velocity is 25 meters per second. Assuming a constant acceleration, what is the acceleration in meters per second per second of the object? (If necessary, round to the nearest hundredth.)


Acceleration  =  (change in speed) / (time for the change) .

Change in speed = (25 m/s - 9 m/s) =  16 m/s

Time for the change = (8 sec  -  5 sec)  =  3 seconds

Acceleration  =  (change in speed) / (time for the change)

                       =                 (16 m/s)  /  (3 sec) 

                       =                          (5 and 1/3)  m/s²  .

(rounded to the nearest hundredth ...  5.33 m/s² . )

I need help with 1, 2 and, 3 and also the green state is north Dakota and under the word Dakota is Bismarck and there is a dot going to Minnesota which that dot says st Paul and then the dot in Minnesota goes to Wisconsin and the dot is Madison so north Dakota and Minnesota are 437 miles and Wisconsin is 260 miles (green)=north Dakota, (blue)=Minnesota, (pink)=Wisconsin


it is kinda hard to read the words by the way you took the picture 

The table shows the number of candies packed by Machine J. The equation shows the number of candies packed by Machine K. In both representations, x is a measure of the number of minutes and y is a measure of the number of candies packed. Machine J Candy Packing
(minutes) y
3 90
6 180
9 270
12 360

Machine K: y = 26x

How many more candies could machine J pack than machine K in 11 minutes?


To find out the answer, treat both machines as lines. The answer can be found when you have equations for each machine. The first step of that would be to make an equation for "line" J, so find the slope using two sets of its given coordinates, I'll use (3,90) and (6,180).

(y_2 - y_1)/(x_2 - x_1)   Substitute in the x and y values
(180 - 90)/(6 - 3)   Subtract
(90)/(3)   Divide

Now that you know 30 is the slope, you can plug that and one set of coordinates, I'll use (3,90) into point-slope form.

y - y_1 = m(x - x_1)   Substitute in your x and y coordinates and slope
  y - 90 = 30(x - 3)     Use the Distributive Property
  y - 90 = 30x - 90      Add 90 to both sides
         y = 30x   

Now you have the equations for both machines. You want to find out how many candies each machine packages in 11 minutes, and x represent minutes, so plug 11 into the x value for both equations.

Machine J

y = 30x         Substitute
y = 30 (11)   Multiply
y = 330
Machine J packs 330 candies in 11 minutes.

Machine K

y = 26x         Substitute
y = 26 (11)    Multiply
y = 286

Machine K packs 286 candies in 11 minutes.

Finally, to find out how many more candies Machine J packs than Machine K, subtract the two values.

330 - 286 = 44

Machine J can pack 44 more candies than Machine K in 11 minutes.

Solve each equation and show work -v+3v=14






hopefully can help you..

So far John has run 1/4 of the way to school and walked 3/8 of the way. what fraction of the distance to school does John have left.


(1)/(4) + (3)/(8) = (2)/(8) + (3)/(8) =(5)/(8) \n\nleft:\ \ \ 1-(5)/(8)=(3)/(8)\ \ \ of\ the\ distance\ to\ school
the whole road is 1

3/8 have left