# What does sound travel through to reach our ears?

Answer: By a series of vibrations produced by an object. When an object produces sound, the sound waves travel and reach the ears. :)
Answer: sound travels through different mediums to reach our ears, depending on your position.
Sound can travel through water in the form of vibrations, and it can travel through the atmosphere, that is, the air, to reach our ears. It travels faster in gas(air).

## Related Questions

1. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for trial 1 and 2.2. Determine the percent yield of MgO for your experiment for trial 1 and 2.

3. Determine the average percent yield of MgO for the two trials.​

Part 1

Theoretical yield of MgO for trial 1 = 0.84 g

Theoretical yield of MgO for trial 2 = 1.01 g

Part 2

Percent yield trial 1 = 28.6 %

Percent yield trial 2 = 49.9 %

Part 3

Average percent yield of MgO for two trial = 39.25 %

Explanation:

Part 1.

Data Given

Trial 1                     Trial 2

mass of empty crucible and lid:          26.679 g               26.685 g

mass of Mg metal, crucible and lid:    26.931 g               26.988 g

mass of MgO, crucible and lid:            27.090 g              27.179 g

Theoretical yield of MgO for trial 1 and 2 = ?

Solution:

As Mg is limiting reagent so amount of MgO depends on the amount of Mg.

So, now we will look for the reaction to calculate theoretical yield

MgO form by the following reaction:

Mg  +  O₂ --------->  2 MgO

1 mol                        2 mol

Convert moles to mass

Molar mass of Mg = 24 g/mol

Molar mass of MgO = 24 + 16 = 40 g/mol

So,

Mg        +         O₂      --------->     2 MgO

1 mol (24 g/mol)                                  2 mol(40 g/mol)

24 g                                                    80 g

So,

24 g of Mg gives 80 g of MgO

To Calculate theoretical yield of MgO for Trial 1

First we look for the mass of Mg in the Crucible

• mass of Mg for trial 1

Mass of Mg = mass of Mg metal, crucible and lid - mass of empty crucible and lid

Mass of Mg = 26.931 g - 26.679 g

Mass of Mg = 0.252 g

As we come to know that 24 g of Mg gives 80 g of MgO, then amount of Mg from trial 1 that is 0.252 g will produce how many grams of MgO

Apply unity formula

24 g of Mg ≅ 80 g of MgO

0.252 g of Mg ≅ X g of MgO

Do cross multiplication

X g of MgO = 0.252 g x 80 g / 24 g

X g of MgO = 0.84 g

So the theoretical yield of MgO is  0.84 g

--------------

To Calculate theoretical yield of MgO for Trial 2

First we look for the mass of Mg in the Crucible

• mass of Mg for trial 2

Mass of Mg = mass of Mg metal, crucible and lid - mass of empty crucible and lid

Mass of Mg = 26.988 g - 26.685 g

Mass of Mg = 0.303 g

As we come to know that 24 g of Mg gives 80 g of MgO, then amount of Mg from trial 2 that is 0.303 g will produce how many grams of MgO

Apply unity formula

24 g of Mg ≅ 80 g of MgO

0.303 g of Mg ≅ X g of MgO

Do cross multiplication

X g of MgO = 0.303 g x 80 g / 24 g

X g of MgO = 1.01 g

So the theoretical yield of MgO is  1.01 g

__________________________

Part 2

percent yield of MgO for trial 1 and 2 = ?

Solution:

For trial 1

To calculate percent yield we have to know about actual yield of MgO

• mass of MgO for trial 1

Mass of MgO = mass of MgO, crucible and lid - mass of empty crucible and lid

Mass of MgO =  27.090 g -  26.685 g

Mass of MgO =  0.24 g

And we also know that

Theoretical yield of MgO for trial 1 = 0.84 g

Formula used

Percent yield = actual yield / theoretical yield x 100

put values in above formula

Percent yield =  0.24 g / 0.84 g x 100

Percent yield = 28.6 %

--------------

For trial 2

To calculate percent yield we have to know about actual yield of MgO

• mass of MgO for trial 2

Mass of MgO = mass of MgO, crucible and lid - mass of empty crucible and lid

Mass of MgO =  27.179 g -  26.685 g

Mass of MgO =  0.494 g

And we also know that

Theoretical yield of MgO for trial 2 = 1.01 g

Formula used

Percent yield = actual yield / theoretical yield x 100

put values in above formula

Percent yield =   0.494 g/ 1.01 g x 100

Percent yield = 49.9 %

--------------

Part 3

average percent yield of MgO for the two trials =?

Solution:

As we know

Percent yield trial 2 = 28.6 %

Percent yield trial 2 = 49.9 %

Formula used

Average percent yield = percent yield trial 1 + percent yield trial 2 / 2

Put values in above formula

Average percent yield = 28.6 + 49.9  / 2

Average percent yield = 78.5 / 2

Average percent yield = 39.25 %

Average percent yield of MgO for two trial = 39.25 %

PLZZZZ HELP MEEEE!!!!!

For the first page:

1) Transverse wave
2) B 2 represents the wavelength
3) D 4 represents amplitude
4) C decreased frequency
5) C wave frequency

Second page:

6) C Longitudinal wave
10) Frequency and wavelength are related. If freqeuncy is higher, wavelength is lower, if frequency is lower, wavelength is higher.

4 wings one tail what am i

only possible answer i think there is its a dragonfly jas 4 wings 1 tail

of course it is a dragonfly with 4 wings and a tail.

How many moles of nitrogen we have at a temperature of 30 ºC, a pressure of 4.0 atm, and a volume of 4000.mL?

0.643 mol.

Explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 4.0 atm).

V is the volume of the gas in L (V = 4000 mL = 4.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 30ºC + 273 = 303 K).

∴ n = PV/RT = (4.0 atm)(4.0 L)/(0.0821 L.atm/mol.K)(303 K) = 0.643 mol.

I do not get it hard science it is so hard

well when the medicine reaches ur stomach all the nutrients from the pill break up making it go to different parts of ur body

A pill is usually absorbed into the blood through the stomach walls after it is swallowed – these can become active in a few minutes but usually take an hour or two to reach the highest concentration in the blood. IV drugs are injected directly into the blood work much faster – sometimes in seconds or minutes.

What can natural selection accomplish? prove Darwin's idea of "survival of the fittest" change relative number of inhabitants within a community favor a particular variety (color or size) of a species change one kind of organism into another in order to surviv

A classic example of natural selection is the origin of giraffes long necks. The ancestors of modern giraffes were similar to deer with necks of ordinary length. Here natural selection accomplish  Darwin's idea of "survival of the fittest". The correct option is A.

### What is natural selection?

The mechanism through which living creature populations adapt and change is defined as the natural selection. The genes which are responsible for the survival of an organism are passed on to the successive generations.

Natural selection states that the organisms which are able to survive and reproduce with the changing environmental conditions are selected by the nature whereas the ones which cannot survive are eliminated.

So the survival of fittest means that the organisms which are suited to the environment will survive. Survival of the fittest is an expression developed from Darwin's theory of evolution.

Thus the correct option is A.

To know more about natural selection, visit;

brainly.com/question/30126941

#SPJ3

Natural selection makes it so that an organism from a species has a better chance of surviving than an organism in the same species, but with different traits. Survival of the fittest proves that certain traits can help an organisms survive better than its peers. For example, say there was an allele that made bears have thicker fur than others. The year-round climate is extremely cold. The bears with thicker fur are more likely to survive due to the warmth their fur provides and will have more offspring. The bears with thinner fur will die more often and not produce healthy offspring due to the frigid temperature. Eventually, the allele for thin fur will die out because the bears with these alleles cannot survive in their habitat.