Which of the following graphs shows the relationship between two variables that obey the inverse square law?
The First One (On Odyssey Ware)
Well, if we've been paying attention in class, we already KNOW that the electrostatic force changes as the inverse square of the distance, and the top graph is conveniently labeled "Electrostatic Force".
But if we didn't already know that, we'd have to examine the graphs, and find the one where 'y' changes like 1/x² .
The top graph does that. After 1 unit of time, the force is 350. Double the time to 2 units, and the force should drop to 1/4 of 350 ... sure enough, it's a little less than 90. Double the time again, to 4 units, and it should drop to 1/4 of a little less than 90 ... by golly, it's down below 30.
The first graph is what an inverse square looks like. Now that you've worked out this graph, you'll know an inverse square relationship whenever you see it.
The movement of deep ocean currents is mainly caused by:?
The relationship between the density of ocean water and the formation of deep currents. Difference in the tempature and salinity and the resulting differences in density cause variations int he movement of deep currents. For example, the deepest current , The Antarctic Bottom Water, is denser than the North Atlantic Deep Water. Both currents spread across the ocean floor as they flow toward eachother. Because less dense water always flows on top of denser water, The north Atlantic Deep Water flows on top of the Atlantic Bottom Water when the currents meet.
No contexto o verbo tomar adquirir duplo sentido . quais sao os sentidos
In the context of the verb take acquire double meaning. what are the senses. Thats what your saying in spanish right?. that has nothing to do with physics, thats english! JS. Whats your question?
Which of he following is the best example of potential energy a:a bird making a nestB:a car stopped at the top of the hill C:a gymnast doing a cart wheel D:a swimwear doing the backstroke Please answer asapppppp I need help
I think it's B. A car stopped at the top the hill
A: bird making a nest
I may be wrong. Hope it helps.
5) Consider pushing a 50.0 kg box through a 5.00 m displacement on both a flat surface and up aramp inclined to the horizontal by 15.0°. In both cases, you apply a force of 100.N parallel to the surface (parallel to the floor or parallel to the ramp). Calculate the work done by: a) the gravitational force as the box is pushed across the flat ground b) the gravitational force as the box is pushed up the ramp c) the force you apply as the box is pushed across the flat ground d) the force you apply as the box is pushed up the ramp
a) The work done by the gravitational force on the flat surface is zero
b) The work done by the gravitational force on the ramp is -634 J
c) The work done by the applied force on the flat surface is 500 J
d) The work done by the applied force on up along the ramp is 500 J
The work done by a force is given by the equation
F is the magnitude of the force
d is the dispalcement of the object
is the angle between the direction of the force and of the displacement
In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.
We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is ; this means that , and therefore, the work done is zero:
In this case, the box is pushed along the ramp. We have:
is the magnitude of the force of gravity, where
m = 50.0 kg is the mass of the box
is the acceleration of gravity
d = 5.00 m is the displacement of the box along the ramp
The ramp is inclined to the horizontal by , therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is:
Therefore, the work done by gravity in this case is:
In this case, we want to calculate the work done by the force you apply as the box is pushed across the flat ground.
Here we have:
F = 100.0 N (force applied)
d = 5.00 m (displacement of the box)
(the force is applied parallel to the flat surface, therefore force and displacement have same direction)
Therefore, the work done by the force you apply on the flat ground is:
In this last case, we want to calculate the work done by the force you apply as the box is pushed up along the ramp.
This time we have:
F = 100.0 N (force applied is the same)
d = 5.00 m (displacement of the box is also the same)
(the force is applied parallel to the ramp, therefore force and displacement have again same direction)
Therefore, the work done by the force you apply while pushing the box along the ramp is:
A ball is dropped from the top of a tall building. As the ball falls, the upward force of air rsistance becomes equal to the downward pull of gravity. When these two forces become equal in magnitude the ball will: a) flatten due to the forces b) fall at a constant speed c) continue to speed up d) slow to a stop
fall at a constant speed
When the force of air resistance equals the downward force of gravity, the net force on a falling object becomes zero, meaning it will fall at a constant speed.
The subject of this question is Physics, specifically focusing on the aspects of forces, gravity, and air resistance involved when an object is in free fall. When the magnitude of the upward air resistance equals the downward pull of gravity, the net force on the ball becomes zero. According to Newton's second law of motion, when the net force on an object is zero, its acceleration is also zero, meaning it will not speed up or slow down. In this case, the ball will fall at a constant speed. Therefore, the correct answer is b) fall at a constant speed.