A car is travelling at 100 km/hr. How far can it travel in 3/4 of an hour?

Answers

Answer 1
Answer: In 1 hour the car travels for a distance = 100 km
In 3/4 hour the car travels for a distance = 100 * (3/4)
                                                                 = 75 km

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Which graph represents the function f (x) =[z-1]-3​

Answers

Answer:

(0,4),(1,5)

(0,0),(1,1)

Step-by-step explanation:

If a quantity increases by 25% and then decreases by 25%, will that result be the original quantity? Explain.

Answers

Yes it will because it is going up the exact same amount as it is going down

Is 100 MG less than 10g

Answers

no becuase 100 mg is greater than 10gs 100>10

there are 1000 grams in a gram  and 1000 times 10 is 10000 so yes 100 mg is less than a 10g

What times 5.25 equals 12

Answers

well that would not work 5.25x2=10.5  5.25x3=15.75
yes it would work:)

divide 12 by 5.25.
yes its hard and the answer is 2.285714286
all because its hard doesn't mean it would not work 
says my calculator:D

I wants to know please the questión 3

Answers

Now,  usually about 1 ruler is the length of a piece of paper.  But this all depends on the paper.  It'd be a safe bet to say 1.

The probability that james will win two races in the next two days is 1/8 for tomorrow and 1/10 for the day after tomorrow. What is P(win tomorrow, then win the day after tomorroww)?

Answers

Answer:

\text{P(win tomorrow, then win the day after tomorrow)}=(1)/(80)[\tex]</p><p><strong>Step-by-step explanation:</strong></p><p><strong>Given : </strong> The probability that James will win two races in the next two days is 1/8 for tomorrow and 1/10 for the day after tomorrow.</p><p><strong>To find :</strong>  What is P(win tomorrow, then win the day after tomorrow)?</p><p><strong>Solution :</strong></p><p>Probability of winning two races in the next two days is</p><p><strong>For tomorrow - </strong> [tex](1)/(8)

For day after tomorrow - (1)/(10)

According to question :

Probability of win tomorrow, then win the day after tomorrow is given by multiple of probability of tomorrow and day after tomorrow.

i.e,

\text{P(win tomorrow, then win the day after tomorrow)}=\text{P(tomorrow)}* \text{P(day after tomorrow)}

\text{P(win tomorrow, then win the day after tomorrow)}=(1)/(8)* (1)/(10)

\text{P(win tomorrow, then win the day after tomorrow)}=(1)/(80)

1/80 because 1/8 times 1/10 equals 1/89